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Excursions in Modern Mathematics Sixth Edition
Peter Tannenbaum
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Chapter 4 The Mathematics of Apportionment
Making the Rounds
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The Mathematics of Apportionment Outline/learning Objectives
To state the basic apportionment problem. To implement the methods of Hamilton, Jefferson, Adams and Webster to solve apportionment problems. To state the quota rule and determine when it is satisfied. To identify paradoxes when they occur. To understand the significance of Balanski and Young’s impossibility theorem.
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The Mathematics of Apportionment
4.1 Apportionment Problems
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The Mathematics of Apportionment
Apportion- two critical elements in the definition of the word We are dividing and assigning things. We are doing this on a proportional basis and in a planned, organized fashion.
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The Mathematics of Apportionment
Table 4-3 Republic of Parador (Population by State) State A B C D E F Total Population 1,646,000 6,936,000 154,000 2,091,000 685,000 988,000 12,500,000 The first step is to find a good unit of measurement. The most natural unit of measurement is the ratio of population to seats. We call this ratio the standard divisor SD = P/M SD = 12,500,000/250 = 50,000
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The Mathematics of Apportionment
Table 4-4 Republic of Parador: Standard Quotas for Each State (SD = 50,000) State A B C D E F Total Population 1,646,000 6,936,000 154,000 2,091,000 685,000 988,000 12,500,000 Standard quota 32.92 138.72 3.08 41.82 13.70 19.76 250 For example, take state A. To find a state’s standard quota, we divide the state’s population by the standard divisor: Quota = population/SD = 1,646,000/50,000 = 32.92
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The Mathematics of Apportionment
The “states.” This is the term we will use to describe the players involved in the apportionment. The “seats.” This term describes the set of M identical, indivisible objects that are being divided among the N states. The “populations.” This is a set of N positive numbers which are used as the basis for the apportionment of the seats to the states.
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The Mathematics of Apportionment
Upper quotas. The quota rounded down and is denoted by L. Lower quotas. The quota rounded up and denoted by U. In the unlikely event that the quota is a whole number, the lower and upper quotas are the same.
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4.2 Hamilton’s Method and the Quota Rule
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Hamilton’s Method Step 1. Calculate each state’s standard quota. State Population Step1 Quota A 1,646,000 32.92 B 6,936,000 138.72 C 154,000 3.08 D 2,091,000 41.82 E 685,000 13.70 F 988,000 19.76 Total 12,500,000 250.00
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State Population Step1 Quota Step 2 Lower Quota A 1,646,000 32.92 32 B 6,936,000 138.72 138 C 154,000 3.08 3 D 2,091,000 41.82 41 E 685,000 13.70 13 F 988,000 19.76 19 Total 12,500,000 250.00 246 Hamilton’s Method Step 2. Give to each state its lower quota.
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The Mathematics of Apportionment
Step 3. Give the surplus seats to the state with the largest fractional parts until there are no more surplus seats. State Population Step1 Quota Step 2 Lower Quota Fractional parts Step 3 Surplus Hamilton apportionment A 1,646,000 32.92 32 0.92 First 33 B 6,936,000 138.72 138 0.72 Last 139 C 154,000 3.08 3 0.08 D 2,091,000 41.82 41 0.82 Second 42 E 685,000 13.70 13 0.70 F 988,000 19.76 19 0.76 Third 20 Total 12,500,000 250.00 246 4.00 4 250
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The Quota Rule No state should be apportioned a number of seats smaller than its lower quota or larger than its upper quota. (When a state is apportioned a number smaller than its lower quota, we call it a lower-quota violation; when a state is apportioned a number larger than its upper quota, we call it an upper-quota violation.)
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4.3 The Alabama and Other Paradoxes
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The most serious (in fact, the fatal) flaw of Hamilton's method is commonly know as the Alabama paradox. In essence, the paradox occurs when an increase in the total number of seats being apportioned, in and of itself, forces a state to lose one of its seats.
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With M = 200 seats and SD = 100, the apportionment under Hamilton’s method State Population Step 1 Step 2 Step 3 Apportionment Bama 940 9.4 9 1 10 Tecos 9,030 90.3 90 Ilnos 10,030 100.3 100 Total 20,000 200.0 199 200
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The Mathematics of Apportionment
With M = 201 seats and SD = 99.5, the apportionment under Hamilton’s method State Population Step 1 Step 2 Step 3 Apportionment Bama 940 9.45 9 Tecos 9,030 90.75 90 1 91 Ilnos 10,030 100.80 100 101 Total 20,000 201.00 199 2 201
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The Mathematics of Apportionment
The Hamilton’s method can fall victim to two other paradoxes called the population paradox- when state A loses a seat to state B even though the population of A grew at a higher rate than the population of B. the new-states paradox- that the addition of a new state with its fair share of seats can, in and of itself, affect the apportionments of other states.
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4.4 Jefferson’s Method
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Jefferson’s Method Step 1. Find a “suitable” divisor D. [ A suitable or modified divisor is a divisor that produces and apportionment of exactly M seats when the quotas (populations divided by D) are rounded down.
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Jefferson’s Method Step 2. Each state is apportioned its lower quota. State Population Standard Quota (SD = 50,000) Lower Quota Modified Quota (D = 49,500) Hamilton apportionment A 1,646,000 32.92 32 33.25 33 B 6,936,000 138.72 138 140.12 140 C 154,000 3.08 3 3.11 D 2,091,000 41.82 41 42.24 42 E 685,000 13.70 13 13.84 F 988,000 19.76 19 19.96 Total 12,500,000 250.00 246 250
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Bad News- Jefferson’s method can produce upper-quota violations! To make matters worse, the upper-quota violations tend to consistently favor the larger states.
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4.5 Adam’s Method
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Adam’s Method Step 1. Find a “suitable” divisor D. [ A suitable or modified divisor is a divisor that produces and apportionment of exactly M seats when the quotas (populations divided by D) are rounded up. State Population Quota (D = 50,500) A 1,646,000 32.59 B 6,936,000 137.35 C 154,000 3.05 D 2,091,000 41.41 E 685,000 13.56 F 988,000 19.56 Total 12,500,000
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The Mathematics of Apportionment
Adam’s Method Step 2. Each state is apportioned its upper quota. State Population Quota (D = 50,500) Upper Quota (D = 50,700) Adam’s apportionment A 1,646,000 32.59 33 32.47 B 6,936,000 137.35 138 136.80 137 C 154,000 3.05 4 3.04 D 2,091,000 41.41 42 41.24 E 685,000 13.56 14 13.51 F 988,000 19.56 20 19.49 Total 12,500,000 251 250
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Bad News- Adam’s method can produce lower-quota violations! We can reasonably conclude that Adam’s method is no better (or worse) than Jefferson’s method– just different.
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4.6 Webster’s Method
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The Mathematics of Apportionment
Webster’s Method Step 1. Find a “suitable” divisor D. [ Here a suitable divisor means a divisor that produces an apportionment of exactly M seats when the quotas (populations divided by D) are rounded the conventional way.
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Step 2. Find the apportionment of each state by rounding its quota the conventional way. State Population Standard Quota (D = 50,000) Nearest Integer Quota (D = 50,100) Webster’s apportionment A 1,646,000 32.92 33 32.85 B 6,936,000 138.72 139 138.44 138 C 154,000 3.08 3 3.07 D 2,091,000 41.82 42 41.74 E 685,000 13.70 14 13.67 F 988,000 19.76 20 19.72 Total 12,500,000 250.00 251 250
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The Mathematics of Apportionment Conclusion
Covered different methods to solve apportionment problems named after Alexander Hamilton, Thomas Jefferson, John Quincy Adams, and Daniel Webster. Examples of divisor methods based on the notion divisors and quotas can be modified to work under different rounding methods
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The Mathematics of Apportionment Conclusion (continued)
Balinski and Young’s impossibility theorem An apportionment method that does not violate the quota rule and does not produce any paradoxes is a mathematical impossibility.
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