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Find Holes and y – intercepts
Rational Functions Find Holes and y – intercepts Holt McDougal Algebra 2 Holt Algebra 2
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Consider the rational function
f(x) = (x – 3)(x + 2) x + 1 The numerator of this function is 0 when x = 3 or x = –2. Therefore, the function has x-intercepts at –2 and 3. The denominator of this function is 0 when x = –1. As a result, the graph of the function has a vertical asymptote at the line x = –1.
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For any simplified rational function, what information can you obtain from the numerator?
If you set the numerator = to 0, you determine the x-intercepts (zeros, solutions, roots).
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Let’s find y-intercepts
To find the y-intercept, what do we do? We set the x-value to 0 and solve for y. This is easy…lets look.
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Let’s do what we learned yesterday and find the y-intercept.
x2 – 3x – 4 X + 2 f(x) = Step 1 – Always factor if possible.
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Step 2 – Find the x-intercepts.
x2 – 3x – 4 X + 2 f(x) = Step 2 – Find the x-intercepts. (x – 4)(x + 1) X + 2 2 - x = 4 x= -1
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Step 3 – Find the vertical asymptotes.
x2 – 3x – 4 X + 2 f(x) = Step 3 – Find the vertical asymptotes. x = -2
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Step 4 – Find the y-intercept. Let x = 0.
x2 – 3x – 4 X + 2 f(x) = Step 4 – Find the y-intercept. Let x = 0. – 4 = -2 + 2 f(x) =
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Try another. Find everything. Remember to factor first!!
f(x) =
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But there is a slant asymptote.
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Slant Asymptotes Slant asymptotes occur when the degree of the numerator is exactly one bigger than the degree of the denominator. In this case a slanted line (not horizontal and not vertical) is the function’s asymptote. To find the equation of the asymptote we need to use long division – dividing the numerator by the denominator.
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When dividing to find slant asymptotes:
Do synthetic division (if possible); if not, do long division! The resulting polynomial (ignoring the remainder) is the equation of the slant asymptote.
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EXAMPLE: Finding the Slant Asymptote of a Rational Function
Rational Functions and Their Graphs EXAMPLE: Finding the Slant Asymptote of a Rational Function Find the slant asymptotes of f (x) = Solution Because the degree of the numerator, 2, is exactly one more than the degree of the denominator, 1, the graph of f has a slant asymptote. To find the equation of the slant asymptote, divide x - 3 into x2 - 4x - 5: 3 Remainder more
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EXAMPLE: Finding the Slant Asymptote of a Rational Function
3.6: Rational Functions and Their Graphs EXAMPLE: Finding the Slant Asymptote of a Rational Function Find the slant asymptotes of f (x) = Solution The equation of the slant asymptote is y = x - 1. Using our strategy for graphing rational functions, the graph of f (x) = is shown. -2 -1 4 5 6 7 8 3 2 1 -3 Vertical asymptote: x = 3 Slant asymptote: y = x - 1
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Graph: Notice that in this function, the degree of the numerator is larger than the denominator. Thus n>m and there is no horizontal asymptote. However, if n is one more than m, the rational function will have a slant asymptote. To find the slant asymptote, divide the numerator by the denominator: The result is We ignore the remainder and the line is a slant asymptote.
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1st, find the vertical asymptote.
Graph: 1st, find the vertical asymptote. 2nd , find the x-intercepts: and 3rd , find the y-intercept: 4th , find the horizontal asymptote. none 5th , find the slant asymptote: 6th , sketch the graph.
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A Rational Function with a Slant Asymptote
Graph the rational function Factoring:
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A Rational Function with a Slant Asymptote
Finding the x-intercepts: –1 and 5 (from x + 1 = 0 and x – 5 = 0) Finding the y-intercepts: 5/3 (because )
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A Rational Function with a Slant Asymptote
Finding the horizontal asymptote: None (because degree of numerator is greater than degree of denominator) Finding the vertical asymptote: x = 3 (from the zero of the denominator)
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A Rational Function with a Slant Asymptote
Finding the slant asymptote: Since the degree of the numerator is one more than the degree of the denominator, the function has a slant asymptote. Dividing, we obtain: Thus, y = x – 1 is the slant asymptote.
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A Rational Function with a Slant Asymptote
Here are additional values and the graph.
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Slant Asymptotes and End Behavior
So far, we have considered only horizontal and slant asymptotes as end behaviors for rational functions. In the next example, we graph a function whose end behavior is like that of a parabola.
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Finding a Slant Asymptote
If There will be a slant asymptote because the degree of the numerator (3) is one bigger than the degree of the denominator (2). Using long division, divide the numerator by the denominator.
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Finding a Slant Asymptote Con’t.
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Finding a Slant Asymptote Con’t.
We can ignore the remainder The answer we are looking for is the quotient and the equation of the slant asymptote is
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Graph of Example 7 The slanted line y = x + 3 is the slant asymptote
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Cwk/Hwk Same worksheet as before. Find
y-intercepts and horizontal asymptotes and them to your graphs.
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