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Section 6.1 Day 3
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Find and interpret the expected value for this lottery game
Find and interpret the expected value for this lottery game. A ticket costs $1. Winnings, x Probability, p $1 1/10 $2 1/14 $3 1/24 $ /200 $ /389 $ /20,000 $ /120,000
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E(X) = $2.72? Find and interpret the expected value for this lottery game. A ticket costs $1. Winnings, x Probability, p $1 1/10 $2 1/14 $3 1/24 $ /200 $ /389 $ /20,000 $ /120,000
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Think again!! Find and interpret the expected value for this lottery game. A ticket costs $1. Winnings, x Probability, p $1 1/10 $2 1/14 $3 1/24 $ /200 $ /389 $ /20,000 $ /120,000
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Think again!! Find and interpret the expected value for this lottery game. A ticket costs $1. Winnings, x Probability, p $1 1/10 $2 1/14 $3 1/24 $18 1/200 $50 1/389 $ /20,000 $ /120,000 Total
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Expected Value Find and interpret the expected value for this lottery game. A ticket costs $1. Winnings, x Probability, p $0 $ /10 $ /14 $ /24 $ /200 $ /389 $ /20,000 $ /120,000
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Expected Value Find and interpret the expected value for this lottery game. A ticket costs $1. Winnings, x Probability, p $ $ /10 $ /14 $ /24 $ /200 $ /389 $ /20,000 $ /120,000
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E(X) = $0.6014 How do we interpret this expected value?
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E(X) = $0.6014 How do we interpret this expected value? If we spend $1, we expect to get back $ Or, the state can expect to pay out $ for every $1000 of tickets sold.
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Linear Transformation Rule
Suppose you have a probability distribution with random variable X, mean x, and standard deviation x.
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Linear Transformation Rule
Suppose you have a probability distribution with random variable X, mean x, and standard deviation x. If you transform each value of x by multiplying it by d and then adding c, where c and d are constants, then
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Linear Transformation Rule
Suppose you have a probability distribution with random variable X, mean x, and standard deviation x. If you transform each value by multiplying it by d and then adding c, where c and d are constants, then c + dx = c + d x c + dx = |d|● x
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Expected Value Find and interpret the expected value for this new lottery game. A ticket costs $1. Winnings, x New winnings, 3x Probability, p $0 $ $1 $3 1/10 $2 $6 1/14 $3 $9 1/24 $18 $54 1/200 $50 $ /389 $150 $ /20,000 $900 $ /120,000
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New x = 0 + 3x, so c = 0 and d = 3 Find and interpret the expected value for this new lottery game. A ticket costs $1. Winnings, x New winnings, 3x Probability, p $0 $ $1 $3 1/10 $2 $6 1/14 $3 $9 1/24 $18 $54 1/200 $50 $ /389 $150 $ /20,000 $900 $ /120,000
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New x = 0 + 3x, so c = 0 and d = 3 μx = 0.6014 for original game
We expect to win $1.804 for each dollar we spend.
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Addition and Subtraction Rules
If X and Y are random variables, then X + Y = X + Y X - Y = X Y
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Addition and Subtraction Rules
If X and Y are random variables, then X + Y = X + Y X - Y = X Y and, if X and Y are independent, then 2X + Y = X Y 2X - Y = X Y
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For each million tickets sold, the original New York lottery awarded one $50,000 prize, nine $5000 prizes, ninety $500 prizes, and nine hundred $50 prizes. a. What was the expected value of a ticket?
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x p ,000/1,000,000 /1,000,000 /1,000,000 /1,000,000 50,000 1/1,000,000
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Expected value of a ticket is $0.185
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Expected value of a ticket is $0.185
The tickets sold for $0.50 each. How much could the state of New York expect to earn for every million tickets sold?
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Expected value of a ticket is $0.185
The tickets sold for $0.50 each. How much could the state of New York expect to earn for every million tickets sold? 1,000,000(0.50 – 0.185) = $315,000
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Page 377, P7
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Page 377, P7 Claire Charlotte Max Alisa Shaun
List all possible random samples of size 3 from this group of 5 students.
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Page 377, P7 Claire Charlotte Max Alisa Shaun
List all possible random samples of size 3 from this group of 5 students. 5C3 = 10
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Page 377, P7 Claire, Charlotte, Max Claire, Charlotte, Alisa
Claire, Charlotte, Shaun Claire, Max, Alisa; Charlotte, Alisa, Shaun Claire, Max, Shaun; Max, Alisa, Shaun Claire, Alisa, Shaun Charlotte, Max, Alisa Charlotte, Max, Shaun
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Page 377, P7
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Page 377, P7 Claire, Charlotte, Max Claire, Charlotte, Alisa
Claire, Charlotte, Shaun Claire, Max, Alisa; Charlotte, Alisa, Shaun Claire, Max, Shaun; Max, Alisa, Shaun Claire, Alisa, Shaun Charlotte, Max, Alisa Charlotte, Max, Shaun
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Page 377, P7
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Page 377, P10
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Page 377, P10 How many possible samples of size 2?
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Page 377, P10 How many possible samples of size 2? 6C2 = 15
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Page 377, P10 (a) The 15 possible samples of size 2 are:
1 and 2; 1 and 3; 1 and 4; 1 and 5; 1 and 6 2 and 3; 2 and 4; 2 and 5; 2 and 6 3 and 4; 3 and 5; 3 and 6 4 and 5; 4 and 6 5 and 6
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Page 377, P10 Assume computers 1, 2, and 3 are the defective monitors. (The probabilities would be the same no matter which 3 were assigned as the defective monitors).
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Page 377, P10 Assume computers 1, 2, and 3 are the defective monitors. (The probabilities would be the same no matter which 3 were assigned as the defective monitors). 1 and 2; 1 and 3; 1 and 4; 1 and 5; 1 and 6 2 and 3; 2 and 4; 2 and 5; 2 and 6 3 and 4; 3 and 5; 3 and 6 4 and 5; 4 and 6 5 and 6
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Page 377, P10
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Page 377, P10
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Page 377, P10
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Page 381, E16
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Page 381, E16
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Page 381, E16
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Page 381, E16
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Page 381, E16
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Page 381, E16
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Page 382, E20
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Page 382, E20
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Page 382, E20
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Questions?
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Fathom Activity 6.1a
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Activity 6.1a x x Die 1 Die 2 Sum Difference
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Activity 6.1a x x Die Die 2 Sum Difference
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Activity 6.1a x x Die Die Sum Difference
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Fathom Activity 6.1a
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Fathom Activity 6.1a
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Activity 6.1a x 2x Die 1 3.5 2.917 Die 2 3.5 2.917 Sum 7 5.834
Difference
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Activity 6.1a x 2x Die 1 3.5 2.917 Die 2 3.5 2.917 Sum 7 5.834
Difference
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Activity 6.1a, 500 rolls Variance 5.276 5.895
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Fathom Activity 6.1a
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Fathom Activity 6.1a
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