1. Chapter 3 Kinematics in two dimensions

2. Up until now we have been working with velocity time etc in 1 dimension (ie only looking at straight line movement)
This chapter extends our work on velocity time into 2 dimensions
You will understand how this is done as we work through the questions …..

3. In order to take the work into 2 dimensions you to
Define a starting point – so we can work from this point
Define a form a measurement – we use unit vectors i and j
Define i and j as being perpendicular to each other
Doing this allows us to form equations using time which tell us the across position (horizontal) and the up position (vertical) at a specific point in time …
Before we understand this fully lets look at the various notations that we have to understand …..

4. 1 2 3
Section A

5. 4 5 6
Section A

6. Section B

7. Expressing Vectors - Task
Put the cards into groups with some meaning

9. r is the position at time t
A new mechanics letter
r is the position at time t
It is the displacement from a defined reference point
(non mechanics people think if it as – distance from a point we made up!)

10. So now lets look at how this works with the time factor
You wont fully understand this until we have got to the end and you have done a few questions
𝐫= 4𝑡+3 𝐢+ 𝑡 2 −4𝑡 𝐣

11. Chapter Notes Page – This all needs to be copied and vaguely understood! Kinematics in two dimensions
4 3
Vector
i and j (perpendicular directions)
Like x and y but not quite the same
𝐫=4𝐢+3𝐣
Resultant
– size given by its length (pythag)
- Direction given by the angle (trig)
As a resultant
distance = (because =5)
direction = (because 𝑡𝑎𝑛 −1 ( 3 4 ))
Using this notation in is possible to find the horizontal position and the vertical position at any point in time
Eg 𝐫= 4𝑡+3 𝐢+ 𝑡 2 −4𝑡 𝐣 This considers the postion of i at time t and considers the position of j at time t

12. Vector form r= i + j Distance Angle Vector form r= i + j Distance
There is a potential problem with the angle… what it it? How do you think this is over come?
Vector form
r= i + j
Distance
Angle
Section C

13. Page 32/33
In practice we will use the table function on the calculator – but this first time these to it by hand to ensure understanding t r i j
Vector /Answer
0.5
Once we have completed this we need to work on squared paper with a reference point

14. t r i j
Vector /Answer
0i + 1j
0.5
3i j 1
6i + 4j
1.5
9i j 2
12i – 3j
Kk remember to describe what this represents

15. So simple don’t use calc
Page 34/35
Table for boat 1 t r i j
Vector /Answer
So simple don’t use calc
Use calc to save time
Table for boat 2 t r i j
Vector /Answer
Now complete your Exercise 3a for homework. You need to do all the questions as they change a little as you go along. You can use the table function on the calc to speed you up.

16. Lets look at the trickier ideas developed in these questions – this is usually how this topic appear in the exam.

17. Worked Example:
A boat moves so that its position, in metres, at time t seconds is given by
r = ( t)i + (4t + 100)j where i and j are unit vectors that are directed east and north, respectively.
A rock has position 250i + 200j.
(a) i) Calculate the time when the boat is due north of the rock.
(ii) Work out the position vector at this point)
(b) i) Calculate the time when the boat is due east of the rock.

18. where i and j are unit vectors that are directed east and north
Task to embed the understanding:
Either go through that question again on your own ensuring you fully understand it OR
Go onto new questions of this type.
Page 35 question 4
4. A boat moves so that its position, in metres, at time t seconds is given by:
r= (2t+6)i+ (3t-9)j
where i and j are unit vectors that are directed east and north
respectively. A lighthouse has position 186i + 281j.
(a) Find the position of the boat, when t = 0, 40, 80 and
120 seconds.
(b) Plot the path of the boat.
(c) Calculate the time when the boat is due south of the
lighthouse and the time when the boat is due east of the
lighthouse.

19. where i and j are horizontal and vertical unit vectors,
5. A bullet is fired from a rifle, so that its position, in metres, at time t seconds is given by:
r = 180ti + ( t2 )j
where i and j are horizontal and vertical unit vectors,
respectively, and the origin is at ground level.
(a) Find the initial height of the bullet.
(b) Find the time when the bullet hits the ground.
(c) Find the horizontal distance travelled by the bullet.
Answers
a) 1.225m b) 0.5 s c) 90m

20. 6 A boomerang is thrown. As it moves its position, in metres, at
time t seconds is modelled by:
r = ( 10t – t2)i +( 2 + t - t2)j
where i and j are horizontal and vertical unit vectors. The
origin is at ground level.
Find the position of the boomerang when it hits the ground.
16i