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Polynomial Division
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Long Division
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A. 2x3y – 3x5y2 B x3y – 3x5y2 C. 6x4y2 + 9x7y3 – 6x9y4 D x7y3 – 3x9y4
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Division Algorithm f(x) = d(x) * q(x) + r(x)
Dividend=divisor*quotient+remainder If r(x) = 0, the d(x) divides evenly into f(x)
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Division Algorithm x(x – 5) = x2 – 5x –2x – (5x) = 3x
Use long division to find (x2 – 2x – 15) ÷ (x – 5). 3(x – 5) = 3x – 15 x(x – 5) = x2 – 5x –2x – (5x) = 3x Answer: The quotient is x + 3. The remainder is 0.
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Polynomial Division Divide by x – 2
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Polynomial Division
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Quotient with Remainder
Which expression is equal to (a2 – 5a + 3)(2 – a)–1? A a + 3 B C D
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Examples by
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Synthetic Division Use synthetic division to find (x3 – 4x2 + 6x – 4) ÷ (x – 2). Step 1 Write the terms of the dividend so that the degrees of the terms are in descending order. Then write just the coefficients as shown. x3 – 4x2 + 6x – 4 1 – 4 6 – 4 Step 2 Write the constant r of the divisor x – r to the left. In this case, r = 2. Bring the first coefficient, 1, down as shown. 1 – 4 6 – 4 1
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Synthetic Division 1 1 –4 6 – 4 2 –2 2 –2 1 1 –4 6 – 4
Step 3 Multiply the first coefficient by r : 1 ● 2 = 2. Write the product under the second coefficient. Then add the product and the second coefficient. 1 1 –4 6 – 4 2 –2 2 –2 1 1 –4 6 – 4 Step 4 Multiply the sum, –2, by r : 2(–2) = –4. Write the product under the next coefficient and add: (–4) = 2. –4 2
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Synthetic Division –2 1 2 –4 1 –4 6 – 4 4 2
Step 5 Multiply the sum, 2, by r : 2(2) = 4. Write the product under the next coefficient and add: –4 + 4 = 0. The remainder is 0. –2 1 2 –4 1 –4 6 – 4 4 2 The numbers along the bottom are the coefficients of the quotient. Start with the power of x that is one less than the degree of the dividend. Answer: The quotient is x2 – 2x + 2.
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Example Use synthetic division to find (x2 + 8x + 7) ÷ (x + 1).
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Divide by x + 3
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Now it’s your turn! Divide
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Divisor with First Coefficient Other than 1
Use synthetic division to find (4y4 – 5y2 + 2y + 4) ÷ (2y – 1). Use division to rewrite the divisor so it has a first coefficient of 1. Divide numerator and denominator by 2. Simplify the numerator and denominator.
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Finish the example
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Remainder Theorem If a polynomial f(x) is divided by x – k, then the remainder is r = f(k) Find the remainder of divided by x + 2
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Factor Theorem A polynomial f(x) has a factor (x – k) if and only if f(k) = 0. Completely Factor if (x + 4) is a factor.
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Example Completely Factor
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