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Energy Level Arrangements

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Presentation on theme: "Energy Level Arrangements"— Presentation transcript:

1 Energy Level Arrangements
How does one know how many electrons are found in each energy level for a given atom? Here are some simple steps to follow when determining the number of electrons in each energy level. First locate where the element is found in the Periodic Table. To demonstrate here’s how to determine the energy level arrangement for S.

2 Next assign group numbers to the periodic table.
8 1 2 3 4 5 6 7 2 2 2 2 2 2 2 2 2 2 These numbers represent the number of electrons in the last energy level

3 Next assign row numbers.
8 1 2 3 4 5 6 7 1 2 3 2 2 2 2 2 2 2 2 2 2 + 4 5 6 7 These numbers represent the number of energy levels atoms of this element have.

4 and 6 e1- in the last energy level
S has 3 energy levels and 6 e1- in the last energy level 8 1 2 3 4 5 6 7 1 2 3 2 2 2 2 2 2 2 2 2 2 + 4 5 6 7

5 Draw blank lines for each of the energy levels
The number of e1- in the 2nd last energy level is always determined by subtracting the number of e1- already placed from the total number in a S atom. 16 - (2+6) = 16-8 = 8 # of e1- in each level 2 8 6 Energy level # 1 2 3 Here is a Bohr-Rutherford Diagram

6 16S 6e1- 8e1- 2e1- 16 p1+

7 Now it’s your turn. Determine the number of electrons in each energy level for an atom of tin and then construct a Bohr-Rutherford diagram.

8 Next assign row numbers.
8 1 2 3 4 5 6 7 1 2 3 2 2 2 2 2 2 2 2 2 2 4 5 + 6 7 These numbers represent the number of energy levels atoms of this element have.

9 and 4 e1- in the last energy level
Sn has 5 energy levels and 4 e1- in the last energy level 8 1 2 3 4 5 6 7 1 2 3 2 2 2 2 2 2 2 2 2 2 4 5 + 6 7

10 Draw blank lines for each of the energy levels
The number of e1- in the 2nd last energy level is always determined by subtracting the number of e1- already placed from the total number in a Sn atom. 50 - ( ) = = 18 # of e1- in each level 2 8 18 18 4 Energy level # 1 2 3 4 5 Here is a Bohr-Rutherford Diagram

11 4e1- 50Sn 18e1- 18e1- 8e1- 2e1- 50 p1+

12 Now it’s your turn. Determine the energy level arrangements and draw the Bohr Rutherford Diagrams for each of the following: 27Co, 45Rh, 56Ba, 23V.

13 and 2 e1- in the last energy level
Co has 4 energy levels and 2 e1- in the last energy level 8 1 2 3 4 5 6 7 1 2 3 2 2 2 2 2 2 2 2 2 2 4 + 5 6 7

14 Draw blank lines for each of the energy levels
The number of e1- in the 2nd last energy level is always determined by subtracting the number of e1- already placed from the total number in a Co atom (27 - (2+8+2) = = 15 # of e1- in each level 2 8 15 2 Energy level # 1 2 3 4 Here is a Bohr-Rutherford Diagram

15 27Co 2e1- 15e1- 8e1- 2e1- 27 p1+

16 and 2 e1- in the last energy level
Rh has 5 energy levels and 2 e1- in the last energy level 8 1 2 3 4 5 6 7 1 2 3 2 2 2 2 2 2 2 2 2 2 4 5 + 6 7

17 Draw blank lines for each of the energy levels
The number of e1- in the 2nd last energy level is always determined by subtracting the number of e1- already placed from the total number in a Rh atom (45 - ( ) = = 15 # of e1- in each level 2 8 18 15 2 Energy level # 1 2 3 4 5 Here is a Bohr-Rutherford Diagram

18 2e1- 45Rh 15e1- 18e1- 8e1- 2e1- 45 p1+

19 and 2 e1- in the last energy level
Ba has 6 energy levels and 2 e1- in the last energy level 8 1 2 3 4 5 6 7 1 2 3 2 2 2 2 2 2 2 2 2 2 4 5 6 + 7

20 Draw blank lines for each of the energy levels
The number of e1- in the 2nd last energy level is always determined by subtracting the number of e1- already placed from the total number in a Ba atom (56 - ( ) = = 8 # of e1- in each level 2 8 18 18 8 2 Energy level # 1 2 3 4 5 6 Here is a Bohr-Rutherford Diagram

21 2e1- 8e1- 56Ba 18e1- 18e1- 8e1- 2e1- 56 p1+

22 and 2 e1- in the last energy level
V has 4 energy levels and 2 e1- in the last energy level 8 1 2 3 4 5 6 7 1 2 3 2 2 2 2 2 2 2 2 2 2 4 + 5 6 7

23 Draw blank lines for each of the energy levels
The number of e1- in the 2nd last energy level is always determined by subtracting the number of e1- already placed from the total number in a Va atom (23 - (2+8+2) = = 11 # of e1- in each level 2 8 11 2 Energy level # 1 2 3 4 Here is a Bohr-Rutherford Diagram

24 23V 2e1- 11e1- 8e1- 2e1- 27 p1+

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