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SOLVING ONE-VARIABLE EQUATIONS •. Goal: Find the one value
SOLVING ONE-VARIABLE EQUATIONS • Goal: Find the one value of the variable that makes the sentence true.
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•. We can solve equations by. doing the OPPOSITE of what
• We can solve equations by doing the OPPOSITE of what has been done to the variable in the problem. • If a problem says +, you subtract. • If a problem has multiplication, you divide.
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By doing the opposite, we keep the sides of the equation balanced.
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5x – 13 = 52
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5x – 13 = x = 65
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5x – 13 = x = x = 13
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12x = 2127
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12x = x = 27.75
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963 – 25x = 704
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963 – 25x = x = 10.36
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What about this? 𝑦 5 −13=2
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What about this? 𝑦 5 −13=2 Fractions mean division, so to cancel, we’ll add 13 and then multiply by n = 75
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Things that can complicate solving equations …
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Parentheses •. Use distributive property. first. Like terms •
Parentheses • Use distributive property first. Like terms • Combine them first.
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4(3x – 7) = 48
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4(3x – 7) = x – 28 = 48
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4(3x – 7) = x – 28 = 48 12x = x = 6.333…
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-7(2x – 11) = 98
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-7(2x – 11) = 98 -14x + 77 = 98 -14x = 21 x = -3/2 or -1.5
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4p + 3 – 2p p + 2 = 17
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4p + 3 – 2p p + 2 = p + 12 = p = p = 5/7
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5(3x + 5) – 3(2x – 1) = 145
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5(3x + 5) – 3(2x – 1) = x + 25 – 6x + 3 = 145
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5(3x + 5) – 3(2x – 1) = x + 25 – 6x + 3 = x + 28 = 145
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5(3x + 5) – 3(2x – 1) = 145 15x + 25 – 6x + 3 = 145 9x + 28 = 145 9x = 117 x = 13
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The goal is always to simplify
The goal is always to simplify. Make the problem look like the easy ones we know how to solve.
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Variable on Both Sides • Find the smaller number of the variable, and subtract that on both sides. • Solve the remaining problem.
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5x – 15 = 2x + 72
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5x – 15 = 2x x x 3x – 15 =
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7x – 15 = 2x x x 3x – 15 = x = x =
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5x + 13 = 7x + 40
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5x + 13 = 7x x x = 2x + 40
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5x + 13 = 7x x x = 2x x = -27/2 or -13.5
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3(2x + 7) = 3x x + 9
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3(2x + 7) = 3x x x + 21 = 4x + 13
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3(2x + 7) = 3x + 4 + x + 9 6x + 21 = 4x + 13 2x + 21 = 13 2x = -8 x = -4
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Special equations 2(3x – 7) = 6x + 11 10x – 15 = 5(2x – 3)
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2(3x – 7) = 6x x – 14 = 6x ?????
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10x – 15 = 5(2x – 3) 10x – 15 = 10x – ?????
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When variables cancel out… •. If you have the exact
When variables cancel out… • If you have the exact same thing on both sides (like 8 = 8), the answer is ALL REAL NUMBERS or INFINITELY MANY SOLUTIONS. 10x – 15 = 5(2x – 3) 10x – 15 = 10x – = -15
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An equation with infinitely many solutions can also be called an IDENTITY.
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•. If there is something. different on the 2 sides
• If there is something different on the 2 sides (like 5 = 7), there is NO SOLUTION. 2(3x – 7) = 6x x – 14 = 6x = 11
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•. If there is something. different on the 2 sides
• If there is something different on the 2 sides (like 5 = 7), there is NO SOLUTION. 2(3x – 7) = 6x x – 14 = 6x = 11
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