1. CLOSE Please YOUR LAPTOPS, and get out your note-taking materials.
and turn off and put away your cell phones,
and get out your note-taking materials.

2. Sections 2.6 and 2.7
More Problem Solving

3. Solving Percent Problems
Note: “Per cent” means “per 100”. For example, 17% = 17/100 =
A percent problem has three different parts:
amount = percent x base
Any one of the three quantities may be unknown.
1. When we do not know the amount:
n = 10% · 500
2. When we do not know the base:
50 = 10% · n
3. When we do not know the percent:
50 = n · 500

4. Solving a Percent Problem: Amount Unknown
Example:
What is 9% of 65?
5.85 is 9% of 65

5. Solving a Percent Problem: Base Unknown
36 is 6% of what?
Example:
36 is 6% of 600

6. Solving a Percent Problem: Percent Unknown
Example:
24 is what percent of 144?

7. Percent Problem Tip:
If you’re having trouble doing percent problems that give you a new value after a certain percent increase or decrease from an old value (such as sales tax problems), try thinking about it this way: Think about when you go shopping to buy, say, a TV. Usually you know how much the TV costs, for example $400, and the percent tax rate, for example 5.5%. Normally what you do (or the salesclerk’s computer does) is calculate the TOTAL COST by taking 5.5% of $400, then adding that amount back onto the $400 price of the TV to get the total cost to you.

8. The working equation is PRICE + TAX = TOTAL COST
The working equation is PRICE + TAX = TOTAL COST. In words, here’s what you did (after writing the 5.5% as a decimal, 0.055): PRICE times PRICE = TOTAL COST Plugging in the numbers, we get x 400 = = 422. Notice that you’ve multiplied the OLD VALUE (the price before tax) by the .055.

9. The same basic format applies to anything with a percent increase or decrease from an original amount:
Old amount +/- % of old amount = new amount
(Remember to write the percent as a decimal.)
This equation works for raises in pay, population increases or decreases, and many other percent change problems, especially where you’re given the new amount and the percent change and you need to work backwards to find out the old amount.

10. Example:
After a 6% pay raise, Nora’s 2013 salary is $39,703. What was her salary in 2012? (Round to the nearest dollar). Solution: Recall the equation: Old amount + % of old amount = new amount The “old amount” is her 2012 salary, which is unknown, so we’ll call it X. This gives us the equation X X = 39703

11. Example (cont.)
After a 6% pay raise, Nora’s 2013 salary is $39,703. What was her salary in 2012? (Round to the nearest dollar). 1X X = This simplifies to 1.06X = Divide both sides X = by 1.06 to get X Answer: Her 2012 salary was $37,456

12. Now check your answer:
x = = 
NOTE that this DOES NOT give you the same answer as if you subtracted 6% of the new salary (39703) from the new salary.
Try it and you’ll see that it doesn’t work.
(It’s not real far off, but enough to give you the wrong answer, and the bigger the percentage, the farther off you’ll be.)
On these kinds of problems, we won’t give partial credit for those “close” answers on tests.

13. Sample problem from today’s homework:
In 2006, the population of the country was 31.2 million. This represented an increase
in population of 3.2% since What was the population of the country in 2001?
Round to the nearest hundredth of a million.

14. Solving Mixture Problems
Example:
The owner of a candy store is mixing candy worth $6 per pound with candy worth $8 per pound. She wants to obtain 144 pounds of candy worth $7.50 per pound. How much of each type of candy should she use in the mixture?
Solution:
Let n = the number of pounds of candy costing $6 per pound.
Let 144 – n = candy costing $8 per pound.

15. Use a table to summarize the information.
Number of Pounds
Price per Pound
Value of Candy
$6 candy n 6 6n
$8 candy
144  n 8
8(144  n)
$7.50 candy
144
7.50
144(7.50)
6n + 8(144  n) = 144(7.5)
# of pounds of $6 candy
# of pounds of $8 candy
# of pounds of $7.50 candy

16. 6n + 8(144  n) = 144(7.5)
6n  8n = 1080
1152  2n = 1080
2n = 72
n = 36
She should use 36 pounds of the $6 per pound candy.
She should use 108 pounds of the $8 per pound candy.
(144  n) = 144  36 = 108

17. Check: Will using 36 pounds of the $6 per pound candy and 108 pounds of the $8 per pound candy yield 144 pounds of candy costing $7.50 per pound?
6(36) + 8(108) = 144(7.5) ?
= 1080 ?
1080 = 1080 ? 

18. distance = rate · time or d = r · t
Distance Problems:
When the amount in the formula is distance, we refer to the formula as the distance formula.
distance = rate · time or d = r · t

19. Visit the MathTLC For homework help!
The assignment on this material (HW 2.6/7) is due at the start of the next class session.
Visit the MathTLC
For homework help!