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7.1. Graphing Quadratics Standard Form
College Algebra 7.1. Graphing Quadratics Standard Form
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Do Now: Solve each of the following problems 8+3 π₯+2 2 =44 β π₯ 2 =4π₯
8+3 π₯+2 2 =44 β π₯ 2 =4π₯ 5 π₯ 2 =35 2 π₯ 2 +7π₯+1=5 4 π₯ 2 β2π₯β5=0
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Do Now: Complete do now handed to you when you entered class
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Homework Questions? Comments? Confusions? Concerns?
ASK ASK ASK ASK ASK!
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Goal: We currently know how to factor quadratics or things that look like π π₯ 2 +ππ₯+π, butβ¦ what do they look like on a graph?
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We know⦠Linear Equations
π¦=ππ₯+π
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We know⦠Exponential Equations
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Now⦠Quadratic Equations
The graph of π π₯ 2 +ππ₯+π=0 will always look like a U shape
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Parabola: This U shape, is called a parabola
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Parts of a Parabola
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Parts of a Parabola Vertex: The highest or lowest point on a graph
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Parts of a Parabola Axis of Symmetry: The vertical βmirrorβ of the graph that goes through the vertex. Everything on the left side of this line is mirrored on the right side.
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Parts of a Parabola Y Intercept: Where the graph crosses the π¦βππ₯ππ . There is always one and only one Y intercept for a quadratic equation.
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Parts of a Parabola X Intercept: Where the graph crosses the π₯- axis. These are the solutions of the quadratic equation: If the equation has two solutions, it intersects the π₯βππ₯ππ twice. If the equation has one solution, it intersects the π₯βππ₯ππ once. If the equation has no solutions, it never intersects the π₯βππ₯ππ
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Visually: X intercepts
Two Intercepts:
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Visually: One Intercept
One X Intercept:
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Visually: X Intercepts
No X Intercepts:
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Realize: Parabolas can be open βupβ (Happy Face) or βdownβ (Frowny Face)
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Example One: Graph π π₯ = π₯ 2 β4π₯+3 Direction of Opening
Vertex/Axis of Symmetry Y intercept X Intercepts Domain Range
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How to Graph Parabolas:
** Our equation must be in the form π π₯ 2 +ππ₯+π=0 Step 1: We determine the direction of opening by checking if π is positive or negative.
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How to Graph Parabolas:
Step Two: We find the vertex byβ¦ Find the value of β π 2π . This is the x coordinate of the vertex Plugging in this value for x in the equation yields the y coordinate of the vertex The axis of symmetry is π₯=β π 2π We plot the point we found and the axis of symmetry line
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How to Graph Parabolas:
Step Three: We find the y-intercept by plugging in zero for x. Plot our value on the y axis. If the point does not fit in your picture, do not graph it If the point does fit, graph the point and its mirror image on the other side of your axis of symmetry.
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How to Graph Parabolas:
Step Four: Find the x intercepts by solving the quadratic equation. Make π¦=0 and you canβ¦ Take the square root if π=0 Factor the GCF if π=0 Use PS2 if all three terms are present Quadratic Formula is all else fails
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How to Graph Parabolas:
Step Five: Draw your parabola. You must have at least three points plotted. Make sure that it is a U shape and not a V shape or straight line.
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Example One: Graph π π₯ = π₯ 2 β4π₯+3 Direction of Opening
Vertex/Axis of Symmetry Y intercept X Intercepts Domain Range
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Example Two: Graph π π₯ = βπ₯ 2 β8π₯β12 Direction of Opening
Vertex/Axis of Symmetry Y intercept X Intercepts Domain Range
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Example Three: Graph π π₯ = π₯ 2 β5π₯ Direction of Opening
Vertex/Axis of Symmetry Y intercept X Intercepts Domain Range
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Do Now: Handed to you when you entered class
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Example Four: Graph π π₯ = π₯ 2 β4 Direction of Opening
Vertex/Axis of Symmetry Y intercept X Intercepts Domain Range
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You Try #1: Graph π π₯ = π₯ 2 β8π₯+15 Direction of Opening
Vertex/Axis of Symmetry Y intercept X Intercepts Domain Range
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You Try #2: Graph π π₯ =β π₯ 2 +9π₯β20 Direction of Opening
Vertex/Axis of Symmetry Y intercept X Intercepts Domain Range
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Realize: So far everything we have graphed has had two x intercepts! BUT there could be parabolaβs with ONE x intercept!
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Example Five: Graph π π₯ =β4 π₯ 2 +12π₯β9 Direction of Opening
Vertex/Axis of Symmetry Y intercept X Intercepts Domain Range
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Example Six: Graph π π₯ =4 π₯ 2 β4π₯+1 Direction of Opening
Vertex/Axis of Symmetry Y intercept X Intercepts Domain Range
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Example Seven: Graph π π₯ =β π₯ 2 +6π₯β9 Direction of Opening
Vertex/Axis of Symmetry Y intercept X Intercepts Domain Range
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Realize: To get another point, choose an x value close to the vertex and plug it in to get the y value! (x,y) gets you a point!
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Example Eight: Graph π π₯ =9 π₯ 2 +36π₯+36 Direction of Opening
Vertex/Axis of Symmetry Y intercept X Intercepts Domain Range
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You Try #1: Graph π π₯ = π₯ 2 β2π₯+1 Direction of Opening
Vertex/Axis of Symmetry Y intercept X Intercepts Domain Range
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You Try #2: Graph π π₯ =β4 π₯ 2 +24π₯β36 Direction of Opening
Vertex/Axis of Symmetry Y intercept X Intercepts Domain Range
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Do Now: Take out homework packet and complete #6
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Soβ¦. We know how to graph things that have one intercept or TWO x interceptsβ¦. What about NO x intercepts?
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Example Ten: Graph π π₯ = π₯ 2 β4π₯+8 Direction of Opening
Vertex/Axis of Symmetry Y intercept X Intercepts Domain Range
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Example Eleven: Graph π π₯ =β π₯ 2 +5π₯β7 Direction of Opening
Vertex/Axis of Symmetry Y intercept X Intercepts Domain Range
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Example Twelve: Graph π π₯ = 1 2 π₯ 2 +2π₯+9 Direction of Opening
Vertex/Axis of Symmetry Y intercept X Intercepts Domain Range
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Example Thirteen: Graph π π₯ =β2 π₯ 2 β1 Direction of Opening
Vertex/Axis of Symmetry Y intercept X Intercepts Domain Range
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You Try #1: Graph π π₯ =β π₯ 2 +4π₯β5 Direction of Opening
Vertex/Axis of Symmetry Y intercept X Intercepts Domain Range
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You Try #2: Graph π π₯ =β π₯ 2 +4π₯β9 Direction of Opening
Vertex/Axis of Symmetry Y intercept X Intercepts Domain Range
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You Try #3: Graph π π₯ = π₯ 2 +8π₯+15 Direction of Opening
Vertex/Axis of Symmetry Y intercept X Intercepts Domain Range
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Practice Problems Try some on your own/in your table groups
As always donβt hesitate to ask questions if you are confused OR ask your tablematesβ they are your greatest resource!
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