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Three-Phase Systems Professor Mohamed A. El-Sharkawi

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1 Three-Phase Systems Professor Mohamed A. El-Sharkawi
of Washington

2 El-Sharkawi@University of Washington

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Single Phase of Washington

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AC Waveform One Cycle Voltage or Current Peak Maximum Time of Washington of Washington

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ac Waveform of Washington of Washington

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AC Representation w t v of Washington of Washington

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How AC is Generated Stator N S Rotor Windings of Washington of Washington

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X N S ϕ 900 2700 Angle 1800 3600 of Washington of Washington

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Alternating Current v N S N S N S N S . N S N S N S N S N S of Washington of Washington

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Reference V2 w t v 1 2 q of Washington of Washington

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Reference V2 w t v 1 2 q of Washington of Washington

14 v i Voltage and Current can be Out of Phase
load V I + _ i v q w t V I is the phase shift of current also known as the power factor angle It is due to the presence of inductive and capacitive elements. of Washington of Washington

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Example If V=120 V and Z=4 + j3 , calculate the current and power factor. V Z I + _ Lagging V I Notice that the pf angle is the angle of the impedance of Washington of Washington

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Polarities Z I + _ Load V I + _ Source of Washington of Washington

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Three-Phase of Washington

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Three-Phase va N S N S N S N S N S N S N S N S I b vb I a vc I c of Washington of Washington

19 Three-Phase Generator
of Washington

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Three-phase system v aa' bb' cc' Reference 120o vaa’ vbb’ vcc’ 120o 120o Time of Washington of Washington

21 Why do we use 3-phase systems?
Three-phase system produces rotating magnetic field. Three-phase motors can start without the need for extra equipment. For the same physical size, a three-phase generator produces more power than a single phase generator. Three-phase lines transmit more power. Three-phase lines are more reliable. In distribution circuit, you can operate the system with one missing phase. of Washington of Washington

22 c b a ¢ ¢ c b ¢ a How is Three-Phase System Connected? X X X
of Washington of Washington

23 How is Three-Phase System Connected?
Any three-phase generator has 6 terminal wires Transmitting 6 wire over a long distance is expensive Instead, three-wire system is used by connecting the six wires as Y or Delta of Washington of Washington

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Y-Connected Source a n c b X X c b X a of Washington of Washington

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Y-Connected Source of Washington of Washington

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Y-Connected Source c c v cn v an Reference n a v bn of Washington b

27 Delta-Connected Source
b X X c b X a of Washington of Washington

28 Delta () Connection: Source
of Washington of Washington

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32 Phase and LineVoltages
of Washington

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c Phase voltage v cn v an Reference a n a b v bn c b v an v bn v cn n of Washington of Washington

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cn c Line-to-line voltage v bc v ca n v an a n c b a Reference v ca v ab v bn b v ab v bc of Washington of Washington

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ca n v bn cn an v ab -v bn Reference v bc Reference v ab ca bc bn b n an a cn c of Washington of Washington

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Keep in mind Unless stated in the problems, the following assumptions are to be used: All voltages are line-to-line quantities All powers are for the three phases of Washington of Washington

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Example Let v ab Calculate the line-to-line voltage Vab v an Reference of Washington of Washington

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Main Conclusions Line-to-line voltage is greater than phase voltage by Line-to-line voltage leads phase voltage by of Washington of Washington

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Y-Load connection Load Most loads are connected in Y To have access to the ground potential To balance the voltage across the load Each load impedance (Z) is called load impedance Voltage across the load impedance is called load voltage Load current a + Three-phase feeder I Z a I b n Z Z + + b I c of Washington of Washington

40 Main Conclusions for Y-Connected Load
Load voltage is equal to the Phase voltage Line current is equal to load current by of Washington of Washington

41 Delta-Load connection
Mostly in industrial loads No Access to ground Used to increase voltage across the load Each load impedance (Z) is called load impedance Voltage across the load impedance is called load voltage Load current a - + Three-phase feeder Ica Z Iab Z - + c Z b - + Ibc of Washington of Washington

42 Y-Connection Source and Load
Line current Transmission Line Source Load I Load current a a a + + I Z V I a an a I n b n V V Z Z cn bn + I c + + b c + b I I I b c c b I c of Washington of Washington

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For balanced system of Washington of Washington

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cn I c q n V an Reference I b q V bn I a q of Washington of Washington

45 Neutral Current of Balanced Load
I c For balanced system I a I b of Washington of Washington

46 Single-Phase Representation
Ia Va Va Z Ia + _ of Washington of Washington

47 Delta () Connection Source and Load
Line current Transmission Line Source Load Phase current I Load current a a a - + - + Ica Ica Z Iab Iab Z V ca V - ab + - + I c Z b c b b - + V bc Ibc - + Ibc I c of Washington of Washington

48 Delta () Connection: Source
Ia a _ Ica + Ia is line current Iab is generator current Vca Vab Iab _ Ib + b Vbc c _ + Ibc Ic of Washington of Washington

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Kirchhoff’s Current law at node a Transmission Line Load I Load current c c - + Ibc Ica Reference v bc ab ca a b c Z Z - q + I b Z a a - + Iab I q b q Voltage Diagram Vab is chosen reference of Washington of Washington

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Line Currents Reference v bc ab ca a b c V ab Refere q I ab q I ca I bc q q of Washington of Washington

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Line Currents V ab Refere q I ab 300 I ca -Ica I a of Washington of Washington

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Example Iab V ab q 300 Let Reference 100 I Calculate the phase current Iab of a delta circuit a of Washington of Washington

53 Main Conclusions for Delta-Connected Load
Load voltage is equal to the line-to-line voltage Line current is greater than load current by Line current lags the load current by of Washington of Washington

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Mixed Connection Line current Transmission Line Source Load Phase current I Load current a a a + I Z Ica a Iab V ca V I ab b n Z Z - I c b c b I b c V bc Ibc I c of Washington of Washington

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Y- Transformation a b c Ia Ib Ic Z a b c Ia Ib Ic ZY of Washington of Washington

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Y- Transformation of Washington of Washington

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Y- Transformation a b c Ia Ib Ic Z a b c Ia Ib Ic ZY THEN of Washington of Washington

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Example 1. Calculate the current of the load 2. Calculate the equivalent Y load 3. Calculate the load current of the equivalent Y load b c Ia Ic Van = 120 v a Ib Z = 4 + j 3 of Washington of Washington

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b c Ia Ic Van Ib Z Part 1: Part 2: Part 3: The load current in  load is equal to of Washington of Washington

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Example Calculate the line current Z2 = j 9 Z1 = 4 + j 3 Ia a b c Van = 120 v c b b c Ic of Washington of Washington

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Change delta to Y Z2y = 4 - j 3 Z1 = 4 + j 3 Ia a b c Van = 120 v b b c c Ic of Washington of Washington

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Zeq = 25/8  Ia a b c Van = 120 v b c Ic of Washington of Washington

63 Instantaneous Electric Power [p(t)]
V I Fixed average Zero average of Washington of Washington

64 Instantaneous Electric Power [p(t)]
of Washington of Washington

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Real Power (Average P) of Washington of Washington

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Real Power (Average P) p wt of Washington of Washington

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Reactive Power [Q] Important points! Frequency of h(t) is double the frequency of supply voltage Average value of h(t) is zero w t h(t) q p of Washington of Washington

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Real power Reactive power of Washington of Washington

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Complex Power (S) IMPORTANT  is the power factor angle V I Real Power Reactive Power of Washington of Washington

70 Power of 3-phase circuits
Iphase Vphase For Single phase IMPORTANT  is the angle between phase voltage and phase current. Use voltage as a reference For 3-phase of Washington of Washington

71 Real Power in Delta Circuit
b c Ia Ib Ic Iab Ica Ibc + _ of Washington of Washington

72 Reactive Power in Delta Circuit
b c Ia Ib Ic Iab Ica Ibc + _ of Washington of Washington

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Real Power in Y Circuit a b c Ia Ib Ic Va Vc Vb of Washington of Washington

74 Reactive Power in Y Circuit
b c Ia Ib Ic Va Vc Vb of Washington of Washington

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Example Calculate the load power b c Ia Ic Van = 120 v a Ib Z = 4 - j 3 of Washington of Washington

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b c Ia Ic Van Ib Z V ab I ca V an 300 q n I ab I bc 300 I a of Washington of Washington

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Method #1 Method #2 Keep in mind The pf angle is the angle of the load impedance. It is the same as the angle between the phase voltage and the phase current of Washington of Washington


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