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Type II Projectiles
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Type II Projectile Motion
Projectile motion in which launch angle is above the horizon and the projectile lands at the same altitude as it was launched. Example: A golf ball driven from the tee box without the use of a tee lands on the green; the green has the same elevation as the tee box.
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Type II Projectile Motion
For a given initial speed, what angle gives maximum range?
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Type II Projectile Motion
For a given initial speed, what angle gives maximum range?
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Commit to Memory You’re expected to know the following characteristics of Type II Projectile problems. Δtup = Δtdown
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Commit to Memory You’re expected to know the following characteristics of Type II Projectile problems. Δtup = Δtdown vy = 0 at top of trajectory (zenith); note that v ≠0!
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Commit to Memory You’re expected to know the following characteristics of Type II Projectile problems. Δtup = Δtdown vy = 0 at top of trajectory (zenith); note that v ≠0! The magnitude of vimpact = the magnitude of vinitial angles are opposite sign
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Commit to Memory You’re expected to know the following characteristics of Type II Projectile problems. Δtup = Δtdown vy = 0 at top of trajectory (zenith); note that v ≠0! The magnitude of vimpact = the magnitude of vinitial; angles are opposite sign (below vs. above horizontal) Maximum range is achieved with a 45° angle.
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Type II Projectile Motion
How do Type II problems differ from Type I problems?
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Solving Type II Draw a VELOCITY vector triangle to find the components of the launch velocity Set up x and y lists Solve
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Type II Projectile Motion – Sample Problem
A golf ball is driven from level ground with an initial velocity of 40 m/s at an angle of 30° above the horizon. Find: Max height of ball’s path b) hangtime c) range d) impact velocity
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