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2D - Quadratics Test Solutions.

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Presentation on theme: "2D - Quadratics Test Solutions."— Presentation transcript:

1 2D - Quadratics Test Solutions

2 Averages / Medians Average Median KU 80.2% 90% App 65.7% 63.5% Comm
70.7% 71.5%

3 Part A – Knowledge [10 marks]
Question #1 y = -(x + 4)2 + 5 Vertex  (-4, 5) Maximum (opens down because of negative sign) Question #2 y = x2 + 2x – 1 same as y = (x-1)2 False – expand (x – 1)2 you get y = x2 – 2x + 1 Question #3 Factor y = 2x2 – 3x – 9 You get y = (2x + 3)(x – 3)

4 Part A – Knowledge (continued)
Question #4 – write in vertex form by completing the square y = -x2 + 6x – 3 You get y = -x(x – 3)2 + 6 Question #5 – find the axis of symmetry for roots (-1, 4) and (6, 4)

5 Part A – Knowledge (continued)
Question #6 – write the equation of a parabola with zeros (3, 0) and (-4, 0) and a y-intercept of (0, -24)

6 Part B – Level 2 Questions
Question #1 – How many zeros y = 5x2 + 4x + 1 Use discriminant Therefore , no zeros!!

7 Part B – Level 2 Questions
Question #2 – Write in other forms y = -2(x – 2)2 + 50 Standard Form Factored Form

8 Part B – Level 2 Questions
Question #3 – Create an I/O diagram, describe transformations for y = -0.5(x + 5)2 - 2 Input (x) +5 ^2 * -0.5 -2 Output (y) (x, y) -5 (-5, -2) -3 2 4 -4 (-3, -4) -1 16 -8 -10 (-1, -10) Transformations: Horizontal shift left 5 Vertical shift down 2 Stretch of ½ (fatter) Reflected over the x-axis (flipped)

9 Part B – Level 3 Questions
Question #4 – Ball on roof (Solution #1) Find equation: Solve for t: (plug in 10 for h) t = 3.6s or t = 0.4s (ignore) Ball was above 10m for approx 3.6s

10 Part B – Level 3 Questions
Better!!! Part B – Level 3 Questions Question #4 – Ball on roof (Solution #2) Find equation: Solve for t: (plug in 10 for h) t = 4.31s or t = -0.31s (ignore) Ball was above 10m for approx 4.31s

11 Part B – Level 3 Questions
Question #5 – Truck under bridge Find Equation: Find height at d of 1.25m: Since the truck is only 4m high, it will fit under the bridge!

12 Part B – Level 3 Questions
Question #6 – Cranberry Juice (Solution #1) Find linear equation for relationship: Revenue = price(#sold) Revenue = x(y)

13 Part B – Level 3 Questions
Question # 6 (continued) Zeros are (0, 0) and (4.35, 0) Find axis of symmetry: Find Revenue that occurs at optimal value: Conclusion: The maximum revenue is $ that occurs when they sell 435 bottles of cranberry juice for a price of $2.18. All numbers are approximate.

14 Part B – Level 3 Questions
Question #7 – Garden fencing (Area problem)

15 Part B – Level 3 Problems Question # 7 (continued) Conclusion:
Axis of Symmetry: Conclusion: The maximum Area is 37.5ft2, which occurs with a length of 7.5ft and a width of 5ft. Optimal Value at width of 7.5:

16 Part B – Level 4 Question Question #8 – Water Jets
Need to find equation of Jet #1: Two Methods: Method #1: get into Standard Form, use Substitution and Quadratic Formula to solve for d Method #2: Substitute in 0.5 for d in each equation and analyze the results

17 Part B – Level 4 Question Question #8 – Water Jets (Method #1)
Equation Jet #1 into Standard Form: Use Substitution:

18 Question #8 (Method #1 - continued) Use quadratic formula to find d
Therefore, the Jets will meet at 1.58m ... Which is after 0.5m, so her plans are fine!

19 Question #8 (Method #2) Jet #1: Jet #2:
This means that at 0.5m away from the post, Jet #1’s water stream is still below Jet #2, so they have not yet met. Therefore, if they meet it will be after 0.5m so her plan is fine!


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