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End 71 Days Until the Final Catalyst: What is entropy?

Published byAlicia Wilkerson Modified over 7 years ago

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Presentation on theme: "End 71 Days Until the Final Catalyst: What is entropy?"— Presentation transcript:

1 End 71 Days Until the Final Catalyst: What is entropy?
What is the triple point on a phase diagram? What is the critical point on a phase diagram? End

2 ?

3 Today’s Learning Target
7.6 – Using calorimetry data, I can utilize my knowledge of temperature change and specific heats to calculate the amount of heat transferred for a reaction.

4 Today’s Focus Question
How do we determine the amount of calories in Flamin’ Hot Cheetos?

5 Specific Heat The amount of energy that is transferred to a material is dependent on the nature of the material receiving the energy. Specific Heat – The amount of energy required to raise the temperature of one gram of substance one degree Celsius Represent by the symbol Cp

6

7 Calorimetry Calorimetry is the science of measuring the heat of a chemical reaction. q represents the heat gained/released Cp is the specific heat ΔT = Final Temperature – Initial Temp. If we can measure the mass and temperature, then we can determine the heat gained/lost in a reaction

8 Class Example A 4.0 g sample of glass is heated from 274 K to 314 K. Glass has a specific heat of 0.20 J/(g x K). How much heat is gained during this heating?

9 Table Talk The specific heat of copper is 0.4 J/oC. How much heat is needed to change the temperature of a 30 g sample of copper from 20.0 oC to 60.0 oC?

10 Stop and Jot Determine the specific heat of a material if a 35 g sample absorbed 96 J as it was heated from 293 K to 313 K.

11 Calories in Flamin’ Cheetos
Q can be measured in calories Food scientists measure the calories contained within food by measuring the amount of energy it takes to raise 1 g of water 1 oC. 1000 calories = 1 Calorie 1 serving of Cheetos has 140 Calories

12 Summarize

13 Lab Intro Info about lab procedures and equipment.

14 Lab Work Time

15 Lab Calculations

16 Work Time Begin working on your “Homework 7.3”
There will be an exit slip after this activity

17 Learning Log Assessment
Rate yourself 1 – 4 on LTs 7.6

18 Exit Slip 1. I have a sample of water and I increase the temperature from 10.0 oC to 40 oC. The specific heat of water is 4.18 J/(g x oC). Calculate the heat absorbed for this process.

19 Learning Log Assessment
Using your exit slip score, re-rate yourself on LTs 7.6

20

21 Closing Time Homework 7.3 – Calorimetry Calculations
Rough Draft of Lab Report DUE TOMORROW

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