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4.2 Integer, Coin and Stamp Problems

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1 4.2 Integer, Coin and Stamp Problems
Hubarth Math 90

2 Consecutive Integers are integers that follow on another in order.
What does this mean? What are consecutive even integers? What are consecutive odd integers? Example 1 Find three consecutive even integers such that three times the second integer is 6 more than the sum of the first and the third integer. 1𝑠𝑑=n 2𝑛𝑑=𝑛+2 3π‘Ÿπ‘‘=𝑛+4 The three consecutive integers are: 4, 6, 8 3 𝑛+2 = 𝑛)+(𝑛+4 +6 3𝑛+6=2𝑛+10 𝑛=4

3 Coin and Stamp problem strategies- for each coin or stamp problems, write a numerical or
variable expression for the number of coins or stamps, the value of the coin/stamp in cents, and the total value of the coins/stamps in cents. Use a table. Example 2 A collection of stamps consist of 3Β’ stamps and 8 Β’ stamps. The number of 8Β’ stamps is five more than three times the number of 3Β’ stamps. The total value of all the stamps is $1.75. Find the number of each type of stamps in the collection. # of stamps Value Total Value 3Β’ x 3 8Β’ 3π‘₯+5 8 x = 3x 8(3x+5) 3π‘₯+8 3π‘₯+5 =175 3 5 +5=20 3π‘₯+24π‘₯+40=175 27π‘₯+40=175 There are five 3 Β’ stamps and twenty 8 Β’ stamps. 27π‘₯=135 π‘₯=5

4 Example 3 A coin bank contains$1.20 in dimes and quarters. In all, there are nine coins in the bank. Find the number of quarters in the bank. π‘‘π‘–π‘šπ‘’π‘ =𝑛 π‘žπ‘’π‘Žπ‘Ÿπ‘‘π‘’π‘Ÿπ‘ =9βˆ’π‘› # of coins value total value dimes n 10 quarters 9-n 25 10n 25(9-n) 10𝑛+25 9βˆ’π‘› =120 9βˆ’7=2 10𝑛+225βˆ’25𝑛=120 There are two quarters in the bank βˆ’15𝑛=βˆ’105 𝑛=7

5 Practice A coin bank contains nickels, dimes and quarters. There are five times as many nickels as dimes and six more quarters than dimes. The total value of all coins is $6.30. Find the number of each kind of coin in the bank. π‘‘π‘–π‘šπ‘’π‘ =𝑑 π‘›π‘–π‘π‘˜π‘’π‘™π‘ =5𝑑 π‘žπ‘’π‘Žπ‘Ÿπ‘‘π‘’π‘Ÿπ‘ =𝑑+6 # of coins Value Total Value dimes d 10 10d nickels 5d 5 25d quarters d+6 25 25d+150 10𝑑+25𝑑+25𝑑+150=630 π‘‘π‘–π‘šπ‘’π‘ =8 π‘›π‘–π‘π‘˜π‘’π‘™π‘ =5 8 =40 π‘žπ‘’π‘Žπ‘Ÿπ‘‘π‘’π‘Ÿπ‘ =8+6=14 60𝑑+150=630 60𝑑=480 𝑑=8


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