1. Problem Explication Amber Gipson Erin Key Kelly Lee Amy Ozley

2. #64 Calculate ∆H° for each of the following reactions using the data in Appendix 4: 4Na(s) + O2(g)  2Na2O(s) 2Na(s) +2H2O(l)  2NaOH(aq) + H2(g) 2Na(s) + CO2(g)  NA2O(s) + CO(g) Explain why a water or carbon dioxide fire extinguisher might not be effective in putting out a sodium fire.

3. Equation: *Product - Reactant = ΔH*
4Na(s) + O2(g)  2Na2O(s)
4 (0) (-416)
-832 – 0 ΔH= -832
EXOTHERMIC!

4. Equation: *Product - Reactant = ΔH*
2Na(s) +2H2O(l)  2NaOH(aq) + H2(g) (-286) 2(-470) + 0
(-572) ΔH= -368
EXOTHERMIC!

5. Equation: *Product - Reactant = ΔH*
2Na(s) + CO2(g)  NA2O(s) + CO(g)
2 (0)
ΔH=
EXOTHERMIC!

6. Answer: The reaction of water and sodium release heat
Answer: The reaction of water and sodium release heat. The reaction of carbon dioxide and sodium release heat also. They are both exothermic reactions.