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Chem. 1B – 11/3 Lecture
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Announcements I Mastering – Ch. 18 assignment due 11/12
Lab – next week Doing Experiment 9 (thermodynamics – lnK vs. 1/T plots) and 10 (electrochemistry) Experiment 8 due Wed./Thurs. Quiz on Exp. 8 and 9 and on electrochemistry
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Announcements III Today’s Lecture Electrochemistry
Standard Cell Potentials Oxidizing and Reducing Agents Acid Oxidation of Metals Charge and Energy in Voltaic Cells Relationship between DG° and E ° The Nernst Equation (for non-standard conditions)
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Chapter 18 Electrochemistry
Example Question An Ag/AgCl electrode is a common reference electrode. What is the standard potential of a cell made up of a Cu2+ solution being reduced to Cu(s) and AgCl(s) being reduced to Ag(s)? E°(Cu2+ + 2e- ↔ Cu(s)) = 0.34 V E°(AgCl(s) + e- ↔ Ag(s) + Cl- (aq)) = 0.22 V What is the balanced reaction and what species must be present at 1 M?
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Chapter 18 Electrochemistry
Oxidizing/Reducing Agents Compounds with large positive or negative E° (standard reduction) values are frequently used in electrochemistry (or in redox titrations) Example: MnO4- - E° (MnO4-(aq) + 8H+(aq) + 5e-) = 1.51 V is frequently used in redox titrations Why? Because if E° is high, it strongly reduces, which makes it useful for oxidizing a wide variety of compounds (e.g. Cu(s)) Such a compound is called an oxidizing agent (oxidizes other compounds)
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Chapter 18 Electrochemistry
Oxidizing/Reducing Agents – cont. Products of reduction reactions with large negative E° values (e.g. Li(s), K(s)) are easily oxidized and can therefore reduce other compounds Example: Al(s) - E° (Al3+(aq) + 3e-) = V is capable of reducing transition metals (reaction with iron oxide is in thermite reaction)
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Chapter 18 Electrochemistry
Reduction Potential and Oxidation of Metals by Acids Just as we can see which metals will oxidize or reduce when pairing two metals (Ag/Cu example), we also can see which metals will react in acid to produce H2(g) Metals with E° (standard reduction) < 0 will react with H+ Examples: Fe, Pb, Sn, Ni, Cr, Zn, Al Metals with E° (standard reduction) > 0 will not react with acid (except with HNO3 which is a stronger oxidizing agent) – Cu, Ag, Au, Hg
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Chapter 18 Electrochemistry
Reducing Potential Questions Given the table below, which of the following oxidizing agents is strong enough to oxidize Ag(s) to Ag+(aq) (under standard conditions)? H+(aq) b) Co2+(aq) c) Cu2+(aq) d) Co3+(aq) e) Br2(l) Reaction Eº (V) Ag+(aq) + e- ↔ Ag(s) +0.799 Co2+(aq) + 2e- ↔ Co(s) -0.277 Cu2+(aq) + 2e- ↔ Cu(s) +0.337 Co3+(aq) + e- ↔ Co2+(aq) +1.808 Br2(l) + 2e- ↔ 2Br- (aq) +1.065
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Chapter 18 Electrochemistry
Relating Standard Potential to Free Energy Two measures of the usefulness of a battery (voltaic cell) are: potential (voltage) supplied and charge stored The combination of these two give the energy stored for electrical work Stored charge (allows one to calculate lifetime under given current load) = q = nF where n = moles of e- (involved in balanced chemical equation) and F = Faraday’s constant F = charge of a mole of electrons = NA*qelectron = (6.02 x 1023 e’s/mol e)(1.60 x C/e) = 96,485 C/mol e
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Chapter 18 Electrochemistry
Relating Standard Potential to Free Energy – cont. Since we know that potential is energy per charge, we can also determine that energy (in terms of maximum electrical work) = -qEcell° (negative sign reflects that work is negative if done by the system on the surroundings) So, wmax = -nFEcell° In terms of potential energy, wmax = DG° Thus DG° = -nFEcell°
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Chapter 18 Electrochemistry
Example problems: A NiCad battery contains 12.0 g of Cd that is oxidized to Cd(OH)2. How long should the battery last if a motor is drawing A? Assume 100% efficiency. (Hint: 1 A = 1 C s-1) Calculate the DG° (in kJ/mol) for the following reaction: 2Ag+(aq) + Cu(s) ↔ 2Ag(s) + Cu2+(aq), based on E° values given for half reactions on slide 8.
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Chapter 18 Electrochemistry
Relating Potential to Non-Standard Conditions: The Nernst Equation Starting from our equation for non-standard Equilibrium: DGrxn = DGºrxn + RTlnQ, we can convert this to a potential equation: -nFEcell = -nFEºcell + RTlnQ or if we divide both sides by –nF: Ecell = Eºcell - (RT/nF)lnQ Ecell = Eºcell - (0.0592/n)logQ (Nernst Equation – valid for T = 25ºC)
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Chapter 18 Electrochemistry
Nernst Equation Application Example: Determine the voltage for a Ag(s)/AgCl(s) electrode when [Cl-] = M if Eº = V (at T = 25°C)? Note: this is the same as when this electrode is attached to a SHE. 13
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Chapter 18 Electrochemistry
Nernst Equation Application – Cont. 2nd Examples: The following cell, Cd(s)|CdC2O4(s)|C2O42-(aq)||Cu2+(aq)1 M|Cu(s) is used to determine [C2O42-]. If Eº for the Cd reaction is V (reduction potential for oxidation reaction) and Eº for the Cu reaction is V, and the measured voltage is V, what is [C2O42-]?
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