1. Lesson 6-5: Synthetic Division
Objective:
Students will use synthetic division to find quotients

2. Why Synthetic Division Less writing Uses addition
Setting Up
Divisor must be of the form: x – a
Use only “a” and coefficients of dividend
Write in “zero terms”
x – 2: a = 2
x + 3: a = -3

3. Steps
Bring down
Multiply diagonally
Add
Remainder = last addition
Answer
Numbers at bottom are coefficients
Start with 1 degree less than dividend
REPEAT

4. Example 1: (2x3 – 7x2 – 11x – 20) (x – 5)
so answer is 2x2 + 3x + 4 (remainder is 0) 10 15 20 2 3 4

5. Example 2: (2x4 – 30x2 – 2x – 1) (x – 4) 8 32 8 24 2 8 2 6 23
So the answer is 2x3 + 8x2 +2x + 6 +
(the remainder is 23)

6. Try It 3: (x5 + x4 + x3 + x2 + x + 1) (x + 1)

7. Marker Board pg 265 2 6 10 14 18 30 31
Assignment 6-5/265/4-20 M4, 33-35