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ME 475/675 Introduction to Combustion
Lecture 9 Textbook’s computer programs: HPFLAME, TPEQUIL, Example 2.8
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Announcements HW 3 due now Midterm 1
(two weeks from today) HW 4 Due Monday, September 21, 2015 Ch 2 (33, 35, 47, 50, 54, 57, 63) ABET PEV: Dr. Sriram Somasundaram at 9:30
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Computer Programs Provided by Book Publisher
Described in Appendix F (pp 113-4) For “complex” reactions (11 product species) Fuel: CNHMOLNK Oxidizer: Air Download from web: student edition Computer codes Access to TPEquil, HFFlame, UVFlame Extract All
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TPEQUIL (TP Equilibrium)
Use to find Equilibrium composition and mixture properties Required input Fuel CNHMOLNK Temperature Pressure Equivalence ratio (with air) to determine initial number of moles of each atom
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Input file Equil. Calc. for Specified Fuel, Phi, T, & P Using Olikara/Borman Code 1 /NUMBER OF CARBON ATOMS IN FUEL MOLECULE 4 /NUMBER OF HYDROGEN ATOMS IN FUEL MOLECULE 0 /NUMBER OF OXYGEN ATOMS IN FUEL MOLECULE (NOT AIR) 0 /NUMBER OF NITROGEN ATOMS IN FUEL MOLECULE (NOT AIR) .9 /EQUIVALENCE RATIO, PHI /TEMPERATURE, T(K) /PRESSURE, P(Pa)
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Output File The mole fractions of the product species are: H: O: N: H2: OH: CO: NO: O2: H2O: CO2: N2: Above properties printed below in a column for cut & paste: E+06 E+04 E+01 E+02 E-01 E-06 E-05 E-11 E-04 E-03 E-04 E-03 E-01 E+00 E-01 E+00 Equil. Calc. for Specified Fuel, Phi, T, & P Using Olikara/Borman Code Data below are as read from the input file. Compare with INPUT.TP. If they do not agree, your input data have not been entered correctly. CARBON ATOMS HYDROGEN ATOMS OXYGEN ATOMS NITROGEN ATOMS EQUIVALENCE RATIO TEMPERATURE (K) PRESSURE (Pa) CALCULATED COMBUSTION PRODUCTS PROPERTIES Mixture Enthalpy [J/kg] = E+06 Mixture Specific Heat, Cp [J/kg-K] = E+04 Specific Heat Ratio, Cp/Cv = Mixture Molecular Weight [kg/kmol] = Moles of Fuel per Mole of Products =
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HPFLAME (HP Flame) Use to find Required Input
Adiabatic flame temperature for constant pressure Required Input Fuel, equivalence ratio, enthalpy of reactants HR, pressure For constant pressure: HP = HR Find TAd In our initial examples we assume ideal combustion so we knew the product composition But this program calculates the more realistic equilibrium composition of the products from a (complex) equilibrium calculation (multiple equilibrium reactions) But this requires TProd = TAd, which we are trying to find! Requires program (not humans) to iterate
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Input File Adiabatic Flame Calculation for Specified Fuel, Phi, P, & Reactant Enthalpy Using Olikara & Borman Equilibrium Routines Problem Title: USER SPECIFIES TITLE HERE /CARBON ATOMS IN FUEL /HYDROGEN ATOMS IN FUEL /OXYGEN ATOMS IN FUEL /NITROGEN ATOMS IN FUEL /EQUIVALENCE RATIO /TEMPERATURE (K) (Initial Guess) /PRESSURE (Pa) /ENTHALPY OF REACTANTS PER KMOL FUEL (kJ/kmol-fuel)
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Output File The mole fractions of the product species are:
H: O: N: H2: OH: CO: NO: O2: H2O: CO2: N2: Above properties printed below in a column for cut & paste: E+04 E+06 E+04 E+01 E+02 E+00 E-03 E-04 E-07 E-01 E-02 E-01 E-03 E-03 E+00 E-01 E+00 Adiabatic Flame Calculation for Specified Fuel, Phi, P, & Reactant Enthalpy Using Olikara & Borman Equilibrium Routines Problem Title: USER SPECIFIES TITLE HERE Data below are as read from the input file. Compare with INPUT.HP. If they do not agree, your input data have not been entered correctly. CARBON ATOMS HYDROGEN ATOMS OXYGEN ATOMS NITROGEN ATOMS EQUIVALENCE RATIO TEMPERATURE (K) guess PRESSURE (Pa) ENTHALPY OF REACTANTS (kJ/kmol fuel) FLAME TEMP. & COMBUSTION PRODUCTS PROPERTIES Flame Temperature [K] = Mixture Enthalpy [J/kg] = E+06 Mixture Specific Heat, Cp [J/kg-K] = E+04 Specific Heat Ratio, Cp/Cv = Mixture Molecular Weight [kg/kmol] = Moles of Fuel per Mole of Products =
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Example 2.8, Page 54 A recuperator (heat exchanger) is employed in a natural-gas-fired heat-treating furnace. The furnace operates at atmospheric pressure with an equivalence ratio of The fuel gas enters the burner at 298 K, and the air is preheated. (a) Determine the effect of air preheat on the adiabatic temperature of the flame zone for a range of inlet air temperatures from 298 to 1000 K. (b) What fuel savings results from preheating the air from 298 to 600 K? Assume that the temperature of the flue gases at the furnace exit, prior to entering the recuperator, is K, both with and without air preheat.
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