1. SQL and Data Modeling Jeopardy
MIST 4610 Summer 2017

2. Game Format STEP 1 GAME FORMAT
Get with your group project team. You will work together when answering the jeopardy questions
GAME FORMAT
Each query and data model have two levels of difficulty
Easy and hard
10 queries (including 2 warm-ups)
Each easy query is worth 1 point (warm-ups do not count)
Each hard query is worth 2 points (warm-ups do not count)
3 data models (no warm-ups)
Easy data model is worth 1 point
Hard data model is worth 2 points
Hard-ish data model is worth 3 points

3. Each member of the winning team will get …
Game Format
GAME FORMAT SCORING
4 easy and 4 hard queries (total of 12 points)
1 easy, 1 medium, and 1 kind of hard data model (total of 6 points)
WINNER
Each member of the winning team will get …
BRAGGING RIGHTS!
RUNNER UP gets “nada,” sorry!

4. Game Rules
RULES
When you are ready to answer raise your hand. Whoever does it first gets to answer the question first. If the answer is incorrect the group loses points (e.g., -1 if you miss the first easy query)
Every group will have a maximum of 10 minutes per query and 15 minutes per data model. If nobody gets the right answer nobody will receive a point

5. SQL and Data Modeling Jeopardy
WARM-UP

6. SQL – Category “Warming Up”
How many sales managers report to the sales VP?
SELECT COUNT(*)
FROM Employees boss, Employees reports
WHERE boss.employeeNumber = reports.reportsTo
AND boss.jobTitle REGEXP 'VP Sales'
AND reports.jobTitle REGEXP 'Sales Manager';

7. SQL – Category “Warming Up”
Report the product name and total buy price for each product shipped on November Sort results by shipped date and product name.
SELECT productName, shippedDate, sum(buyPrice)
FROM Products, OrderDetails, Orders
WHERE Products.productCode = OrderDetails.productCode
AND Orders.orderNumber = OrderDetails.orderNumber
AND YEAR(shippedDate) = 2003
AND MONTH(shippedDate) = 11
GROUP BY productName
ORDER BY shippedDate, productName;

8. SQL and Data Modeling Jeopardy
STARTS NOW…

9. SQL 1 – Category “Easy”
List the required date and order number of all orders shipped in November Sort by required
date and order number.
SELECT requiredDate, orderNumber
FROM Orders
WHERE MONTH(shippedDate) = 11 AND YEAR(shippedDate) = 2003
ORDER BY requiredDate, orderNumber

10. SQL 2 – Category “Easy”
List the name and price of each cancelled Porsche product. Sort by highest price to lowest. Format to two decimals.
SELECT productName, FORMAT(priceEach,2) AS 'Price' FROM OrderDetails, Orders, Products
WHERE OrderDetails.orderNumber = Orders.orderNumber
AND OrderDetails.productCode = Products.productCode
AND status = 'Cancelled'
AND productName REGEXP 'Porsche'
ORDER BY priceEach DESC;

11. SQL 3 – Category “Hard”
Find all orders where it took more than a year for the customer to pay for the order.
SELECT orderNumber, datediff(paymentDate,orderDate) as DaysTakenToPay, amount as AmountInDollars
FROM Payments,Customers,Orders
WHERE Payments.customerNumber = Customers.customerNumber
AND Customers.customerNumber = Orders.customerNumber
AND datediff(paymentDate,orderDate) > 365;

12. SQL 4 – Category “Hard”
Report the total revenue for each sales rep who has completed an order. Format results to show two decimal places. Sort and group results by employee's last name.
SELECT lastName, ROUND(SUM(quantityOrdered*priceEach),2) AS 'Total Revenue’
FROM OrderDetails, Orders, Customers, EmployeesWHERE OrderDetails.orderNumber = Orders.orderNumberAND Orders.customerNumber = Customers.customerNumberAND Customers.salesRepEmployeeNumber = Employees.employeeNumberAND jobTitle = 'Sales Rep'GROUP BY lastNameORDER BY lastName;

13. SQL 5 – Category “Easy”
Which country/countries has/have more than 2 offices?
SELECT country, COUNT(*)
FROM Offices
GROUP BY country
HAVING COUNT(*) > 2

14. SQL 6 – Category “Easy”
List the and phone extension for all employees working in Australia. Sort results by .
SELECT , extension
FROM Offices, Employees
WHERE Offices.officeCode = Employees.officeCode
AND country = 'Australia'
ORDER BY

15. SQL 7 – Category “Hard”
Are there any products that have appeared in all orders?
SELECT productCode, productName
FROM products
WHERE NOT EXISTS
                        (SELECT * FROM orders
                               WHERE NOT EXISTS
                                           (SELECT * FROM orderdetails
                  WHERE orderdetails.Productcode = products.productCode
                  AND orderdetails.ordernumber = orders.ordernumber));

16. SQL 8 – Category “Hard”
Find the customer name and total credit limit (only if higher than 90000) for all customer accounts that are controlled by William Patterson through the sales representative Andy Fixter. Organize the data by the customer name in alphabetical order. Finally, make sure the columns are labeled for ease of reading by the Marketing Director.
SELECT customerName, SUM(creditLimit) AS 'Total Credit Limit', emp.lastName AS 'Sales Rep Last Name', emp.firstName AS 'Sales Rep First Name', boss.lastName 'Boss Last Name', boss.firstName 'Boss First Name'
FROM Customers, Employees emp, Employees boss
WHERE Customers.salesRepEmployeeNumber = Employees.employeeNumber
AND emp.reportsTo = boss.employeeNumber
AND boss.firstName = 'William'
AND boss.lastName = 'Patterson'
AND emp.firstName = 'Andy'
AND emp.lastName = 'Fixter'
GROUP BY boss.lastName, customerName
HAVING SUM(creditLimit) > 90000
ORDER BY customerName;

17. SQL and Data Modeling Jeopardy
BREAK TIME

18. Data Modeling – Category “Easy”
A dairy farmer, who is also a part-time cartoonist, has several herds of cows. He has assigned each cow to a particular herd. In each herd, the farmer has one cow that is his favorite--often that cow is featured in a cartoon. Draw a data model to represent this scenario.

19. Data Modeling – Category “Medium”
A consulting company has assigned each of its employees to a specialist group (e.g., database management). Each specialist group has a team leader. When employees join the company, they are assigned a mentor for the first year. One person might mentor several employees, but an employee has at most one mentor. Draw a data model to represent this scenario.

20. Data Modeling – Category “Hard-ish”
The National Office of Academic Conferences (N. O.A.C.) wants to keep track of the conferences attended by university researchers. It gives you the following information:
A university is identified by its name and located in a particular city. A university has many researchers, each of whom can only be associated with only one university. A researcher is identified by an identification number, and has a name, phone, and address. A researcher can attend many conferences. A conference is identified by an identification number; it also has a name, a location, and a date. For each conference, a researcher may or may not present a scientific research paper.
For each conference, one university is in charge of its logistics, while another university is in charge of its marketing. A university can be involved in either role with any conference.

21. Data Modeling – Category “Hard-ish”