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Published byMargaret Patterson Modified over 7 years ago
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Today’s Lecture Forces and Torques Magnetism in Materials Magnetic BCs
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Forces and Torques F = q(v x B) Work done by B fields is zero !!
This is why classical mechanics doesn’t allow magnetism, because magnetic fields don’t change energy of charges! Net force 0
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Different orientation
F = q(v x B) = I∫(dl x B) Net force 0 Torque non 0 T = NIA x B = m x B
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Same as electric fields
T = NIA x B = m x B T = (d/2 x F+) + (d/2 x F+) = qd x E = p x E F+ = qE + - F- = -qE
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Could Force be non-zero on a dipole?
Fx = qEx(dx/2,dy/2) q[Ex(0,0) +(d/2.)Ex] Similarly for Fy Yes – in a spatially varying field (In fact, field gradients are used to collect polar molecules) - + Fx = -qEx(-dx/2,-dy/2) -q[Ex(0,0) - (d/2.)Ex] Similarly for Fy Net force F = (p.)E For magnets F = (m.)B
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So far, we explored the force of an external
field on a dipole. What about the force between two dipoles?
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How do currents interact? (Magnetostatics)
dl1 I1 I2 dl2 R i12 i21 Another current senses it Force ~ i2 x H
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I1 I2 B =(m0I1/2pD)f F = I2 ∫dl x B F/l = -r(m0I1I2/2pD)
Force Between Wires I1 I2 B =(m0I1/2pD)f F = I2 ∫dl x B F/l = -r(m0I1I2/2pD) Parallel currents attract
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+ - + - Force Between Dipoles
From the basic notion that Like charges repel but Parallel currents attract we can derive that El. Dip. Mom. p=qd Magn. Dip. Mom. M=Ia2 + - Parallel, non-collinear dipoles (arrows) repel + - Parallel, collinear dipoles (arrows) attract
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Images X X + - Opposite charges Attract Parallel currents Attract
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Fields in material media
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Dipoles Screen field D E E=(D-P)/e0 rtotal = rfree + rbound
Attracts opposite charges to reduce field E E=(D-P)/e0 Opposing Polarization field Total field External field rtotal = rfree + rbound .D = rfree -.P = rbound .E = rtotal/e0
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What happens near a magnet?
Unmagnetized iron Magnetizing iron
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What happens near a magnet?
Sets up little current loops
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What happens near a magnet?
Only surface currents survive, but they aid rather than oppose the incident H field (because currents attract Parallel currents) M x M = Jbound H
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What happens near a magnet?
So the net field gets augmented B B=m0(H+M) Aiding magnetization field Total field External field H
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Magnetic dipoles augment flux
B=m0(H+M) Aiding magnetization field Total field External field Jtotal = Jfree + Jbound xH = Jfree xB = m0Jtotal x M = Jbound
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Electric vs magnetic fields
E field weaker inside B field stronger inside E = (D-4pP/3)/e0 B = m0(H+2pM/3) Ignore constants, but they Look opposite!
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Effect of material on C and L
- + Q increases to make up for weakening E C goes up C = eA/d Flux increases as field aligns magnetic domains L goes up L = mN2A/l
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Magnetostatic Boundary Condns
Maxwell equations for E Supplement with constitutive relation B=mE .B = 0 x H = J B1n B.dS=0 H.dl = Ifree B2n Use Gauss’ law for a short cylinder Only caps matter (edges are short!) B1n-B2n = 0 Perpendicular B continuous
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Magnetostatic Boundary Condns
Maxwell equations for E Supplement with constitutive relation B=mE .B = 0 x H = J B.dS=0 H.dl = Ifree H1t H2t No net circulation on small loop Only long edges matter (heights are short!) H1t-H2t = 0 Parallel H continuous
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Summary: Main equations
.B = 0 x H = J Differential eqns B.dA = 0 H.dl = I Integral eqns 1st tells us to look for loops 2nd tells us to choose loops cleverly (Ampere’s Law) 1st defines Vector potential B = x A 2nd gives Magnetic Poisson’s equation (.A) - 2A = m0J Choosing reference For A F = q(v x B) Need moving charges to create and detect fields ! B1n-B2n = 0 H1t-H2t = Js Magnetic bcs
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