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Welcome to Week 6 College Trigonometry
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Polar Coordinates We know about square graph paper
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Polar Coordinates Now we’re going to learn about circular graph paper!
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Polar Coordinates In the 700s and 800s AD, Arabic astronomers developed methods for calculating the direction and distance to Meccah from any point on Earth
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Polar Coordinates They were using spherical trigonometry to do this
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Polar Coordinates Just like with square graph paper, polar graph paper has a starting point
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Polar Coordinates For square graph paper, this point is called the origin For polar graph paper, it is called the pole
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Polar Coordinates Just like square graph paper, the starting position is the right horizontal line
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Polar Coordinates This is called the “polar axis”
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Polar Coordinates The rotation for both square and polar graphs is counterclockwise II I III IV
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Polar Coordinates Just like for (x,y) coordinates, there are a pair of polar coordinates (r,θ) These are called the “polar coordinates”
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Polar Coordinates r is the distance from the pole (the radius) θ is the angle around the circle
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Polar Coordinates Angles in polar notation can be expressed in either degrees or radians
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Polar Coordinates Degrees are traditionally used in navigation, surveying, and many applied disciplines Radians are more common in mathematics and mathematical physics
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Polar Coordinates point P = (r,θ) r is the distance (radius) from the pole to P (+,- or 0) θ is the angle from the polar axis to the terminal side of the angle (degrees or radians)
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Polar Coordinates Positive angles are measured counterclockwise from the polar axis Negative angles are measured clockwise from the polar axis
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Polar Coordinates P = (r, θ) is located | r | units from the pole
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Polar Coordinates r > 0 – the point lies on the terminal side of θ r < 0 - point lies along the ray opposite the terminal side of θ r = 0 the point lies on the pole no matter what the value of θ is!
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As usual, it’s easier to DO it than to explain it!
Polar Coordinates As usual, it’s easier to DO it than to explain it!
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Plot (2,135º) Begin with the angle θ = 135º:
Polar Coordinates IN-CLASS PROBLEMS Plot (2,135º) Begin with the angle θ = 135º:
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Polar Coordinates IN-CLASS PROBLEMS Because the angle is positive, the point will be along this line It will be r=2 radii from the pole
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Polar Coordinates IN-CLASS PROBLEMS Plot (-3,270º)
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Polar Coordinates IN-CLASS PROBLEMS Plot (-3,270º)
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Polar Coordinates IN-CLASS PROBLEMS Plot (-3,270º)
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Polar Coordinates IN-CLASS PROBLEMS Plot (-1,-45º)
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Polar Coordinates IN-CLASS PROBLEMS Plot (-1,-45º)
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Polar Coordinates IN-CLASS PROBLEMS Plot (-1,-45º)
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Check Point 1 page 685 Plot the points: (3,315º) (–2,π) (–1,–π/2)
Polar Coordinates IN-CLASS PROBLEMS Check Point 1 page 685 Plot the points: (3,315º) (–2,π) (–1,–π/2)
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Polar Coordinates Polar to rectangular conversion If you have a polar point P = (r,θ) To convert to (x,y) coordinates: x = r cos θ y = r sin θ
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Polar Coordinates IN-CLASS PROBLEMS x = r cos θ y = r sin θ Find the rectangular coordinates: a) P = (3,π) b) P = (-10,π/6) What quadrant is each in?
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Polar Coordinates Rectangular to polar coordinates r = 𝒙 𝟐 + 𝒚 𝟐 θ = arctan (y ÷ x)
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Polar Coordinates IN-CLASS PROBLEMS r = 𝒙 𝟐 + 𝒚 𝟐 θ = arctan (y ÷ x) Find the polar coordinates of: (x,y) = (1, – 𝟑 ) (x,y) = (0, – 4)
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Questions?
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Polar Equations Polar equations have variables r and θ
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Polar Equations Converting rectangular equations to polar equations: replace x with r cosθ and y with r sinθ
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Polar Equations Converting polar equations to rectangular equations: try r 2 = x2 + y2 r cosθ = x r sinθ = y tanθ = y/x
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Polar Equations This is not easy – you may have to square both sides, take the tangent of both sides, multiply both sides by r
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Polar Equations People actually use polar equations for real work… But mostly you graph them because they change a ho-hum rectangular graph to a really interesting polar graph
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Polar Equations
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Polar Equations
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Polar Equations Spiral of Archimedes r = aθ
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Polar Equations
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Polar Equations
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Polar Equations Video: Polar Graphs graph of r = cos(2θ)
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Questions?
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Complex Plane Remember the imaginary unit i i = −1
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Complex Plane Remember we didn’t allow any exponents when using i i = −1 i 2 = -1
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Complex Plane i = −1 i 2 = -1 i 3 = - i i 4 = 1 i 5 = i
You can keep on going: i = −1 i 2 = -1 i 3 = - i i 4 = 1 i 5 = i
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But, that pattern formed a complete cycle, and you can keep cycling forever!
i 7 = - i i 8 = 1 i 9 = i …
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Complex Plane Remember complex #s: z = a + bi
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Complex Plane real #s are points on the real # line
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Complex Plane complex numbers can be plotted as points on the “complex plane”: real axis (horizontal) and an imaginary axis (vertical)
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Complex Plane Check Point 1 page 707 Plot: a) z = 2 + 3i b) z = i c) z = -4 d) z = -i
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Complex Plane Fractals/Mandelbrot sets Graphing complex numbers
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Complex Plane Video: Fractals
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Questions?
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Using Complex Numbers More complex numbers!
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Using Complex Numbers Remember the absolute value |x| is the distance between x and 0:
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Using Complex Numbers But absolute value is not what we usually use to calculate a distance because it only works for horizontal or vertical distances along an axis
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Using Complex Numbers √
d = (y2 – y1)2 + (x2 – x1)2 is the formula used to calculate distances “d” in virtually all technical equations
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Using Complex Numbers This is based on the Pythagorean Theorem
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Using Complex Numbers So, an absolute value and a square root of a sum of squares are really both a measure of distance (and hence, the same thing)
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Using Complex Numbers √
We can calculate the absolute value of a complex number z = a + bi as: |z| = |a + b i| = a2 + b2 √
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Using Complex Numbers Check Point 2 page 708 Find the absolute value of: a) z = i b) z = 2 - 3i
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Using Complex Numbers Polar form of a complex number: z = a + bi becomes: z = r (cos θ + i sin θ ) where a = r cos θ b = r sin θ r = a 2 + b 2 tan θ = b/a
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Using Complex Numbers r is called the modulus θ is called the argument
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Using Complex Numbers Always plot these first or you may end up in the wrong quadrant! (This is because of the tan)
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Using Complex Numbers Example 3 page 708 Plot z = -2 – 2i in the complex plane then write z in polar form
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Using Complex Numbers z = -2 – 2i z = a + bi a = ? b = ?
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Using Complex Numbers z = -2 – 2i z = a + bi a = -2 b = -2 Plot?
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Using Complex Numbers z = -2 – 2i So it’s in quadrant 3 r = ? Θ = ?
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Using Complex Numbers z = -2 – 2i in quadrant 3 a = -2 b = -2
= 8 = 2 2 Θ = ?
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Using Complex Numbers z = -2 – 2i in quadrant 3 a = -2 b = -2
tanΘ = b/a = -2/-2 So tan-1(1) = Θ
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Using Complex Numbers z = -2 – 2i in quadrant 3 a = -2 b = -2
If tan-1(1) = Θ (use your table!) then Θ = π/4 or 5π/4 Which?
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Using Complex Numbers z = -2 – 2i in quadrant 3 a = -2 b = -2
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Using Complex Numbers z = -2 – 2i Θ = 5π/4 SO what is:
z = r (cos θ + i sin θ)
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Using Complex Numbers z = -2 – 2i Θ = 5π/4 SO:
z = (cos 5π/4 + i sin 5π/4)
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Using Complex Numbers Rectangular form of a complex number (You don’t have to plot these first!)
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Using Complex Numbers Example 4 on page 709 Write z = 2(cos(60o) + i sin(60o)) in rectangular form
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z = 2(cos(60o) + i sin(60o)) would mean: r = 2 Θ = 60 o
Using Complex Numbers z = 2(cos(60o) + i sin(60o)) would mean: r = 2 Θ = 60 o
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Using Complex Numbers Write z = 2(cos(60o) + i sin(60o)) r = 2 Θ = 60 o z = 2(1/2 + i 𝟑 /2) z = 1 + 𝟑 i
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Questions?
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DeMoivre’s Theorem Powers of complex numbers in polar form
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DeMoivre’s Theorem the power of a complex number z = r (cos θ + i sin θ ) For n>0 zn = [r (cos θ + i sin θ )] n = rn(cos nθ + i sin nθ )
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DeMoivre’s Theorem Example 7 page 712 Find [2(cos 20° + i sin 20°)]6
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DeMoivre’s Theorem [2(cos 20° + i sin 20°)]6 zn = [r (cos θ + i sin θ )] n So, what is n? What is r? What is θ?
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DeMoivre’s Theorem [2(cos 20° + i sin 20°)]6 zn = [r (cos θ + i sin θ )] n n = 6 r = 2 θ = 20° yay! No radians!
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DeMoivre’s Theorem n = 6 r = 2 θ = 20° zn = rn(cos nθ + i sin nθ ) = 26(cos 6(20°) + i sin 6(20°))
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DeMoivre’s Theorem = 64 (cos 120° + i sin 120°) = 64(-1/2 + i 3 /2) = i 3
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DeMoivre’s Theorem Check Point 7 page 712 Find [2(cos 30° + i sin 30°)]5
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DeMoivre’s Theorem Example 8 page 712 Find (1 + i)8 z = a + bi a = ? b = ?
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DeMoivre’s Theorem Example 8 page 712 Find (1 + i)8 z = a + bi a = 1 b = 1
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DeMoivre’s Theorem (1 + i)8 a = 1 b = 1 Which quadrant?
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DeMoivre’s Theorem (1 + i)8 Quadrant 1 a = 1 b = 1 r = a 2 + b 2 = ?
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DeMoivre’s Theorem (1 + i)8 Quadrant 1 a = 1 b = 1 r = a 2 + b 2 = = 2 tan Θ = b/a = ?
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DeMoivre’s Theorem (1 + i)8 Quadrant 1 a = 1 b = 1 r = a 2 + b 2 = = 2 tan Θ = b/a = 1/1 = 1 and Θ = π/4 or 45° because Θ is in Quadrant 1
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DeMoivre’s Theorem (1 + i )8 r = a 2 + b 2 = = 2 Θ = π/4 or 45° 1 + i = r(cos Θ + i sin Θ) = 2 (cos π/4 + i sin π/4)
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DeMoivre’s Theorem Use DeMoivre to raise it to the power 8: (1 + i)8 = [ 2 (cos π/4 + i sin π/4)]8 = ( 2 )8(cos 8*π/4 + i sin 8*π/4) = 16(cos 2π + i sin 2π) = 16(1 + 0 i ) = i or 16
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DeMoivre’s Theorem Check Point 8 page 713 Find (1 + i )4
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Questions?
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Liberation! Be sure to turn in your assignments from last week to me before you leave Don’t forget your homework due next week! Have a great rest of the week!
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