1. Section 6.4 – Synthetic Division

4. 3 1 3 -3 -3 -1 -1 -8 1 2 2 1 3 1 3

5. 3 4 12 27 57 9 19 61 5 2 10 25
-15 5 -3 -1

6. 2 16 32
-162
-81 3 1 3 3 6 1 2 7

7. 3 1 3 9 12 3 4 14 4 1 4 16 -4
-16 4 -1 -4

8. 2/3 6 4 2 3 3
-1/2 2 -1 -2 -1 -2 4 2 4 2

9. 1/4 4 1 -1 -4 4

10. -1/2 4 -2 1 6 -2
-12 2

11. 3 1 3 9 12 3 4 14

12. 4 1 4 16 -4
-16 4 -1 -4

13. -3 2 -6 15 -6 -5 2

14. -1/2 2 -1 -5 6 10
-12 2

15. 1 2 2 19 54 45
-3/2 19 54 45 2 -3
-24
-45 16 30 2

16. Synthetic Division Summary
Set denominator = 0 and solve (box number)
Bring down first number
Multiply by box number and add until finished
Remainder goes over divisor
Notes of Caution
ALL terms must be represented (even if coefficient is 0)
If box number is a fraction, must divide final answer by
the denominator
To evaluate a function at a particular value, you may EITHER:
Substitute the value and simplify OR
Complete synthetic division…the remainder is your answer