1. q = CM∆T CALORIMETRY NaOH(aq) + HCl(aq)  NaCl(aq) + H2O(l)
In a coffee cup calorimeter mL of NaOH is mixed with mL of 1.0 molar HCl. Both solutions were at 24.6 C, with the temperature after the reactiojn at 31.3 C. Assuming all the solutions have a density of 1.0 grams/ml, and a heat capacity of 4.18 J/C * g calculate the enthalpy of neutralization for the reaction. Assume 100 efficiency.
NaOH(aq) + HCl(aq)  NaCl(aq) + H2O(l)
q = CM∆T

2. q = CM∆T
200.0mL x 1.0g/ml = 200.0g
q = (4.18 J/gC)(200g)( )
Q= -5.6 X 103 J, -5.6 kJ