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Predicting if a Reaction is in Equilibrium

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Presentation on theme: "Predicting if a Reaction is in Equilibrium"— Presentation transcript:

1 Predicting if a Reaction is in Equilibrium
Trial Keq Lesson 9

2 The Keq is a constant- a number that does not change
Changing the volume, pressure, or any concentration, does not change the Keq. Only temperature changes the Keq Increasing a [Reactant] shifts right and maintains the Keq Increasing the temperature of an endothermic equilibrium shifts right and increases the Keq

3 Ktrial How can you tell if a system is in equilibrium or not? Calculate a trial Keq. Use initial concentrations in the equilibrium expression- evaluate.

4 How can you tell if a system is in equilibrium or not?
Calculate a trial Keq. Put initial concentrations into the equilibrium expression and evaluate. If Kt < Keq If Kt = Keq If Kt > Keq Shifts right equilibrium Shifts left Kt Kt Kt Keq 5 20 35

5 1. 10. 0 moles of NH3, 15. 0 moles of N2, and 10
moles of NH3, 15.0 moles of N2, and 10.0 moles of H2 are put in a 5.0 L container. Is the system in equilibrium and how will it shift if it is not? 2NH3(g) ⇄ N2(g) H2(g) Keq = 10 2.0 M M 2.0 M [N2][H2]3 Kt = = (3)(2)3 = 6 (2)2 [NH3]2 Kt < Keq Not in equilibrium Shifts right!

6 2. 4. 56 x 10-5 moles of NH3, 5. 62 x 10-4 moles of N2, and 2
x 10-5 moles of NH3, 5.62 x 10-4 moles of N2, and 2.66 x 10-2 moles of H2 are put in a mL container. Is the system in equilibrium and how will it shift if it is not? 2NH3(g) ⇄ N2(g) H2(g) Keq = 10 9.12 x 10-5 M x 10-5 M 5.32 x 10-2 M [N2][H2]3 Kt = = (1.124 x 10-3 )(5.32 x 10-2 )3 = (9.12 x 10-5 )2 [NH3]2 Kt > Keq Not in equilibrium Shifts left!

7 4. If 4. 00 moles of CO, 4. 00 moles H2O, 6. 00 moles CO2, and 6
4. If 4.00 moles of CO, 4.00 moles H2O, 6.00 moles CO2, and 6.00 moles H2 are placed in a L container at 670 oC. CO(g) H2O(g) ⇄ CO2(g) H2(g) Keq = 1.0 2.00 M M M M Is the system at equilibrium? +x x x x (3)(3) Kt = = (2)(2) x x x x Not in equilibrium Shifts left! [CO2][O2] Keq = [CO][H2O] Calculate all equilibrium concentrations.

8 (3 - x)2 = (2 + x)2 3 - x = 2 + x 3 - x = x 1 = 2x x = M [CO2] = [H2] = = M [CO] = [H2O] = = M

9 Size of the Keq

10 Big Keq products Keq = reactants Keq =

11 reactants Little Keq Keq = Keq = 0.1
products Keq = reactants Keq = 0.1 Note that the keq cannot be a negative number!

12 Keq = 1 products Keq = reactants


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