1. Geometry Homework 5.3
Pages 282

2. 1) medians 8) 9 9) 12 10) 4 8 12) EP 2 8 = = EH 3 x PH 4 1 2x = 24
Geometry – page 282 // 5.3: 1, 8-10, 12
Medians, Centroids, & Altitudes of a 
1) medians
8) 9
9) 12
10) 4 E D F G J H P 8
7.5
12) EP
= =
EH x PH
2x = 24
x = 12
EH = 12
PH = 4
Find
= = EH PH
= = EP

3. Geometry Homework 5.4
Pages 290

4. 1) midsegments 12) BC 3) DF 13) MN GH 14) 10 21.2 15) 14 12 16) 9 16
Geometry – page 290 // 5.4: 1, 3-8, 12-18
Midsegment Theorem
1) midsegments
3) DF GH
21.2 12 16 8
12) BC
13) MN
14) 10
15) 14
16) 9
17) 31
18) 6

5. Geometry Homework 5.5
Pages

6. 1) 90˚  is opposite the 2 1/8 in. side
Geometry – pages // 5.5: 1-6, 8-9, 11, 14, 16-17, 19, 25
Inequalities in a 
1) 90˚  is opposite the 2 1/8 in. side
62˚  is opposite the 1 7/8 in. side
28˚  is opposite the 1 in. side
2) No; is not greater than 8.
3)  D,  F
EF, DE
greater than 66 miles and less than 264 miles

7. 6) AC, AB 8) JK, HJ 9)  C,  B 11)  H,  F 14) AB, BC, AC
Geometry – pages // 5.5: 1-6, 8-9, 11, 14, 16-17, 19, 25
Inequalities in a 
6) AC, AB
8) JK, HJ
9)  C,  B
11)  H,  F
14) AB, BC, AC
16) AB, BC, AC
17)  L,  K,  M
19)  T,  S,  R
25) x < 7

8. Geometry Homework 5.6
Pages 305

9. Geometry – pages 305 // 5.6: 3-5, 7-15, 16-17, 19
Comparing 2 
16) C; AD = AD, BD = CD, and AC > AB, so by the Converse Hinge Thm, m4 < m5.
17) B; AD = AD, AB = DC, and m3 < m5, so by the Hinge Thm, AC > BD.
19) x > 1
3) >
<
7) <
8) =
9) >
10) >
11) =
12) <
13) >
14) >
15) >

10. Geometry Homework 5 Review
Pages

11. 2) U is on the  bisector of RT. 3) Q is on the bisector of RST. 20 6
Geometry – page // 5 Review: 2-9, 15-16, 18,
Page 308: 1-3.
2) U is on the  bisector of RT.
3) Q is on the bisector of RST. 20 6
 bisectors; incenter
 bisectors; circumcenter
medians; centroid
altitudes; orthocenter

12. 15) 31 16) mC, mA, mB; AB, BC, AC 18) mH, mJ, mG; JG, GH, JH
Geometry – page // 5 Review: 2-9, 15-16, 18,
Page 308: 1-3.
15) 31
16) mC, mA, mB; AB, BC, AC
18) mH, mJ, mG; JG, GH, JH
20) 600 feet; the third side must be less than 300 ft long (100 ft ft = 300 ft), so the total fencing is less than 100 ft ft ft = 600 ft
21) <
22) <
23) =

13. Geometry – page 310-312 // 5 Review: 2-9, 15-16, 18, 20-23.
1) CE
2) 16
3) 21