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Grab a white board and try the Starter – Question 1
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Starter – Question 2 (c)
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(c)
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Differentiating Using The Quotient Rule
A2 Maths
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The Quotient Rule Aims: To be able to apply the quotient rule in order to differentiate y=f(x)/g(x) To successfully answer exam questions using the chain, product and quotient rules.
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Bilborough College Maths - Core 3 differentiation: the product rule (Adrian)
05/05/2018 Quotient rule If Then “The derivative of the top times the bottom, minus the derivative of the bottom times the top, divided by the bottom function squared.”
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The rule can also be written using function
Bilborough College Maths - Core 3 differentiation: the product rule (Adrian) 05/05/2018 Quotient rule The rule can also be written using function Given The derivative is
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Example 1 Differentiate y = Let u = 1+x2 and v = 1+ex
Bilborough College Maths - Core 3 differentiation: the product rule (Adrian) 05/05/2018 Example 1 Differentiate y = Let u = 1+x and v = 1+ex Then differentiate each one Finally apply the rule ……………
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Bilborough College Maths - Core 3 differentiation: the product rule (Adrian)
05/05/2018 Example 1 (cont’d)
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Example 2 Differentiate to find . Solution: and
We now need to simplify.
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Now collect like terms:
Example 2 (cont’d) We could simplify the numerator by taking out the common factor x, but it’s easier to multiply out the brackets. We don’t touch the denominator. Now collect like terms: and factorise: We leave the brackets in the denominator. ( A factorised form is considered to be simpler. ) Multiplying out numerator:
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Quotients can always be turned into products.
e.g. can be written as However, differentiation is usually more awkward if we do this. In the quotient above, and ( both simple functions ) In the product , and ( v needs the chain rule )
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TARSIA TIME!!
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Bilborough College maths - core 3 quotient rule (Adrian)
05/05/2018 Exercise Use the quotient rule, where appropriate, to differentiate the following. Try to simplify your answers: 1. 2. 3.
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Bilborough College maths - core 3 quotient rule (Adrian)
05/05/2018 1. Solution: and
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Bilborough College maths - core 3 quotient rule (Adrian)
05/05/2018 2. Solution: and
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Bilborough College maths - core 3 quotient rule (Adrian)
05/05/2018 3. Solution: Divide out:
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SUMMARY To differentiate a quotient: Check if it is possible to divide out. If so, do it and differentiate each term. Otherwise use the quotient rule: If , where u and v are both functions of x
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Core 3 textbook Page 97 Exercise D
Independent Study Core 3 textbook Page 97 Exercise D DUE: NEXT LESSON!
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