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Unit V: The Mole Concept
V.5. Empirical and Molecular Formulae
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Empirical Formula Empirical Formula Simplest Formula
Gives the simplest whole number ratio of elements in a compound
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Molecular Formula Molecular Formula
Gives the ACTUAL number of each kind of atom in a molecule and compound
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Molecular vs. Empirical
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Molecular vs. Empirical
Molecular Formula Empirical Formula P4O10 C10H22 C6H18O3 C5H12O N2O4
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Molecular vs. Empirical
Molecular Formula Empirical Formula P4O10 P2O5 C10H22 C5H11 C6H18O3 C2H6O C5H12O N2O4 NO2
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Finding Empirical Formulas
A sample of an unknown compound is analyzed and found to contain 8.4 g of “C” 2.1 g of “H” and 5.6 g of “O”. Find the empirical formula.
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Finding Empirical Formulas
Element Mass (g) Atomic Mass Moles Sm.Moles Smallest Ratio C H O
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Finding Empirical Formulas
0.888 grams of a compound made up of carbon, hydrogen and oxygen are found to contain g of carbon and g of hydrogen. Find the mass of oxygen Find the empirical formula
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Finding Empirical Formulas
Element Mass (g) Atomic Mass Moles Sm.Moles Smallest Ratio C H O
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Finding Empirical Formulas
A while powder used in paints has the following composition: Ba 69.58% C % O 24.32% Find the Empirical Formula
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Finding Empirical Formulas
Element Mass(g) Atomic Mass Moles Sm.Moles Smallest Ratio Ba C O
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Multiply ALL numbers by…. to get the Smallest Ratio
WHAT HAPPENS WHEN…….. is not near a whole # __ Moles__ smallest moles If ends in a decimal of Multiply ALL numbers by…. to get the Smallest Ratio ≈ 0.5 2 ≈0.33 or ≈0.66 3 ≈0.25 or ≈0.75 4 ≈0.2, ≈0.4, ≈0.6, ≈0.8 5
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Empirical to Molecular Formula
A compound has a molar mass of 60.0g/mol and its empirical formula is CH2O. Find the molecular formula. Empirical Molecular Formula Mass
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Hebden Do Exercises 46 (d, g, & m) on pages 93 & Exercises 48 and 52 on page 95 of Hebden Read through Tutorial 5-1: Percent Mass and Empirical Formulas (Working in Pairs) Do the Self-Test on Tutorial 5-1
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