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Transportation Engineering Horizontal curve concepts March 28, 2011

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Presentation on theme: "Transportation Engineering Horizontal curve concepts March 28, 2011"— Presentation transcript:

1 Transportation Engineering Horizontal curve concepts March 28, 2011

2 ANNOUNCEMENTS

3 Homework 4 due next Wednesday
WyoSUITE forms No class Wednesday.

4 EVALUATION RESULTS

5 Pace: Slow: 1 OK: 23 Fast: 2

6 Most unclear concept: Signal design was the clear winner here. Recommendation: take a close look at the solutions to Homework 3

7 Most helpful things: Examples in class Things I can do better/other comments: Even more examples Even more homework Powerpoints can be ambiguous Notation for grade: %G vs G Funnier examples in class Review before next exam

8 REVIEW

9 The shape of a vertical curve is usually parabolic. Why?
PVI A = –8 G2= -5 G1= +3 L PVT PVC

10 Design a vertical curve that can be safely traversed at 70 mi/hr, assuming 2.5 s reaction time and coefficient of braking friction 0.348 G1= -2 G2= +4 PVI: Elevation 7250 ft

11 Coefficient of friction is 0
Coefficient of friction is 0.348; only one direction of travel from left to right. What is maximum safe speed? G2= -3 G1= +5 500 ft

12 Step 1: Find SSD from curve length:
SSD < L: SSD > L: G2= -3 G1= +5 500 ft

13 HORIZONTAL CURVE CONCEPTS

14 Now switching to an overhead view
Now switching to an overhead view... what shape should a horizontal curve have?

15 Now switching to an overhead view
Now switching to an overhead view... what shape should a horizontal curve have?

16 Point of intersection Point of tangency Point of curvature

17 PI PT Radius of curvature Intersection angle PC

18 Tangent length PI D PT Chord length R D/2 PC D

19 External distance PI D Middle ordinate PT T C R D/2 PC D

20 PI D E PT T M C R D/2 PC D

21 Another question: what angle is swept out by 100 ft of roadway?
This is the degree of curve D 100 ft R D

22 In radians In degrees 100 ft R D

23 Assorted formulae PI D E PT T M D/2 C PC R Curve length D

24 How do we describe a horizontal curve?
At PC, PT, and every whole station in between: provide deflection angle and chord length PT Deflection angle is measured from the initial tangent PC

25 How do we describe a horizontal curve?
At PC, PT, and every whole station in between: provide deflection angle and chord length PT The chord is measured from the last whole station (or PC for the first point) PC

26 EXAMPLE

27 Given a 4-degree curve with an intersection angle 55°25' with PC at station 238+44.75...
what is the length of curve, the station of PT, and the deflection and chord lengths?

28 Assorted formulae PI D E PT T M D/2 C PC R Curve length D

29 Curve length: use and PI D E PT T M C D/2 PC R D
R = 1432 ft and L = 1385 ft PI D E PT T M D/2 C PC R D

30 To find deflection angles and chord lengths, apply the formulas to a segment of the curve:
PT D/2 R PC D

31 In this example, PC is at 238+44
In this example, PC is at , so the distance to the next whole station is ft. Using L = 55.25 and gives D = 2.21° The deflection is half of this, or 1°6'18" PT D/2 R PC D

32 Using the chord formula:
PT D/2 R PC D

33 Final answer: Station Deflection angle Chord length (ft) 238+44.75
239+00 1°6'18" 55.25 240+00 3°6'18" 99.98 ... 252+00 27°6'18" 27°42'30" 30.17


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