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ELEC 3105 Basic EM and Power Engineering
Electric dipole Force / torque / work on electric dipole Z
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The Electric Dipole z P(x, z)
Consider electric field and potential produced by 2 charges (+q, -q) separated by a distance d. P(x, z) +q d x -q
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The Electric Dipole z P(x, z)
The dipole is represented by a vector of magnitude qd and pointing from –q to +q. P(x, z) +q d x -q Note: small letter p Units {p} dipole moment; Coulomb meter {Cm}
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Potential at P(x, y) due to charge +q.
The Electric Dipole z P(x, z) Potential at P(x, y) due to charge +q. +q d x -q Units {p} dipole moment; Coulomb meter {Cm}
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Potential at P(x,y) due to charge -q.
The Electric Dipole z P(x,z) Potential at P(x,y) due to charge -q. +q d x -q Units {p} dipole moment; Coulomb meter {Cm}
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The Electric Dipole Suppose (x,y) >>> d P(x, z) z +q d -q x
Can be rewritten and the expression for the potential simplified. Then:
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Suppose (x, z) >>> d
The Electric Dipole Suppose (x, z) >>> d Binomial expansion
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Suppose (x, z) >>> d
The Electric Dipole Suppose (x, z) >>> d Binomial expansion
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Suppose (x,y) >>> d
The Electric Dipole Suppose (x,y) >>> d z P(x, z) +q d -q x
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The Electric Dipole Suppose (x, z) >>> d
Potential produced by the dipole
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Suppose (x, z) >>> d
The Electric Dipole Suppose (x, z) >>> d z P(x, z) +q d -q x
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The Electric Dipole Suppose (x, z) >>> d P(x, z) z
Cartesian coordinates (x, z) +q d -q x
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The Electric Dipole Suppose (x, z) >>> d P(r, , ) z
Spherical coordinates (r, , ) +q d -q x
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The Electric Dipole z x V Drops off as 1/r2 for a dipole
P(r, , ) x V Drops off as 1/r2 for a dipole V Drops off as 1/r for a point charge
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The Electric Dipole Now to compute the electric field expression
P(x, z)) Cartesian coordinates (x, z) z P(r, , ) Spherical coordinates (r, , ) +q d -q x
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Now to compute the electric field expression
The Electric Dipole Now to compute the electric field expression
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Spherical coordinates (r, , )
The Electric Dipole Spherical coordinates (r, , ) No 𝜙 dependence
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The Electric Dipole
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Here consider dipole as a rigid charge distribution
Force on a dipole in a uniform electric field Here consider dipole as a rigid charge distribution +q d No net translation since -q Opposite direction
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Here consider dipole as a rigid charge distribution
Force on a dipole in a non-uniform electric field Here consider dipole as a rigid charge distribution +q d net translation since -q And / Or
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Force on a dipole in a non-uniform electric field
y Force on a dipole in a non-uniform electric field +q Manipulate expression to get simple useful form d -q x
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Force on a dipole in a non-uniform electric field
y Force on a dipole in a non-uniform electric field After the manipulations end we get: +q d -q x We will obtain this expression using a different technique.
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Here consider dipole as a rigid charge distribution
Torque on a dipole Here consider dipole as a rigid charge distribution +q d/2 d/2 -q The torque components + and - act in the same rotational direction trying to rotate the dipole in the electric field.
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Review of the concept of torque
Torque on a dipole Torque: Pivot Moment arm length Force Angle between vectors r and F
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For simplicity consider the dipole in a uniform electric field
Torque on a dipole Act in same direction +q d -q Also valid for small dipoles in a non-uniform electric field.
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Consider work dW required to rotate dipole through an angle d
Work on a dipole By definition When you have rotation If we integrate over some angle range then +q d -q
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Work on a dipole For = 90 degrees W = 0. Thus = 90 degrees is reference orientation for the dipole. It corresponds to the zero of the systems potential energy as well. U=W
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Work on a dipole For = 0 degrees W = -pE. Thus = 0 degrees is the minimum in energy and corresponds to the having the dipole moment aligned with the electric field.
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Work on a dipole For = 180 degrees W = pE. Thus = 180 degrees is the maximum in energy and corresponds to having the dipole moment anti-aligned with the electric field.
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Force on a dipole +q d -q Work Force
After the manipulations end we get: +q d We will obtain this expression using a different technique. Work -q Force
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Exam question: once upon a time
Stator dipole +q -q +Q 2R 2r Rotor dipole E on +q F on +q on +q on rotor -Q (0,0)
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Exam question: Once upon a time
D>>R 2R e) on dipole -Q
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Electric flux Density extra topic (1)
𝐷 𝐷 =𝜀 𝐸
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From other definitions of flux we can obtain other useful expressions for electrostatics
Divergence theorem
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Divergence theorem Integrands must be the same for all dV
Point function Gauss’s law in differential form Medium dependence
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Divergence theorem Integrands must be the same for all dV
Point function Gauss’s law in differential form No dependence on the dielectric constant
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