Presentation is loading. Please wait.

Presentation is loading. Please wait.

Temperature and Pressure

Similar presentations


Presentation on theme: "Temperature and Pressure"— Presentation transcript:

1 Temperature and Pressure
General, Organic, and Biological Chemistry Fourth Edition Karen Timberlake Chapter 7 Gases 7.5 Temperature and Pressure (Gay-Lussac’s Law) Lectures © 2013 Pearson Education, Inc.

2 Gay-Lussac’s Law: P and T
Gay-Lussac’s law states that the pressure exerted by a gas is directly related to the Kelvin temperature. V and n are constant. an increase in temperature increases the pressure of a gas. 2

3 Calculation with Gay-Lussac’s Law
A gas has a pressure at 2.0 atm at 18 ˚C. What is the new pressure when the temperature is increased to 62 ˚C? (V and n constant) Step 1 Organize the data in a table of initial and final conditions. Analyze the Problem. Conditions 1 Conditions 2 Know Predict P1 = 2.0 atm P2 = ? P increase T1 = 18 °C + 273 = 291 K T2 = 62 °C + 273 = 335 K T increase 3

4 Calculation with Gay-Lussac’s Law
A gas has a pressure at 2.0 atm at 18 ˚C. What is the new pressure when the temperature is increased to 62 ˚C? (V and n constant) Step 2 Rearrange the gas law equation to solve for the unknown quantity. 4

5 Calculation with Gay-Lussac’s Law
A gas has a pressure at 2.0 atm at 18 ˚C. What is the new pressure when the temperature is increased to 62 ˚C? (V and n constant) Step 3 Substitute values into the gas law equation and calculate. 5

6 Learning Check Solve for the final pressure of a gas with an initial pressure of 1.20 atm at 75 ˚C when cooled to −22 ˚C. (V and n constant) 6

7 Solution Solve for the final pressure of a gas with an initial pressure of 1.20 atm at 75 ˚C when cooled to −22 ˚C. Step 1 Organize the data in a table of initial and final conditions. Analyze the Problem. Conditions 1 Conditions 2 Know Predict P1 = 1.20 atm P2 = ? P decrease T1 = 75 °C + 273 = 348 K T2 = −22 °C + 273 = 251 K T decrease 7

8 Solution Solve for the final pressure of a gas with an initial pressure of 1.20 atm at 75 ˚C when cooled to −22 ˚C. Step 2 Rearrange the gas law equation to solve for the unknown quantity. 8

9 Solution Solve for the final pressure of a gas with an initial pressure of 1.20 atm at 75 ˚C when cooled to −22 ˚C. Step 3 Substitute values into the gas law equation and calculate. 9

10 Vapor Pressure In a closed container, the vapor above a liquid accumulates and creates pressure called vapor pressure. Each liquid exerts its own vapor pressure at a given temperature. As temperature increases, more vapor forms, and vapor pressure increases. 10

11 Vapor Pressure and Boiling Point
A liquid reaches its boiling point when its vapor pressure becomes equal to the external pressure. 11

12 Boiling Point of Water The boiling point of water
depends on the vapor pressure. is lower at higher altitudes. is increased by using an autoclave to increase external pressure. 12

13 Learning Check In which pairs of pressures will water boil? Atmospheric Vapor Pressure Pressure A. 760 mmHg 760 mmHg B. 960 mmHg 760 mmHg C. 520 mmHg 620 mmHg 13

14 Solution In which pairs of pressures will water boil? Atmospheric Vapor Boiling Pressure Pressure Occurs? A. 760 mmHg 760 mmHg yes B. 960 mmHg 760 mmHg no C. 520 mmHg 620 mmHg yes 14


Download ppt "Temperature and Pressure"

Similar presentations


Ads by Google