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Bond and Lone Pairs Valence electrons are distributed as shared or BOND PAIRS and unshared or LONE PAIRS. • •• H Cl shared or bond pair lone pair (LP)

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Presentation on theme: "Bond and Lone Pairs Valence electrons are distributed as shared or BOND PAIRS and unshared or LONE PAIRS. • •• H Cl shared or bond pair lone pair (LP)"— Presentation transcript:

1 Bond and Lone Pairs Valence electrons are distributed as shared or BOND PAIRS and unshared or LONE PAIRS. •• H Cl shared or bond pair lone pair (LP) This is called a LEWIS structure.

2 Note that each atom has a single, unpaired electron.
Bond Formation A bond can result from an overlap of atomic orbitals on neighboring atoms. Cl H •• + Overlap of H (1s) and Cl (2p) Note that each atom has a single, unpaired electron.

3 Review of Valence Electrons
Remember from the electron chapter that valence electrons are the electrons in the OUTERMOST energy level… that’s why we did all those electron configurations! B is 1s2 2s2 2p1; so the outer energy level is 2, and there are 2+1 = 3 electrons in level 2. These are the valence electrons! Br is [Ar] 4s2 3d10 4p5 How many valence electrons are present?

4 Steps for Building a Dot Structure
Ammonia, NH3 1. Decide on the central atom; never H. Why? If there is a choice, the central atom is atom of lowest affinity for electrons. (Most of the time, this is the least electronegative atom…in advanced chemistry we use a thing called formal charge to determine the central atom. But that’s another story!) Therefore, N is central on this one 2. Add up the number of valence electrons that can be used. H = 1 and N = 5 Total = (3 x 1) + 5 = 8 electrons / 4 pairs

5 Building a Dot Structure
3. Form a single bond between the central atom and each surrounding atom (each bond takes 2 electrons!) H N 4. Remaining electrons form LONE PAIRS to complete the octet as needed (or duet in the case of H). H •• N 3 BOND PAIRS and 1 LONE PAIR. Note that N has a share in 4 pairs (8 electrons), while H shares 1 pair.

6 Building a Dot Structure
Check to make sure there are 8 electrons around each atom except H. H should only have 2 electrons. This includes SHARED pairs. H •• N 6. Also, check the number of electrons in your drawing with the number of electrons from step 2. If you have more electrons in the drawing than in step 2, you must make double or triple bonds. If you have less electrons in the drawing than in step 2, you made a mistake!

7 Carbon Dioxide, CO2 1. Central atom = 2. Valence electrons =
3. Form bonds. C 4 e- O 6 e- X 2 O’s = 12 e- Total: 16 valence electrons This leaves 12 electrons (6 pair). 4. Place lone pairs on outer atoms. 5. Check to see that all atoms have 8 electrons around it except for H, which can have 2.

8 Carbon Dioxide, CO2 C 4 e- O 6 e- X 2 O’s = 12 e- Total: 16 valence electrons How many are in the drawing? 6. There are too many electrons in our drawing. We must form DOUBLE BONDS between C and O. Instead of sharing only 1 pair, a double bond shares 2 pairs. So one pair is taken away from each atom and replaced with another bond.

9 Double and even triple bonds are commonly observed for C, N, P, O, and S
H2CO SO3 C2F4

10 Now You Try One! Draw PH3

11 Sigma () and Pi () bond
sigma bond - direct orbital overlap between the two nuclei. pi bond has orbital overlap off to the sides of the line joining the two nuclei. Sigma bonds are stronger than pi.

12 A single bond has 1 σ bond A double bond has 1 σ bond and 1 π bond. A triple bond has 1 σ bond and 2 π bonds.

13 Lewis structure practice Draw structures for PBr3, N2H2, CH3OH and C2H4

14 Violations of the Octet Rule
Usually occurs with B and elements of higher periods. Common exceptions are: Be, B, P, S, and Xe. Less than 8= sub-octet More than 8= super-octet SF4 Be: 4 B: 6 P: 8 OR 10 S: 8, 10, OR 12 Xe: 8, 10, OR 12 BF3

15 MOLECULAR GEOMETRY

16 VSEPR MOLECULAR GEOMETRY Valence Shell Electron Pair Repulsion theory.
Molecule adopts the shape that minimizes the electron pair repulsions. VSEPR Valence Shell Electron Pair Repulsion theory. Most important factor in determining geometry is relative repulsion between electron pairs.

17 Some Common Geometries
Linear Tetrahedral Trigonal Planar

18 VSEPR charts Use the Lewis structure to determine the geometry of the molecule Electron arrangement establishes the bond angles Molecule takes the shape of that portion of the electron arrangement Charts look at the CENTRAL atom for all data! Think REGIONS OF ELECTRON DENSITY rather than bonds (for instance, a double bond would only be 1 region)

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20 Other VSEPR charts

21 Structure Determination by VSEPR
Water, H2O The electron pair geometry is TETRAHEDRAL 2 bond pairs 2 lone pairs The molecular geometry is BENT.

22 Structure Determination by VSEPR
Ammonia, NH3 The electron pair geometry is tetrahedral. The MOLECULAR GEOMETRY — the positions of the atoms — is TRIGONAL PYRAMID.

23 Structures of PCl5 and SF6
PCl5 – trigonal bi pyramid-only shape with 2 different bond angles SF6- square bipyramid or octahedral

24 Hybridization The orbitals mix to give hybrid orbitals of equal energy. The number of atomic orbitals that mix and form the hybrid orbitals are equal to the total number of electron pairs.

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26 Molecular Models Lab Chemical formulas Lewis Structure
Steric (total) pairs Bond pairs Lone pairs Molecular Geometry(Draw) Hybridization Name of Shape H2 O2 N2 H2O PH3 CF4 CO2 PCl5 HCN BF3

27 Bond Polarity HCl is POLAR because it has a positive end and a negative end. (difference in electronegativity- Cl more elctronegative) Cl has a greater share in bonding electrons than does H. Cl has slight negative charge (-d) and H has slight positive charge (+ d) - polar covalent bond

28 Polar and Non-polar molecules
Bond can be polar but because of symmetry of molecule, polarity cancels out. Ex- CCl4 Bond is polar but molecule is not symmetrical- then molecule stays polar. Ex- H2O Bonds are not polar due to same electronegativity- molecule is nonpolar. Ex- CH4 Pull up Electronegativity chart on your Ipad.

29 Deciding Polarity BONDS SHAPE OVERALL MOLECULE NON-POLAR
SYMMETRICAL OR NOT POLAR SYMMETRICAL ASYMMETRICAL

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31 Electronegativity difference and bond polarity
Bond character >1.7 Mostly ionic Polar covalent <0.4 Mostly covalent Nonpolar covalent

32 Like dissolves like Polar solvents dissolve polar solutes-
Example: Salt in water= Na+ Cl- Non-polar solutes dissolve in nonpolar solvents Example: Oil in CCl4

33 When do things dissolve in each other?
- when the solution is MORE stable or has lower energy compared to the separate solute and solvent! This means that there have to be attractive forces between the solute and solvent.

34 Bond Polarity This is why oil and water will not mix! Oil is nonpolar, and water is polar. The two will repel each other, and so you can not dissolve one in the other

35 Bond Polarity “Like Dissolves Like” Polar dissolves Polar
Nonpolar dissolves Nonpolar

36 Polarity Practice Worksheet
For each of the following pairs, determine which is most polar based on Lewis structure and electronegativity. 1. CHCl3 or CHBr3 2. H2O or H2S 3. HCl or HI 4. C2HBr or C2HCl 5. CH3OH or CH3OCH3 6. CH3C=OCH3 or C3H8O

37 Molecular Bonding Practice
For each of the following molecules: 1. H2S 2. NCl3 3. CHF3 a. Draw the Lewis dot structure and the geometry of the molecule B. Draw the dipoles and determine the overall polarity of the molecule C. What is the hybridization of the central atom? D. Give the number of sigma and pi bonds E. Build the molecule using your model kits.

38 P 375 practice Q11. For each of the following sets of elements, arrange the elements in order of increasing electronegativity- a. Li, F, C b. I, C, F c. Li, Rb, Cs Q13. ON the basis of the electronegativity values given in an EN chart, indicate whether each of the following bonds would be expected to be ionic, covalent or polar covalent- K-N b.Cs-O c. C-N d. O-F Q15. Which of the following molecules contain a 100% polar bond- a. P b. O c. HF

39 P 375 practice contd. Q 17.On the basis of the electronegativity values given in EN chart, indicate which is the more polar bond in each of the following pairs- A. H-F or H-Cl B. H-Cl or H-I C. H-Br or H-Cl D. H-I or H-Br Q 23. IN each of the following diatomic molecules, which end of the molecule is negative relative to the other end? HCl, CO, BrF

40 P 375 practice Q 25. For each of the following bonds, draw a figure indicating the direction of the bond dipole, including which end is positive and which is negative- C-F Si-C C-O B-C

41 Remember: BrINClHOF Diatomic Elements
These elements do not exist as a single atom; they always appear as pairs When atoms turn into ions, this NO LONGER HAPPENS! Hydrogen Nitrogen Oxygen Fluorine Chlorine Bromine Iodine Remember: BrINClHOF

42 IONIC AND COVALENT BONDING TEST – REVIEW TOPICS LIST
1. DEFINITIONS- IONIC AND COVALENT 2. PROPERTIES- IONIC AND COVALENT 3. FORMULAS OF IONIC COMPOUNDS, BINARY, POLYATOMICS 4. CRYSTAL LATTICE 5. LEWIS STRUCTURES- LONE PAIR, BOND PAIR 6. VSEPR THEORY 7. MOLECULAR GEOMETRY 8. DOUBLE AND TRIPLE BONDS- SIGMA ND PI. 9. POLARITY AND DIPOLE.

43 Covalent Review list Covalent bonding- definition and properties
Sigma and pi bonds Octet rule- violations to octet vsepr theory- names of shapes, lewis structures, bond angles Electronegativity/ polarity/ dipoles- solubility


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