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S4 Credit The gradient Vertical ÷ Horizontal

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Presentation on theme: "S4 Credit The gradient Vertical ÷ Horizontal"— Presentation transcript:

1 Straight Line Graphs www.mathsrevision.com
S4 Credit The gradient Vertical ÷ Horizontal The gradient from Coordinates Drawing Straight line graphs General Equation y = mx + c Equation from 2 Points Modelling Situations Best – fitting straight line Exam Type Questions

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Starter Questions S4 Credit Q1. Calculate 7 – 5 x 2 Q2. Calculate Q3. Is this triangle right angled ? Explain 9 8 5 15-Dec-17 Created by Mr.Lafferty Maths Dept

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The Gradient of a Line S4 Credit Learning Intention Success Criteria To show how to get the equations for horizontal and vertical lines. Understand that vertical lines have equations of the form x = a 2. Understand that horizontal lines have equations of the form y = a 15-Dec-17 Created by Mr.Lafferty Maths Dept

4 x = -6 Mark the points on your grid below and then join them together
Equations for Vertical and Horizontal lines 1 2 3 4 5 6 7 8 9 10 -9 -8 -7 -6 -5 -4 -3 -2 -1 -10 x y x = -6 Mark the points on your grid below and then join them together Vertical lines have equations of the form x = 8 Horizontal lines have equations of the form y = 2 y = -9 15-Dec-17 Created by Mr. Lafferty Maths Dept

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The Gradient S4 Credit Now Try MIA Exercise 2.1 Ch7 (page 136) 15-Dec-17 Created by Mr.Lafferty Maths Dept

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Starter Questions S4 Credit Q1. Write this number in full to 1 sig. figs Q2. Calculate the volume of the triangular prism. 20cm 12cm 8cm 15-Dec-17 Created by Mr.Lafferty Maths Dept

7 The Gradient of a Line www.mathsrevision.com Learning Intention
S4 Credit Learning Intention Success Criteria To explain how to calculate the gradient using a right angle triangle Gradient is : change in vertical height divided by change in horizontal distance 2. Calculate simple gradients. 15-Dec-17 Created by Mr.Lafferty Maths Dept

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The Gradient Difference in y -coordinates S4 Credit The gradient is the measure of steepness of a line Change in vertical height Change in horizontal distance Difference in x -coordinates The steeper a line the bigger the gradient 15-Dec-17 Created by Mr.Lafferty Maths Dept

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The Gradient S4 Credit 3 4 3 2 3 5 2 6 15-Dec-17 Created by Mr.Lafferty Maths Dept

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The Gradient S4 Credit Now Try MIA Exercise 3.1 Ch7 (page 139) 15-Dec-17 Created by Mr.Lafferty Maths Dept

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Starter Questions S4 Credit Q1. A house is valued at £ Calculate it’s value after 4 years if it appreciates by 5% each year. Q2. Calculate 3.36 x 70 to 2 significant figures. Q3. Calculate the volume of a cylinder with radius 5cm and height 100 cm. 15-Dec-17 Created by Mr.Lafferty Maths Dept

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The Gradient of a Line S4 Credit Learning Intention Success Criteria To explain positive and negative gradients using coordinates. Know gradient formula. 2. Calculate gradients given two coordinates. 15-Dec-17 Created by Mr.Lafferty Maths Dept

13 The gradient using coordinates
Mr. Lafferty The gradient using coordinates S4 Credit m = gradient y-axis y2 We start by find the equation of a circle centre the origin. First draw set axises x,y and then label the origin O. Next we plot a point P say, which as coordinates x,y. Next draw a line from the origin O to the point P and label length of this line r. If we now rotate the point P through 360 degrees keep the Origin fixed we trace out a circle with radius r and centre O. Remembering Pythagoras’s Theorem from Standard grade a square plus b squared equal c squares we can now write down the equal of any circle with centre the origin. y1 O x-axis x1 x2 15-Dec-17

14 The gradient using coordinates
Mr. Lafferty The gradient using coordinates S4 Credit Find the gradient of the line. m = gradient y-axis We start by find the equation of a circle centre the origin. First draw set axises x,y and then label the origin O. Next we plot a point P say, which as coordinates x,y. Next draw a line from the origin O to the point P and label length of this line r. If we now rotate the point P through 360 degrees keep the Origin fixed we trace out a circle with radius r and centre O. Remembering Pythagoras’s Theorem from Standard grade a square plus b squared equal c squares we can now write down the equal of any circle with centre the origin. O x-axis 15-Dec-17

15 The gradient using coordinates
Mr. Lafferty The gradient using coordinates S4 Credit Find the gradient of the two lines. y-axis We start by find the equation of a circle centre the origin. First draw set axises x,y and then label the origin O. Next we plot a point P say, which as coordinates x,y. Next draw a line from the origin O to the point P and label length of this line r. If we now rotate the point P through 360 degrees keep the Origin fixed we trace out a circle with radius r and centre O. Remembering Pythagoras’s Theorem from Standard grade a square plus b squared equal c squares we can now write down the equal of any circle with centre the origin. O x-axis 15-Dec-17

16 The gradient using coordinates
S4 Credit The gradient formula is : It is a measure of how steep a line is A line sloping up from left to right is a positive gradient A line sloping down from left to right is a negative gradient 15-Dec-17 Created by Mr.Lafferty Maths Dept

17 The gradient using coordinates
S4 Credit Now try MIA Ex 4.2 Ch7 (page 143) 15-Dec-17 Created by Mr.Lafferty Maths Dept

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Straight Line Graphs S4 Credit Learning Intention Success Criteria To draw graphs by using a coordinate table Understand the keypoints of drawing a straight line graph Be able to plot a straight line graph 15-Dec-17 Created by Mr.Lafferty Maths Dept

19 Drawing Straight Line Graphs y = ax + b y = x
1 2 3 4 5 6 7 8 9 10 -9 -8 -7 -6 -5 -4 -3 -2 -1 -10 x y x y 3 -4 y = 3x+1 3 -4 x y -2 2 -5 1 7 y = x - 3 y = 2x x y 4 8 x y 3 -4 -3 1 5 6 -8 15-Dec-17 Created by Mr. Lafferty Maths Dept

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Straight Line Graphs S4 Credit Key Points Make a table Calculate and plot 3 coordinates 3. Draw a line through points 15-Dec-17 Created by Mr.Lafferty Maths Dept

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Straight Line Graphs S4 Credit Now try MIA Ex5.1 Q5 Only Ch7 (page 145) 15-Dec-17 Created by Mr.Lafferty Maths Dept

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Starter Questions S4 Credit Q1. Write out in full to 2 sig. figs. Q2. A superstore make 20% profit on each can of soup they sell. If they buy in a can for 50p. What is the selling price. Q3. A hemisphere has a diameter of 10cm. Calculate its volume. 15-Dec-17 Created by Mr.Lafferty Maths Dept

23 The Straight Line Equation
S4 Credit Learning Intention Success Criteria To explain the connection between the straight line equation and the gradient. Understand the term standard form. 2. Identity the gradient m from the standard form. 15-Dec-17 Created by Mr.Lafferty Maths Dept

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Straight line equation and the gradient connection 1 2 3 4 5 6 7 8 9 10 -9 -8 -7 -6 -5 -4 -3 -2 -1 -10 x y y = 2x - 5 y = 2x + 1 x y 1 3 x y 1 3 -5 -3 1 1 3 7 m = 2 m = 2 15-Dec-17 Created by Mr. Lafferty Maths Dept

25 Straight Line Equation
S4 Credit y 10 lines are parallel if they have the same gradient All straight lines have the equation of the form 9 8 y = mx + c 7 6 5 4 3 Where line meets y-axis 2 Gradient 1 x 1 2 3 4 5 6 7 8 9 10 Find the equations of the following lines y = x y = x+4 y = 4x+2 y = -0.5x+2 15-Dec-17 Created by Mr.Lafferty Maths Dept

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The Gradient of a Line S4 Credit Now try MIA Ex 6.1 Ch7 (page 146) 15-Dec-17 Created by Mr.Lafferty Maths Dept

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Starter Questions S4 Credit Q1. Write out in full to 1 significant fig. Q2. A computer store buys in a laptop for £500. They want to make a 40% profit. How much do they sell it for. Q3. A line is parallel to y = 2x. Write down its equation 15-Dec-17 Created by Mr.Lafferty Maths Dept

28 Straight Line Equation
lines are parallel if same gradient Straight Line Equation S4 Credit All straight lines have the equation of the form Slope left to right upwards positive gradient y = mx + c y - intercept Gradient y intercept is were line cuts y axis Slope left to right downwards negative gradient 15-Dec-17 Created by Mr.Lafferty Maths Dept

29 Equation of a Straight Line
y = mx+c S4 Credit To find the equation of a straight line we need to know Two points that lie on the line ( x1, y1) and ( x2, y2) Or The gradient and a point on the line m and (a,b) 15-Dec-17

30 Equation of a Straight Line
Mr. Lafferty Equation of a Straight Line y = mx+c S4 Credit Find the equation of the straight line passing through the points (4, 4) and (8,24). Solution Using the point (4,4) and the gradient m = 5 sub into straight line equation We are now in a position to find the equation of any circle with centre A,B. All we have to do is repeat the process in shown in slide 2, but this time the centre is chosen to be (a,b). First plot a point C and label it’s coordinates (a,b), next we plot another point P and label it’s coordinates (x,y). Next draw a line from C to P and call this length (r). (r) will be the radius of our circle with centre (a,b). Again we rotate the point P through 360 degrees keeping the point C fixed. Using Pythagoras Theorem a squared plus b squared equal c squared we can write down the equation of any circle with centre (a,b) and radius (r). The equation is (x - a) all squared plus (y-b) all squared equals (r) squared. Finally to write down the equation of a circle we need to know the co-ordinates of the centre and the length of the radius or co-ordinates of the centre and the co-ordinates of a point on the circumference of the circle. y = mx + c 4 = 5 x 4 + c c = = -16 Equation : y = 5x - 16

31 Equation of a Straight Line
Mr. Lafferty Equation of a Straight Line y = mx+c S4 Credit Find the equation of the straight line passing through the points (3, -5) and (6,4). Solution Using the point (6,4) and the gradient m = 3 sub into straight line equation We are now in a position to find the equation of any circle with centre A,B. All we have to do is repeat the process in shown in slide 2, but this time the centre is chosen to be (a,b). First plot a point C and label it’s coordinates (a,b), next we plot another point P and label it’s coordinates (x,y). Next draw a line from C to P and call this length (r). (r) will be the radius of our circle with centre (a,b). Again we rotate the point P through 360 degrees keeping the point C fixed. Using Pythagoras Theorem a squared plus b squared equal c squared we can write down the equation of any circle with centre (a,b) and radius (r). The equation is (x - a) all squared plus (y-b) all squared equals (r) squared. Finally to write down the equation of a circle we need to know the co-ordinates of the centre and the length of the radius or co-ordinates of the centre and the co-ordinates of a point on the circumference of the circle. y = mx + c 4 = 3 x 6 + c c = = -14 Equation : y = 3x - 14

32 Created by Mr.Lafferty Maths Dept
Straight Line Graphs S4 Credit Now try MIA Ex 6.2 Ch7 (page 147 ) 15-Dec-17 Created by Mr.Lafferty Maths Dept

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Starter Questions S4 Credit Q1. The points ( 1, 4) and (3, 11) lie on a line. Find the gradient of the line. Q2. Complete the table given : y = 3x + 1 x -3 3 y Q3. Are the two lines parallel. Explain answer y = x and y = 2x + 2 15-Dec-17 Created by Mr.Lafferty Maths Dept

34 Modelling Using Straight Line Equation
S4 Credit Learning Intention Success Criteria How to model real life situations using straight line theory Be able to work out gradient and y intercept using a graph. Form an equation for any straight line graph. 15-Dec-17 Created by Mr.Lafferty Maths Dept

35 The cost for hiring a plumber per hour is shown below
Pick any 2 points Modelling Real – life The cost for hiring a plumber per hour is shown below 10 1 2 3 4 5 6 7 8 9 10 T C 20 30 40 50 60 70 80 90 100 Cost £ Time (hours) (7,100) (a) Calculate the gradient. What is the value of C when T = 0 30 30 Write down an equation connecting C and T. (0,30) C = T + (d) Find the cost for a plumber for 10 hours? T = 10 C = 10x = £130

36 (a) Calculate the gradient. (0,80) What is the value of V when T = 0
Pick any 2 points Modelling Real – life The graph shows how a the volume of water tank drains over time. -5 1 2 3 4 5 6 7 8 9 10 T V 20 30 40 50 60 70 80 90 100 Volume Time (mins) (a) Calculate the gradient. (0,80) What is the value of V when T = 0 80 80 (8,40) Write down an equation connecting V and T. V = T + (d) How long before the tank is empty? V = 0 0 = -5xT + 80 T = (-80) ÷(–5) = 16mins

37 Straight Line Equation
S4 Credit Now try Ex 7.1 MIA (page 149) 15-Dec-17 Created by Mr.Lafferty Maths Dept

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Starter Questions S4 Credit Q1. The points ( 5, 7) and (7, 21) lie on a line. Find the gradient of the line. Q2. Complete the table given : y = 2x + 10 x -3 3 y Q3. Are the two lines parallel. Explain answer y = -2x and y = 2x + 1 15-Dec-17 Created by Mr.Lafferty Maths Dept

39 Best Fit Straight Line Equation
S4 Credit Learning Intention Success Criteria How to model real life situations using straight line theory Be able to work out gradient and y intercept using a graph. Form an equation for any straight line graph. 15-Dec-17 Created by Mr.Lafferty Maths Dept

40 Best-Fitting Straight line
Data was collected on pupils weight and height. Data is plotted below. Pick any 2 points (a) Is there correlation between height and weight. Yes, a positive correlation 10 20 30 40 50 60 70 80 90 100 w h 120 140 160 180 200 Height (cms) Weight (Kgs) Draw in the best-fit line and find an equation relating height and weight. x (70,180) 2.57 c = 0 (0,0) x h = w + (d) What height is a pupils who weights 40 kgs? w = 40 h = 2.57x40 = cms

41 Best-Fitting Straight line
A survey was carried out on the value of cars depending on their age The data is plotted below. Pick any 2 points (a) Is there correlation between value and age. Yes, a negative correlation 1 2 3 4 5 6 7 8 9 10 y v 12 14 16 18 20 value £ ‘ 000 Years Draw in the best-fit line and find an equation relating value and year. (0,18) x x (8,8) -1.25 c = 18 18 v = y + (d) What is the cost of a car after 4years? y = 4 v = -1.25x = 13 Value = £13 000

42 Best Fit Straight Line Equation
S4 Credit Now try Ex 8.1 MIA (page 151) 15-Dec-17 Created by Mr.Lafferty Maths Dept

43 Straight Line Questions
Exam Type Straight Line Questions Example The graph shows an electrician’s charging system. He has a call-out charge plus an hourly rate. S4 Credit a) Work out the equation of the line. b) Calculate the cost of a 10 hour job.

44 Straight Line Questions
Exam Type Straight Line Questions S4 Credit a) Pick two convenient points on the line, say (0, 30) and (5, 80). Thinking of the form y = mx + c The y-intercept gives c = 30 = 10 The equation is: y = 10x + 30 The label on the y-axis is C and the label on the x-axis is T So the equation is C = 10 T So the equation is C = 10 T b) Find C when T = 10 C = 10 x = 130 The cost of a 10 hr job is £130.

45 Straight Line Questions
Exam Type Straight Line Questions S4 Credit 1. The tank of a car contains 5 litres of petrol. The graph below shows how the volume of petrol in this tank changes as a further 45 litres of petrol is pumped in at a steady rate for 60 seconds. Find the equation of the straight line in terms of V and t.

46 Straight Line Questions
Exam Type Straight Line Questions S4 Credit 2. In the diagram below. A is the point (-1, -7) and B is the point (4, 3). (a) Find the gradient of the line AB. AB cuts the y-axis at the point (0, -5). Write down the equation of the line AB. The point (3k, k) lies on the line AB. Find the value of k.

47 Straight Line Questions
Exam Type Straight Line Questions S4 Credit 3. A water pipe runs between two buildings. These are represented by the points A and B in the diagram below. (a) Using the information in the diagram, show that the equation of the line AB is 3y – x = 6.

48 Straight Line Questions
Exam Type Straight Line Questions S4 Credit (b) An emergency outlet pipe has to be built across the main pipe. The line representing this outlet pipe has equation 4y + 5x = 46. Calculate the coordinates of the point on the diagram at which the outlet pipe will cut across the main water pipe.

49 Straight Line Questions
Exam Type Straight Line Questions S4 Credit


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