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Chapter 15 Chemical Equilibrium
Lecture Presentation Chapter 15 Chemical Equilibrium James F. Kirby Quinnipiac University Hamden, CT
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The equilibrium constant Kp for the reaction
is 158 at 1000K. What is the equilibrium pressure of O2 if the PNO = atm and PNO = atm? 2NO2 (g) NO (g) + O2 (g) 2 Kp = 2 PNO PO PNO PO 2 = Kp PNO PO 2 = 158 x (0.400)2/(0.270)2 = 347 atm
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Homogeneous Equilibrium
CH3COOH (aq) + H2O (l) CH3COO- (aq) + H3O+ (aq) [CH3COO-][H3O+] [CH3COOH][H2O] Kc = ‘ [H2O] = constant [CH3COO-][H3O+] [CH3COOH] = Kc [H2O] ‘ Kc =
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Heterogenous equilibrium applies to reactions in which reactants and products are in different phases. CaCO3 (s) CaO (s) + CO2 (g) Kc = ‘ [CaO][CO2] [CaCO3] [CaCO3] = constant [CaO] = constant Kc x ‘ [CaCO3] [CaO] Kc = [CO2] = Kp = PCO 2 PCO 2 does not depend on the amount of CaCO3 or CaO The concentrations of pure solids, pure liquids and solvent do not appear in the equilibrium constant expressions.
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Factors that affect chemical equilibrium
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Le Châtelier’s Principle
If an external stress is applied to a system at equilibrium, the system adjusts in such a way that the stress is partially offset as the system reaches a new equilibrium position. Changes in Concentration Remove Add Add Remove aA + bB cC + dD Change Shifts the Equilibrium Increase concentration of product(s) left Decrease concentration of product(s) right Increase concentration of reactant(s) right Decrease concentration of reactant(s) left
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Le Châtelier’s Principle
Changes in Volume and Pressure A (g) + B (g) C (g) Change Shifts the Equilibrium Increase pressure Side with fewest moles of gas Decrease pressure Side with most moles of gas Increase volume Side with most moles of gas Decrease volume Side with fewest moles of gas Change pressure will not affect the concentration of reacting species in condensed phase, e.g. liquid and solid. In general, the increase of pressure favors the net reaction that decreases the total number of moles of gases and decrease of pressure favors the net reaction that increases the total number of moles of gases
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Le Châtelier’s Principle
Changes in Temperature Change Exothermic Rx Endothermic Rx Increase temperature K decreases K increases Decrease temperature K increases K decreases Increase temperature favors an endothermic reaction, and the temperature decrease favors an exothermic reaction.
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Effect of Pressure Change
Changes in the partial pressure of substances that are part of the equilibrium are handled in the same way as adding or removing a substance. (Changing the partial pressures of gaseous reactants and products by changing volume) Copyright © Cengage Learning. All rights reserved.
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The following reaction is at equilibrium: COCl2(g) CO(g) + Cl2(g)
a. Predict the direction of reaction when chlorine gas is added to the reaction mixture. b. Predict the direction of reaction when carbon monoxide gas is removed from the mixture. Copyright © Cengage Learning. All rights reserved.
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Note: forward = right = .
COCl2(g) CO(g) + Cl2(g) When we add Cl2, the reaction will shift in the reverse direction to use it. Note: reverse = left = . When we remove CO, the reaction will shift in the forward direction to produce it. Note: forward = right = . Copyright © Cengage Learning. All rights reserve
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Effect of Temperature Change
Temperature has profound effect on most of the reactions. Reaction rates usually increase with an increase in temperature. Equilibrium constant vary with temperature. Changing the temperature changes the value of the equilibrium constant. Changing the temperature can also cause a shift in the equilibrium. The direction of each of these changes depends on the sign of DHo. Copyright © Cengage Learning. All rights reserved.
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For an endothermic reaction, DHo > 0 (positive), we consider that heat is a reactant.
For an exothermic reaction, DHo < 0 (negative), we consider that heat is a product. Copyright © Cengage Learning. All rights reserved.
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Le Châtelier’s Principle
Change Equilibrium Constant Change Shift Equilibrium Concentration yes no Pressure yes no Volume yes no Temperature yes yes Catalyst no no
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