1. Problem 2
While training for breeding season, a 380 gram male squirrel does 32 pushups in a minute, displacing its center of mass by a distance of 8,5 cm for each pushup.
Determine the total work done on the squirrel while moving upward (32 times).

2. We must calculate the total work done by the squirrel in 32 jumps, then we must apply the law:
L = F x s (Work = force x displacement)
In this case the strength corresponds to the force, ie the gravitational attraction of bodies from the earth, then F = m x g
g = 9.8 m / s ² (gravitational accelerator value) L = m x g x s (Work = mass x gravitational acceleration x displacement)

3. But first we must do two conversations, and bring in meters and centimeters kilograms grams: 8.5 cm = m 380 grams = 0.38 kg

4. Now we can apply the law mxgxs = , then:  = 0. 38 kg x 9
Now we can apply the law mxgxs = , then:  = 0.38 kg x 9.8 m / s ² x m = 0.31 J
But as 0,31 J is the work done in each step, then: x 32 J = 10 J