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Warm-Up Any questions about homework?
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Agenda: Factoring Sum and Difference of Cubes Factor Relays Homework
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Factoring Sum and Difference of Cubes
βPatternsβ π 3 + π 3 =(π+π)( π 2 βππ+ π 2 ) π 3 β π 3 =(πβπ)( π 2 +ππ+ π 2 ) Remember signs: same-different-positive
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1. π₯ A = x b =5 2. π₯ 3 β27 A = x b =3 π 3 + π 3 π 3 β π 3 (π₯) 3 + (5) 3 (π₯) 3 β (3) 3 (π+π)(π 2 βππ+ π 2 ) (πβπ)(π 2 +ππ+ π 2 ) (π₯+5)(π₯ 2 β5π₯+25) (π₯β3)(π₯ 2 +3π₯+9)
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3. 8 π₯ A = 2x b =7 4. 64 π₯ 4 β27π₯ A = 4x b =3 π 3 + π 3 x(64 π₯ 3 β27) (2π₯) 3 + (7) 3 π₯(π 3 β π 3 ) (π+π)(π 2 βππ+ π 2 ) π₯((4π₯) 3 β ) (2π₯+7)((2π₯) 2 β14π₯+49) π₯(πβπ)(π 2 +ππ+ π 2 ) (2π₯+7)(4π₯ 2 β14π₯+49) x (4π₯β3)(16π₯ 2 +12π₯+9)
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Other Cubics by Grouping
5. 12π₯ 3 β 9π₯ 2 +4π₯ β3 6. 2π₯ 3 + 5π₯ 2 +6π₯+15 3π₯ 2 (4π₯ β3) +1(4π₯ β3) π₯ 2 (2π₯+5) +3(2π₯+5) (3 π₯ 2 +1)(4π₯ β3) ( π₯ 2 +3)(2π₯+5) 7. 10π 3 β 20π 2 +6π β12 2( 5π 3 β 10π 2 +3π β6) 5π 2 (πβ2) +3(πβ2) 2( 5π 2 +3)(πβ2)
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Factor Relays Directions: Get into groups of 4
As a new questions appears you have a new spokesperson for the group Work as a team to get the answer Spokesperson runs up to the board and writes their answer (make sure to keep it covered If your team gets it right, you get one point
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5 π₯ 2 +5π₯ β10 5(π₯+2)(π₯β1)
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2 π 3 β π 2 +2π β1 (2π₯β1)( π₯ 2 +1)
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18 π₯ 2 β2 2(3π₯β1)(3π₯+1)
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2 π 2 +12π β16 2( π 2 +6πβ8)
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125 π₯ 3 β216 (5π₯β6)(25 π₯ 2 +30π₯+36)
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β π£ 2 +2π£ β1 β (π£β1) 2
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π₯ 3 +64 (π₯+4)( π₯ 2 β4π₯+16)
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5 π 2 +4π β12 (5π₯β6)(π₯+2)
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π£ 3 β 4π£ 2 +4π£ β16 (π₯β4)( π₯ 2 +4)
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2 π 7 β32 π₯ 3 2 π₯ 3 (π₯+2)(π₯β2)( π₯ 2 +4)
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25 π₯ 2 β10π₯+1 (5π₯β1) 2
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π₯ 4 β10 π₯ 2 +16 ( π₯ 2 +2)( π₯ 2 +8)
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6 π¦ π¦ 2 +15π₯ 3π₯(π₯+1)(2π₯+5)
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