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Specific Heat 4/28/17
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Heat is the ___Transfer___ of energy due to a change in temperature
OUCH! Why can you still burn your fingers by touching the metal handle of a pot on the stove even when the water is only lukewarm? The heat is still there…in the water. It holds 10x’s more heat than the iron pot! The __Specific Heat __ of water is very high; it takes a lot of energy to raise one gram of water 1 degree Celsius.
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Calories to Joules _1_calorie = Joules 1 kilocalorie = ___1000____ calories. ( a kilocalorie is the same thing as “big C” Calorie)
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SPECIFIC HEAT CAPACITY
The amount of heat (in calories or Joules) that must be added or removed from a __gram___ of that substance to change its temperature by ____1˚C__. WHEN THERE IS HEAT/ENERGY INVOLVED: Q (heat energy) = m (mass) x Δt (temp.) x cp (specific heat capacity) (cal/Joules) (g) (°C) (cal/g °C) or (Joule/g °C)
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Problem 1 How much heat energy is needed to raise the temperature of 100 grams of water from 0 degrees to 30° C? (the specific heat of water is J/(g°C) Find your variables: Q=? m= 100 g ΔT= 30° C - 0° C = 30° C Cp = 4.18 J/(g°C) Solve for Q… 12,540 J or KJ
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Problem 2 A calorimeter contains 300 grams of water at 10° C. After a food sample is burned in the calorimeter the water temperature changes to 15° C. How much heat was given off by the food sample? Can you recall the specific heat of water from the last problem?? You’re going to need it.
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Problem 3 What amount of heat is required to raise the temperature of 85.9 g of water by 7C? The specific heat of water is J/gC.
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Problem 4 What amount of heat is required to increase the temperature of 75.0 g of water from 22.3C to 36.1C? The specific heat of water is J/gC.
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Problem 5 How much energy is required to increase the temperature of 100 grams of water from 25 C to 85 C?
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Problem 6 How much water can absorb calories of heat if the temperature changes 5 degrees? Can we use the specific heat value for water we have been using (4.18 J/gC.) ? No we cannot! The Problem asks for calories not Joules. We must use 1 c/g °C
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Problem 7 q(water) = m c (T-22.3) q(silver) = m c (T-100)
You place g of water in a coffee-cup calorimeter and the temperature of the water is 22.3C. A 94.5 g piece of silver metal is heated to 100.0C and added to the water in the calorimeter. What will the final temperature of the silver and the water be? The specific heat of silver is J/gC. q(water) = m c (T-22.3) q(silver) = m c (T-100) set the two equations equal to each other q(water)= -q(silver)
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