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Five-Minute Check (over Lesson 3–3) Then/Now New Vocabulary
Key Concept: Nonvertical Line Equations Example 1: Slope and y-intercept Example 2: Slope and a Point on the Line Example 3: Two Points Example 4: Horizontal Line Key Concept: Horizontal and Vertical Line Equations Example 5: Write Parallel or Perpendicular Equations of Lines Example 6: Real-World Example: Write Linear Equations Lesson Menu
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A B C D What is the slope of the line MN for M(–3, 4) and N(5, –8)? A.
5-Minute Check 1
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What is the slope of a line perpendicular to MN for M(–3, 4) and N(5, –8)?
B. C. D. A B C D 5-Minute Check 2
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What is the slope of a line parallel to MN for M(–3, 4) and N(5, –8)?
B. C. D. A B C D 5-Minute Check 3
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What is the graph of the line that has slope 4 and contains the point (1, 2)?
A. B. C. D. A B C D 5-Minute Check 4
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What is the graph of the line that has slope 0 and contains the point (–3, –4)?
A. B. C. D. A B C D 5-Minute Check 5
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A. (–2, 2) B. (–1, 3) C. (3, 3) D. (4, 2) A B C D 5-Minute Check 6
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You found the slopes of lines. (Lesson 3–3)
Write an equation of a line given information about the graph. Solve problems by writing equations. Then/Now
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slope-intercept form point-slope form Vocabulary
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Concept
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y = mx + b Slope-intercept form y = 6x + (–3) m = 6, b = –3
Slope and y-intercept Write an equation in slope-intercept form of the line with slope of 6 and y-intercept of –3. Then graph the line. y = mx + b Slope-intercept form y = 6x + (–3) m = 6, b = –3 y = 6x – Simplify. Example 1
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Plot a point at the y-intercept, –3.
Slope and y-intercept Answer: Plot a point at the y-intercept, –3. Use the slope of 6 or to find another point 6 units up and 1 unit right of the y-intercept. Draw a line through these two points. Example 1
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Write an equation in slope-intercept form of the line with slope of –1 and y-intercept of 4.
A. x + y = 4 B. y = x – 4 C. y = –x – 4 D. y = –x + 4 A B C D Example 1
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Slope and a Point on the Line
Write an equation in point-slope form of the line whose slope is that contains (–10, 8). Then graph the line. Point-slope form Simplify. Example 2
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Graph the given point (–10, 8).
Slope and a Point on the Line Answer: Graph the given point (–10, 8). Use the slope to find another point 3 units down and 5 units to the right. Draw a line through these two points. Example 2
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Write an equation in point-slope form of the line whose slope is that contains (6, –3).
B. C. D. A B C D Example 2
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Step 1 First find the slope of the line.
Two Points A. Write an equation in slope-intercept form for a line containing (4, 9) and (–2, 0). Step 1 First find the slope of the line. Slope formula x1 = 4, x2 = –2, y1 = 9, y2 = 0 Simplify. Example 3
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Distributive Property
Two Points Step 2 Now use the point-slope form and either point to write an equation. Point-slope form Using (4, 9): Distributive Property Add 9 to each side. Answer: Example 3
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Step 1 First find the slope of the line.
Two Points B. Write an equation in slope-intercept form for a line containing (–3, –7) and (–1, 3). Step 1 First find the slope of the line. Slope formula x1 = –3, x2 = –1, y1 = –7, y2 = 3 Simplify. Example 3
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Distributive Property
Two Points Step 2 Now use the point-slope form and either point to write an equation. Point-slope form Using (–1, 3): m = 5, (x1, y1) = (–1, 3) Distributive Property Add 3 to each side. y = 5x + 8 Answer: Example 3
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A. Write an equation in slope-intercept form for a line containing (3, 2) and (6, 8).
B. C. D. A B C D Example 3a
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B. Write an equation in slope-intercept form for a line containing (1, 1) and (4, 10).
A. y = 2x – 3 B. y = 2x + 1 C. y = 3x – 2 D. y = 3x + 1 A B C D Example 3b
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This is a horizontal line.
Write an equation of the line through (5, –2) and (0, –2) in slope-intercept form. Step 1 Slope formula This is a horizontal line. Example 4
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Subtract 2 from each side. y = –2
Horizontal Line Step 2 Point-Slope form m = 0, (x1, y1) = (5, –2) Simplify. Subtract 2 from each side. y = –2 Answer: Example 4
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Write an equation of the line through (–4, –8) and (–1, –6) in slope-intercept form.
B. C. D. A B C D Example 4
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Concept
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y = mx + b Slope-Intercept form 0 = –5(2) + b m = 5, (x, y) = (2, 0)
Write Parallel or Perpendicular Equations of Lines y = mx + b Slope-Intercept form 0 = –5(2) + b m = 5, (x, y) = (2, 0) 0 = –10 + b Simplify. 10 = b Add 10 to each side. Answer: So, the equation is y = 5x + 10. Example 5
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A. y = 3x B. y = 3x + 8 C. y = –3x + 8 D. A B C D Example 5
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A = mr + b Slope-intercept form A = 525r + 750 m = 525, b = 750
Write Linear Equations RENTAL COSTS An apartment complex charges $525 per month plus a $750 annual maintenance fee. A. Write an equation to represent the total first year’s cost A for r months of rent. For each month of rent, the cost increases by $525. So the rate of change, or slope, is 525. The y-intercept is located where 0 months are rented, or $750. A = mr + b Slope-intercept form A = 525r m = 525, b = 750 Answer: The total annual cost can be represented by the equation A = 525r Example 6
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Evaluate each equation for r = 12.
Write Linear Equations RENTAL COSTS An apartment complex charges $525 per month plus a $750 annual maintenance fee. B. Compare this rental cost to a complex which charges a $200 annual maintenance fee but $600 per month for rent. If a person expects to stay in an apartment for one year, which complex offers the better rate? Evaluate each equation for r = 12. First complex: Second complex: A = 525r A = 600r + 200 = 525(12) r = 12 = 600(12) + 200 = 7050 Simplify. = 7400 Example 6
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Write Linear Equations
Answer: The first complex offers the better rate: one year costs $7050 instead of $7400. Example 6
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RENTAL COSTS A car rental company charges $25 per day plus a $100 deposit.
A. Write an equation to represent the total cost C for d days of use. A. C = 25 + d + 100 B. C = 125d C. C = 100d + 25 D. C = 25d + 100 A B C D Example 6a
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RENTAL COSTS A car rental company charges $25 per day plus a $100 deposit.
B. Compare this rental cost to a company which charges a $50 deposit but $35 per day for use. If a person expects to rent a car for 9 days, which company offers the better rate? A B C D A. first company B. second company C. neither D. cannot be determined Example 6b
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End of the Lesson
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