1. Data Representation Covering… Binary addition / subtraction
2’s complement
Floating Point Binary
Normalisation of Floating Point Binary

2. Question 1
Question…
Convert the
8-bit binary numbers to its denary equivalent.
Answer… 140

3. Question 2 Question… Convert 67 denary to its 8 bit binary equivalent…
Answer…

4. Question 3 Convert the 8-bit two’s complement binary 10000010
to its denary equivalents.
Answer… -126

5. Question 4 Question… Convert -120
denary to its 2’s complement 8-bit binary equivalent
Answer…

6. Question 5 Question… Convert 175 denary to its hexadecimal equivalent
Answer… af

7. Question 6 Question… Convert BB hexadecimal to its denary equivalent
Answer… 187

8. Question 7
Question…
Convert 9B hexadecimal to its 8-bit binary equivalent
Answer…

9. Question 8 Question… Convert the 8 –bit binary 10101010
to its hexadecimal equivalent
Answer… aa

10. Question 9 Question… Represent 5.125 as a binary fraction
Answer…

11. Question 10 Question… 1101000.011 What is the decimal equivalent?
Answer…

12. Question 11
Question…
What is
Answer…

13. Question 12 (2 marks) Question…
What is 76 – 24 in 2’s complement 8-bit binary
(show working for 1 mark and right answer for 1 mark)
Answer… 76-24=

14. Question 13 (2 marks) Question…
What is in 2’s complement 8-bit binary
(show working for 1 mark and right answer for 1 mark)
Answer… =

15. Question 14 (3 marks) Question…
The following floating binary numbers have a 10 bit 2’s complement mantissa and 6 bit 2’s complement exponent. What is the decimal value? a) b) c)
Answer… a) 9.25 b) c) -3.25

16. Question 15
Question…
What is the trade off when changing the size of the mantissa and exponent in terms of accuracy and range.
Answer… A larger mantissa means higher accuracy and lower range whereas higher exponent means higher range but lower accuracy

17. Question 16
Question…
Represent the value − in floating point form using 10-bit two’s complement mantissa and 6-bit two’s complement exponent in normalised form.
Answer…