Download presentation
Presentation is loading. Please wait.
1
Do Now
2
Synthetic Division and the Remainder Theorem
Section 4.3 Day 2 Synthetic Division and the Remainder Theorem
3
Synthetic Division There is a shortcut for dividing polynomials by binomials of the form x – k. Synthetic Division is only possible if the divisor is in the form x – k, where k is any constant.
4
Example 1 Divide −x 3 + 4x by x − 3.
5
Divide using synthetic division:
6
Divide:
7
Remainder Theorem
8
Example 4 Use synthetic division to evaluate f (x ) = 5x 3 − x x + 29 when x = −4.
9
Example
10
Homework: Dividing Polynomials Using Synthetic Division Worksheet
11
Do Now: Divide using Long Division and Synthetic Division
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.