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GCSE Right-Angled Triangles
Skipton Girls’ High School Learning Objectives: To be able to find missing sides and missing angles in right-angled triangles and 3D shapes. Last modified: 2nd March 2014
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For any right-angled triangle with longest side c.
Pythagoras’ Theorem ! Hypotenuse (the longest side) For any right-angled triangle with longest side c. a2 + b2 = c2 c b a
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x 4 2 22 + 42 = x2 x2 = 4 + 16 = 20 x = √20 = 4.47 to 2dp Example
Step 1: Determine the hypotenuse. x Step 2: Form an equation 2 = x2 The hypotenuse appears on its own. 4 Step 3: Solve the equation to find the unknown side. x2 = = 20 x = √20 = 4.47 to 2dp
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h 7 3 x 5 4 Pythagoras Mental Arithmetic ℎ= 3 2 + 5 2 = 34
We’ve so far written out the equation 𝑎 2 + 𝑏 2 = 𝑐 2 , filled in our information, and rearranged to find the missing side. But it’s helpful to be able to do it in our heads sometimes! If you’re looking for the hypotenuse Square root the sum of the squares If you’re looking for another side Square root the difference of the squares h 7 3 x 5 4 ℎ= = 34 ? 𝑥= − 4 2 = 33 ?
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10 h 12 4 5 y 9 q 1 x 2 2 Pythagoras Mental Arithmetic
? ? ℎ= =13 𝑦= − 4 2 = 84 9 q 1 x 2 2 𝑥= − 2 2 = 77 ? 𝑞= = 5 ?
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The Wall of Triangle Destiny
Answer: 𝐱= 𝟐 ? 5 2 3 Answer: 𝐱=𝟏𝟎 ? 42 1 6 1 1 x x x 6 4 x x 4 55 12 Answer: 𝐱= 𝟐𝟎 ? 8 10 Answer: 𝐱= 𝟒𝟕𝟖𝟗 ? Answer: 𝐱= 𝟒𝟒 ? “To learn secret way of ninja, find x you must.”
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Exercise 1 Give your answers in both surd form and to 3 significant figures. 4 7 1 13 13 x 18 12 6 y 10 8 x = 65 = 13.4 ? Find the height of this triangle. ? x = 10 5 2 x 6 12 ? 10 y N x 4 3 7 ? x = 43 = 6.56 9 x = 51 = 7.14 ? 7 1 6 3 x x x 2 1 x = 81 – x2 x = 4 ? 5 1 x = 29 = 5.39 ? ? x = 3 = 1.73
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Areas of isosceles triangles
To find the area of an isosceles triangle, simplify split it into two right-angled triangles. 13 1 1 13 3 2 ? 12 ? 10 1 Area = 60 ? Area = 3 4 ?
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Exercise 2 Determine the area of the following triangles. 12 1 3 5 5 5 17 17 7 12 6 16 Area = 12 ? Area = 120 ? Area = 40.2 ? 2 4 4 4 1 1 1.6 4 Area = 0.48 ? ? Area = 212 = 43 = 6.93
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Names of sides relative to an angle
? hypotenuse opposite ? 30° adjacent ?
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Names of sides relative to an angle
Hypotenuse Opposite Adjacent x y z √2 1 c a b x ? ? ? 60° z y ? ? ? 1 √2 45° 1 ? ? ? c 20° a b
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“soh cah toa” sin 𝜃 = 𝑜 ℎ cos 𝜃 = 𝑎 ℎ tan 𝜃 = 𝑜 𝑎 Sin/Cos/Tan
sin, cos and tan give us the ratio between pairs of sides in a right angle triangle, given the angle. sin 𝜃 = 𝑜 ℎ ? θ o h a cos 𝜃 = 𝑎 ℎ ? tan 𝜃 = 𝑜 𝑎 ? “soh cah toa”
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One way to remember this…
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tan(45) = 1 Example ? opposite ? ? 45 adjacent
Looking at this triangle, how many times bigger is the ‘opposite’ than the ‘adjacent’ (i.e. the ratio) ? Ratio is 1 (they’re the same length!) Therefore: opposite tan(45) = 1 ? ? 45 adjacent
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Find 𝑥 (to 3sf) More Examples ? ? 20 ° 7 x 40 ° 4 x 𝑥=3.06 𝑥=2.39
Step 1: Determine which sides are hyp/adj/opp. Step 2: Work out which trigonometric function we need. Find 𝑥 (to 3sf) 20 ° 7 x 40 ° 4 x 𝑥=3.06 ? 𝑥=2.39 ?
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More Examples 60 ° x 12 𝑥=24 ? 30° 4 x 𝑥=8 ?
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Exercise 3 1 Find 𝑥, giving your answers to 3𝑠𝑓. Please copy the diagrams first. 𝟕𝟎° 15 𝒙 𝟒𝟎° 22 𝒙 𝑥=16.9 ? 𝟖𝟎° 20 𝒙 𝑥=20.3 ? a b c 𝑥=14.1 ? 𝟕𝟎° 4 𝒙 𝟕𝟎° 𝒙 𝟒 𝟓𝟓° 10 𝒙 f d e 𝑥=11.0 ? 𝑥=7.00 ? 𝑥=11.7 ? 2 I put a ladder 1.5m away from a tree. The ladder is inclined at 70° above the horizontal. What is the height of the tree? 𝟒.𝟏𝟐𝒎 Ship B is 100m east of Ship A, and the bearing of Ship B from Ship A is 30°. How far North is the ship? 𝟏𝟎𝟎÷ 𝐭𝐚𝐧 𝟑𝟎 =𝟏𝟕𝟑.𝟐𝒎 Find 𝑥 𝒙= 𝟏 𝟑 −𝟏 ? 3 ? 𝟑𝟎° 𝒙 𝒙+𝟏 ? 4
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We can do the ‘reverse’ of sin, cos or tan to find the missing angle.
But what if the angle is unknown? 𝒂 3 5 sin 𝑎 = 3 5 𝑆𝑜 𝑎= sin − =36.9° ? ? We can do the ‘reverse’ of sin, cos or tan to find the missing angle.
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What is the missing angle?
Quiz What is the missing angle? 𝟓 𝒂 𝟒 cos − cos − cos − sin −
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What is the missing angle?
𝒂 𝟏 𝟐 cos − sin −1 2 tan −1 2 tan −
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What is the missing angle?
𝟓 𝟑 𝒂 cos − sin − tan − sin −
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What is the missing angle?
𝟑 𝒂 𝟐 cos − sin − sin − tan −
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The Wall of Trig Destiny
? 𝜃=45° 2 3 1 1 1 1 θ θ ? 𝜃=48.59° 4 2 3 6 θ 8 ? 𝜃=70.53° 3 θ ? 𝜃=33.7° “To learn secret way of math ninja, find θ you must.”
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3D Pythagoras- not usually tested but a higher level
The strategy here is to use Pythagoras twice, and use some internal triangle in the 3D shape. Determine the length of the internal diagonal of a unit cube. 1 ? √3 1 √2 ? Click to Sketch 1
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Test Your Understanding
The strategy here is to use Pythagoras twice, and use some internal triangle in the 3D shape. Determine the length of the internal diagonal of a unit cube. 12 13 ? 4 3
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Test Your Understanding
Determine the height of this right* pyramid. 2 2 ? 2 2 * A ‘right pyramid’ is one where the top point is directly above the centre of the base, i.e. It’s not slanted.
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Exercise 4 Determine the length x in each diagram. Give your answer in both surd for and as a decimal to 3 significant figures. 2 2 1 x 3 N1 1 13 2 x x 2 2 2 6 3 8 2 2 x = 14 = 3.74 ? x = 12 ? x = 28 = 5.29 ? 2 4 N2 x 4 8 1 x 1 x 5 6 2 4 1 x = 51 = 7.14 ? x = 45 = 6.71 ? Hint: the centre of a triangle is 2/3 of the way along the diagonal connecting a corner to the opposite edge. x = (2/3) = 0.816 ?
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