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Surface Area of Pyramids

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1 Surface Area of Pyramids
Lesson 9.2 7.G.6: Solve real-world and mathematical problems involving area, volume, and surface area of two- and three-dimensional objects composed of triangles, quadrilaterals, polygons, cubes, and right prisms.

2 Pyramids Pyramids are named from their base shape
Most pyramids we’ve seen are square pyramids but there are plenty of others as well…

3 Parts of a pyramid A regular pyramid is a pyramid whose base is a regular polygon (all sides equal). The lateral faces are triangles. The height of each triangle is the slant height of the pyramid.

4 Surface Areas of Pyramids and Cones
Regular Pyramid The slant height of a pyramid or cone is measured along its lateral surface. Right cone The base of a regular pyramid is a regular polygon, and the lateral faces are all congruent. In a right cone, a line perpendicular to the base through the vertex passes through the center of the base.

5 Another look Surface Area of Pyramid =
Area of Base + Areas of Lateral Faces

6

7 Example 1A: Finding Surface Area using a net

8 Example 1B: Find the Surface Area of a Pyramid
Find the surface area of the figure. SA = B + 1/2 Pl = (2.4 • 2.4) (9.6)(3) 1 2 = ft2

9 You Try! What is the surface area of a square pyramid with a base side length of 9 cm and a slant height of 7 cm? (Draw a picture, then solve) 207 cm2

10 Example 2: Finding Surface Area of a Triangular Pyramid

11 Surface Area of a Composite Solid
Composite Solid: A figure that consists of two or more geometric shapes

12 Surface Area of a Composite Solid
When finding the surface area of a composite solid, remember that surface area is only the area of the SURFACES (some parts of figures get covered)

13 Example 3 – Find the surface area of a composite figure
283.5 cm2

14 Example 4: Real-Life Application

15 17 bundles Example 4 extension
One bundle of shingles covers 32 square feet. How many bundles should you buy to cover the roof? 17 bundles

16 You Try! 105.6 ft2

17 Additional Example: Find the Surface Area of a Cone
Find the surface area of each figure to the nearest tenth. Use 3.14 for p. SA = pr2 + prl 18 ft = p(72) + p(7)(18) 7 ft = 175p  ft2

18 Homework  p.366 #1-3, 8-16 even, 17-20


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