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Published byMaria Dean Modified over 7 years ago
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The Ideal Op-amp (Operational amplifier) v+ VOUT v– +15V VIN VOUT –15V
saturation VOUT VOUT [V] VOUT=A(v+–v–) A~105 VIN [μV]
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Op-amp Feedback v+ VOUT v– v+ VIN VOUT v– R1 R2
Non-Inverting Amplifier Circuit
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Op-amp Feedback v+ v– Assumptions: Gain is very large (A)
Inputs draw no current (ZIN=) Output attempts to make input voltage difference zero (v+=v–) VOUT + – v+ v– VIN R1 R2 Non-Inverting Amplifier Circuit
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R2 R1 v– VIN i VOUT v+ R2 i R1 v– V1 VOUT v+ V2 V3
Inverting Amplifier Circuit R2 – v– v+ i Summing amplifier R2 – + v– v+ VOUT i V1 R1 V2 V3
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RF i V1 R1 V2 R2 V3 R3 v– – VOUT v+ +
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Difference amplifier R2 R1 v– V1 – VOUT v+ R1 + V2 R2
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Integrator VIN VOUT Capacitor as integrator R Vi C Vint If RC>>t
VC<<Vi
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Op-amp Integrator C – v– v+ i R VIN VOUT +
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Differentiation C Vi Vdiff R Small RC
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Op-amp Differentiator
VIN VOUT R – v– v+ i C VIN VOUT +
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Complex analysis R2 i C R1 v– – i VOUT v+ V0ejωt + High pass filter
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Exploiting op-amp saturation
+ – v+ v– VOUT Saturation voltage VOUT = A(v+–v–) A VOUT = +VSat v+>v– VOUT = –VSat v+<v–
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Analogue – digital conversion (ADC)
+ – R + – R + – VIN R + – R
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Oscillator VOUT + R1 C R
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Op-amp applications Building block of analogue electronics
Signal amplifiers Audio amplifiers Integrators / differentiators Voltage / current sources Active filters Oscillators Digital-analogue and analogue-digital convertors
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Bridge circuits Z1 Z3 VA VB V0 VOUT Z4 Z2 Bridge balanced when VAVB=0
+ – VB V0 VOUT Z2 Z4 Bridge balanced when VAVB=0
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End of Op-Amps!
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