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9.8 Probability Basic Concepts
An experiment has one or more outcomes. The outcome of rolling a die is a number from 1 to 6. The sample space is the set of all possible outcomes for an experiment. The sample space for a dice roll is {1, 2, 3, 4, 5, 6}. Any subset of the sample space is called an event. The event of rolling an even number with one roll of a die is {2, 4, 6}.
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9.8 Probability Probability of an Event E
In a sample space with equally likely outcomes, the probability of an event E, written P(E), is the ratio of the number of outcomes in sample space S that belong to E, n(E), to the total number of outcomes in sample space S, n(S). That is,
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9.8 Finding Probabilities of Events
Example A single die is rolled. Give the probability of each event. (a) E3 : the number showing is even (b) E4 : the number showing is greater than 4 (c) E5 : the number showing is less than 7 (d) E6 : the number showing is 7
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9.8 Finding Probabilities of Events
Solution The sample space S is {1, 2, 3, 4, 5, 6} so n(S) = 6. (a) E3 = {2, 4, 6} so (b) E4= {5, 6} so
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9.8 Finding Probabilities of Events
Solution (c) E5 = {1, 2, 3, 4, 5, 6} so (b) E6 = Ø so
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9.8 Probability For an event E, P(E) is between 0 and 1 inclusive.
An event that is certain to occur always has probability 1. The probability of an impossible event is always 0.
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9.8 Complements and Venn Diagrams
The set of all outcomes in a sample space that do not belong to event E is called the complement of E, written E´. If S = {1, 2, 3, 4, 5, 6} and E = {2, 4, 6} then E´ = {1, 3, 5}.
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9.8 Complements and Venn Diagrams
Probability concepts can be illustrated with Venn diagrams. The rectangle represents the sample space in an experiment. The area inside the circle represents event E; and the area inside the rectangle but outside the circle, represents event E´.
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9.8 Using the Complement Example A card is drawn from a well-shuffled
deck, find the probability of event E, the card is an ace, and event E´. Solution There are 4 aces in the deck of 52 cards and 48 cards that are not aces. Therefore
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9.8 Odds The odds in favor of an event E are expressed as the
ratio of P(E) to P(E´) or as the fraction
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9.8 Finding Odds in Favor of an Event
Example A shirt is selected at random from a dark closet containing 6 blue shirts and 4 shirts that are not blue. Find the odds in favor of a blue shirt being selected. Solution E is the event “blue shirt is selected”.
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9.8 Finding Odds in Favor of an Event
Solution The odds in favor of a blue shirt are or 3 to 2.
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9.8 Probability Probability of the Union of Two Events
For any events E and F,
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9.8 Finding Probabilities of Unions
Example One card is drawn from a well-shuffled deck of 52 cards. What is the probability of each event? (a) The card is an ace or a spade. (b) The card is a 3 or a king.
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9.8 Finding Probabilities of Unions
Solution (a) P(ace or space) = P(ace) + P(spade) – P(ace and spade) (b) P(3 or K) = P(3) + P(K) – P(3 and K)
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9.8 Probability Properties of Probability 1.
2. P(a certain event) = 1; 3. P(an impossible event) = 0; 4. 5.
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9.8 Binomial Probability An experiment that consists of
repeated independent trials, only two outcomes, success and failure, in each trial, is called a binomial experiment.
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9.8 Binomial Probability Let the probability of success in one trial be p. Then the probability of failure is 1 – p. The probability of r successes in n trials is given by
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9.8 Finding Binomial Probabilities
Example An experiment consists of rolling a die 10 times. Find the probability that exactly 4 tosses result in a 3. Solution Here , n = 10 and r = 4. The required probability is
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