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Applications of RAM Section 5.1b.

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1 Applications of RAM Section 5.1b

2 (a) Estimate distance with LRAM:
The “Do Now” – p.255: #10 Time (sec) Velocity (in/sec) 20 1 2 3 4 5 6 7 8 9 10 12 22 10 5 13 11 6 2 15 Velocity (in/sec) 10 5 1 2 3 4 5 6 7 8 9 10 Time (sec) (a) Estimate distance with LRAM: 1( ) = 87 in = 7.25 ft

3 (a) Estimate distance with RRAM:
The “Do Now” – p.255: #10 Time (sec) Velocity (in/sec) 20 1 2 3 4 5 6 7 8 9 10 12 22 10 5 13 11 6 2 15 Velocity (in/sec) 10 5 1 2 3 4 5 6 7 8 9 10 Time (sec) (a) Estimate distance with RRAM: 1( ) = 87 in = 7.25 ft

4 Estimate for road length using LRAM:
Now let’s work through #12 on the same page!!! 50 40 30 Velocity (ft/sec) 20 10 10 20 30 40 50 60 70 80 90 100 110 120 Time (sec) Estimate for road length using LRAM: 10( … + 30) = 3490 ft

5 Estimate for road length using RRAM:
Now let’s work through #12 on the same page!!! 50 40 30 Velocity (ft/sec) 20 10 10 20 30 40 50 60 70 80 90 100 110 120 Time (sec) Estimate for road length using RRAM: 10( … + 35) = 3840 ft

6 Now let’s work through #12 on the same page!!!
50 40 30 Velocity (ft/sec) 20 10 10 20 30 40 50 60 70 80 90 100 110 120 Time (sec) 3490 ft ft Average = = 3665 ft 2

7 Using RAM to Approximate Volume
Estimate the volume of a solid sphere of radius 4. First, graph the function: Now, imagine the sphere as the revolution of this function about the x-axis…

8 Using RAM to Approximate Volume
Estimate the volume of a solid sphere of radius 4. We partition the function into 8 subintervals of equal length and slice the sphere with planes perpendicular to the x-axis at the partition points. Look at the diagrams on p.251…

9 Using RAM to Approximate Volume
Estimate the volume of a solid sphere of radius 4. Each slice can be approximated by a cylinder: Height: Radius: Volume of each cylinder:

10 Using RAM to Approximate Volume
Estimate the volume of a solid sphere of radius 4. Use the RAM program: Function: Interval: [– 4, 4] Number of Slices (n) MRAM n 10 25 50 100 Let’s work with this last value…

11 The error percentage is only about 5 thousandths of a percent!
Using RAM to Approximate Volume Estimate the volume of a solid sphere of radius 4. Approximated volume: How close is this to the actual volume?: The error percentage is only about 5 thousandths of a percent! As a percentage of V :

12 Using RAM to Approximate Volume
Let’s try #20 on p.256… Volume of each of the cylinders: Use LRAM with on the interval [0,5], n = 5:


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