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Scheduling, IP …
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Puzzle Two glass marbles, identical properties
One building with 100 floors Either marble, if thrown from a certain floor k or above will break, but will not break if thrown from floor k-1 or below What is the minimum number of throws required to find k? (worst case scenario) Once you break a marble, you cannot use it anymore
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Scheduling Policies … FCFS Priority
Packets queued on a first-come-first-served basis No fairness Priority Multiple queues with different priorities Packets belonging to queue k served only when queues with higher priorities are empty
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Scheduling (Contd.) Generalized Processor Sharing (GPS)
Ideal fair queuing approach based on a fluid flow system Complex, idealistic Packetized GPS (WFQ) Packetized version of GPS (practical) Finish times in a correponding GPS system used for prioritizing packets
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Scheduling - WFQ 3 flows A, B, C Weights: A(1), B(2), C(3)
Assume same packet sizes 8 7 Complex overhead due to computation of finishing times Simpler approach? 5 4 6 3 2 1 Tx Schedule: C B C C B A C B …
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Scheduling (Contd.) Weighted Round Robin A Fixed Tx Schedule:
Simpler approximation of WFQ Assumes constant packet sizes Can cause unfair delay A Fixed Tx Schedule: C C C B B A A B C
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Scheduling (Contd.) WRR with WFQ Spread
For each flow k with weight wk generate wk elements of the form (1/wk,k), (2/wk,k), …, (wk/wk,k) Sort all such elements from all competing flows in lexicographic order Extracting the second element of each pair from the resulting sorted list gives the WRR with WFQ spread
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WRR with WFQ Spread A (1) (1,A) B (2) (1/2,B), (1,B) C (3)
(1/3,C), (2/3,C), (1,C) Lexicographically Sorted: (1/3,C), (1/2,B), (2/3,C), (1,A), (1,B), (1,C) Schedule: C B C A B C
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Other scheduling policies…
Deficit Round Robin (DRR) Handles varying size packets Frame of N bits split among the competing flows in the ratio of their weights Flows get to transmit HOL packet only when they have accumulated packet-length number of bits Class based queuing (CBQ) General scheduling and link-share scheduling Greater flexibility to control scheduling policy
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TCP/IP Protocol Suite Physical layer Data-link layer – ARP, RARP, SLIP
Network layer – IP, ICMP, IGMP, BootP Transport layer _ TCP, UDP, RTP Application layer – http, smtp, ftp
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Internet Protocol (IP)
Addressing Routing Fragmentation and Reassembly Quality of Service Multiplexing and Demultiplexing
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Addressing Need unique identifier for every host in the Internet (analogous to postal address) IP addresses are 32 bits long Hierarchical addressing scheme Conceptually … IPaddress =(NetworkAddress,HostAddress)
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Address Classes Class A Class B Class C 0 netId hostId
7 bits 24 bits netId hostId 14 bits 16 bits netId hostId 21 bits 8 bits
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IP Address Classes (contd.)
Two more classes 1110 : multicast addressing 1111 : reserved Significance of address classes? Why this conceptual form?
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Addresses and Hosts Since netId is encoded into IP address, each host will have a unique IP address for each of its network connections Hence, IP addresses refer to network connections and not hosts Why will hosts have multiple network connections?
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Special Addresses hostId of 0 : network address
hostId of all 1’s: directed broadcast All 1’s : limited broadcast netId of 0 : this network Loopback : Dotted decimal notation: IP addresses are written as four decimal integers separated by decimal points, where each integer gives the value of one octet of the IP address.
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Exceptions to Addressing (norm today)
Subnetting Splitting hostId into subnetId and hostId Achieved using subnet masks Useful for? Supernetting (Classless Inter-domain Routing or CIDR) Combining multiple lower class address ranges into one range Achieved using 32 bit masks and max prefix routing
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Examples Subnetting Supernetting 192.168.1.0/24 – class C network
/26 and /26 – 2 subnetworks with upto 62 stations each! Supernetting /24 and /24 – 2 class C networks /23 – 1 super network with upto 126 stations!!
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Weaknesses Mobility Switching address classes
Notion of host vs. IP address
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IP Routing Direct Indirect
If source and destination hosts are connected directly Still need to perform IP address to physical address translation. Why? Indirect Table driven routing Each entry: (NetId, RouterId) Default router Host-specific routes
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IP Routing Algorithm RouteDatagram(Datagram, RoutingTable)
Extract destination IP address, D, from the datagram and compute the netID N If N matches any directly connected network address deliver datagram to destination D over that network Else if the table contains a host-specific route for D, send datagram to next-hop specified in table Else if the table contains a route for network N send datagram to next-hop specified in table Else if the table contains a default route send datagram to the default router specified in table Else declare a routing error
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Routing Protocols Interior Gateway Protocol (IGP)
Within an autonomous domain RIP (distance vector protocol), OSPF (link state protocol) Exterior Gateway Protocol (EGP) Across autonomous domains BGP (border gateway protocol)
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IP Fragmentation The physical network layers of different networks in the Internet might have different maximum transmission units The IP layer performs fragmentation when the next network has a smaller MTU than the current network MTU = MTU=500 IP fragmentation
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IP Reassembly Fragmented packets need to be put together
Where does reassembly occur? What are the trade-offs?
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Multiplexing Web Email MP3 Web Email MP3 TCP UDP TCP UDP IP IP
IP datagrams IP datagrams
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IP Header Used for conveying information to peer IP layers Source
Destn Application Application Transport Router Router Transport IP IP IP IP DataLink DataLink DataLink DataLink Physical Physical Physical Physical
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IP Header (contd.) 4 bit version 4 bit hdr length 16 bit total length
TOS 16 bit identification 3 bit flags 13 bit fragment offset 8 bit TTL 8 bit protocol 16 bit header checksum 32 bit source IP address 32 bit destination IP address Options (if any) (maximum 40 bytes) data
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Recap MAC Protocols: ALOHA, slotted-ALOHA, CSMA, CSMA/CD
Scheduling: FCFS, Priority, FQ, WFQ, WRR, CBQ Internet Protocol: Addressing, Routing, Fragmentation & Reassembly, Mux/Demux
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Puzzle You have a deck of 52 cards
You draw out 5 cards randomly and look at the cards You can now show 4 of the cards to a friend, and the friend should identify the 5th card How do you do this?
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TCP/IP in relation to the OSI model
TCP/IP in relation to the OSI model
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