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Extended Do Now

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Presentation on theme: "Extended Do Now "β€” Presentation transcript:

1 Extended Do Now 𝒙 πŸ‘ βˆ’ 𝒙 𝟐 βˆ’πŸ—π’™+πŸ— βˆ’ 𝒙 πŸ’ +πŸπŸ“ 𝒙 𝟐 𝟐 𝒙 𝟐 π’™βˆ’πŸ πŸ‘ (𝒙+𝟐)
For the following: Using the LCT to determine the graph’s end behavior. Find x-intercepts. State whether the graph crosses or bounces at the x-axis. Find the y-intercept. If necessary, find a few additional points and graph the function. Use turning points to check your drawing. 𝒙 πŸ‘ βˆ’ 𝒙 𝟐 βˆ’πŸ—π’™+πŸ— βˆ’ 𝒙 πŸ’ +πŸπŸ“ 𝒙 𝟐 𝟐 𝒙 𝟐 π’™βˆ’πŸ πŸ‘ (𝒙+𝟐) βˆ’ 𝒙 πŸ‘ 𝒙+πŸ’ 𝟐 (π’™βˆ’πŸ)

2 Yesterday’s Quiz Results

3 Dividing Polynomials 7/11/13

4 Division Describe, in the most detail possible, what division is. Some important vocab to use is: Dividend Divisor Quotient Remainder

5 Divide – NO CALCULATOR πŸ—πŸ” Γ·πŸ”= πŸ—πŸ“πŸ• πŸ‘πŸ‘ = πŸ”πŸ“πŸ’ Γ·πŸ‘πŸ= 4) 𝟐,πŸ–πŸ‘πŸ‘ ÷𝟏𝟐=
5) πŸ’πŸ”,πŸŽπŸŽπŸ‘ Γ·πŸπŸ‘πŸ 6) πŸ“πŸŽπŸ—,πŸ”πŸ•πŸ πŸπŸ—

6 Dividing Polynomials Divide 𝒙 𝟐 +πŸπŸŽπ’™+𝟐𝟏 by 𝒙+πŸ‘

7 Dividing Polynomials Divide 𝒙 𝟐 +πŸπŸ’π’™+πŸ’πŸ“ by 𝒙+πŸ—

8 Dividing Polynomials Divide πŸ’βˆ’πŸ“π±βˆ’ 𝐱 𝟐 +πŸ” 𝒙 πŸ‘ by πŸ‘π’™βˆ’πŸ

9 Dividing Polynomials Divide πŸ•βˆ’πŸπŸπ±βˆ’ πŸ‘π± 𝟐 +𝟐 𝒙 πŸ‘ by π’™βˆ’πŸ‘

10 Dividing Polynomials Divide (𝒙 πŸ’ βˆ’πŸ–π’™+𝟐𝟐)Γ·(π’™βˆ’πŸ’)

11 Practice P. 350 #1-16

12 The Remainder Theorem If the polynomial 𝒇(𝒙) is divided by π’™βˆ’π’„, then the remainder is 𝒇(𝒄). The following example shows that we can use the Remainder Theorem to evaluate a polynomial function at 2. Rather then substituting 2 for x, we divide the function by x-2. The remainder is f(2). Given 𝒇 𝒙 = 𝒙 πŸ‘ βˆ’πŸ’ 𝒙 𝟐 +πŸ“π’™+πŸ‘, use the RT to find 𝒇 𝟐 .

13 The Remainder Theorem Given 𝒇 𝒙 =πŸ‘ 𝒙 πŸ‘ +πŸ’ 𝒙 𝟐 βˆ’πŸ“π’™+πŸ‘, use the RT to find 𝒇 βˆ’πŸ’ .

14 Practice P. 350, #33-40 Use Remainder Theorem, then divide to check your answers.

15 Harkness Discussion

16 Exit Slip Quiz Good luck!


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