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The Mole, Mass & Formulas
Dr. Ron Rusay Fall 2001 © Copyright 2001 R.J. Rusay
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The Mole Definition: The number of carbon atoms in exactly 12 grams of pure 12C. The number equals atoms. 1 mole = 6.02 units 6.02 “units” of anything: atoms, people, stars, $s, etc., etc. = 1 mole There are about 6.2 billion people in the world. How many moles of people are there?
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Avogadro’s number equals 1 mole ….which equals
Avogadro’s number equals 1 mole ….which equals 6.022 1023 “units” How many molecules are there in 0.5 moles of oxygen?
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Counting by Weighing 12 red marbles @ 7g each = 84g
12 yellow each=48g 55.85g Fe = x 1023 atoms Fe 32.07g S = x 1023 atoms S Consult the Periodic Table
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Relative Masses of 1 Mole
CaCO3 Name? g Oxygen 32.00 g Copper 63.55 g Water 18.02 g 1 mole of a gas equals 22.4 Liters. (A balloon diameter of 35 cm.) What is the volume of 1 mole of water?
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Atomic and Molecular Weights Mass Measurements
1H weighs x g and 16O x g. DEFINITION: mass of 12C = exactly 12 amu. Using atomic mass units: 1 amu = x g 1 g = x 1023 amu
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Atomic and Molecular Weights
Formula Weight a.k.a. Molecular Weight Formula weights (FW): sum of Atomic Weights (AW) for atoms in formula. FW (H2SO4) = 2AW(H) + AW(S) + 4AW(O) = 2(1.0 amu) + (32.0 amu) + 4(16.0) = amu
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Atomic and Molecular Weights
Molecular weight (MW) is the weight of the molecular formula in amu. MW of sugar (C6H12O6 ) = ? MW = 6(12.0 amu) + 12(1.0 amu) + 6(16.0 amu) = 180 amu
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Molar Mass A substance’s molar mass is the mass in grams of one mole of the element or compound. (Equals the formula weight: atomic or molecular weight in grams) Molar Mass CO2 = ? C = grams per mole (g/mol) O = grams per mole (g/mol) CO 2 = grams per mole (g/mol) (16.00) = 44.01
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Percent Composition Mass percent of an element:
For iron in (Fe2O3), iron (III) oxide = ?
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Formulas: Dalton’s Law
Dalton’s law of multiple proportions: When two elements form different compounds, the mass ratio of the elements in one compound is related to the mass ratio in the other by a small whole number.
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Formulas: Multiple Proportions
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Formulas & Multiple Proportions Components of acid rain, SO2(g) and SO3(g)
Compound A contains: 1.000 g Sulfur & g Oxygen Compound B contains: 1.000 g Sulfur & g Oxygen Mass ratio A: 1 to 1.5; Mass ratio B: 1 to 1 MUST adjust for atomic mass differences: AW sulfur is 2x the AW oxygen; therefore the oxygen ratios are 2x sulfur. S1O3 and S1O2 respectively
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Formulas & Molecular Representations
molecular formula = C6H6 Benzene empirical formula = CH = C6/6H6/6 molecular formula = (empirical formula)n [n = integer] (CH)6 Other representations: Lewis Dot formulas, structural formulas, 2-D, 3-D
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Formulas & Molecular Representations
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Empirical Formulas from Analyses
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Empirical Formula Determination
1. Use percent analysis. Let 100 % = 100 grams of compound. 2. Determine the moles of each element. (Element % = grams of element.) 3. Divide each value of moles by the smallest of the mole values. 4. Multiply each number by an integer to obtain all whole numbers.
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Empirical & Molecular Formula Determination
Quinine: C 74.05%, H 7.46%, N 8.63%, O 9.86% 74.05/12.01, 7.46/1.008, 8.63/14.01, 9.86/16.00 C6.166 H7.40 N0.616 O0.616 Empirical Formula: C10 H12 N1 O1 Empirical Formula Weight = ? Molecular Weight = Molecular Formula = 2x empirical formula Molecular Formula = C20 H24 N2 O2
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Structural Representations of Quinine
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