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Objective 7.04 Apply Built-in String Functions (3%)

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Presentation on theme: "Objective 7.04 Apply Built-in String Functions (3%)"— Presentation transcript:

1 Objective 7.04 Apply Built-in String Functions (3%)
Computer Programming I

2 Objective/Essential Standard
Essential Standard 7.00 Apply Advanced Logic Indicator 7.04 Apply Built-in String Functions (3%)

3 The String Class The String data type is a class.
A class includes properties and methods called members. When a class is used to create a variable, the variable is called an object. An object accesses a member of its class with a dot (.) between the object name and the member name.

4 Strings Remember with strings the first letter is at index position 0.
The last letter is always at the length of the string -1. The middle letter is always at the length of the string / School

5 String Class Properties
You can get the length of any string by using the Length property. intLength = strName.Length You can get any character that is part of the string by using the Chars property. chrLetter = strName.Chars(0) No ( )’s This must be an integer or integer variable that represents the index position.

6 String Class Functions
Visual Studio provides the programmer with multiple built-in functions from the String class, including the following: String Class Functions Compare() Concat() Equals() Format() IndexOf() Insert() The String class is not limited to these functions. Remove() Replace() ToLower() ToUpper() ToString() Trim(), TrimEnd(), TrimStart()

7 String Class Functions
Purpose Compare() Compares two specified String objects and returns an integer that indicates their relative position in the sort order Concat() Creates the string representation of a specified object, usually two or more strings Equals() Determines whether this instance and another specified String  object have the same value IndexOf() Reports the index of the first occurrence of the specified Unicode character (or string) in this string Insert() Inserts a specified instance of String at a specified index position in this instance Remove() Deletes all the characters from this string beginning at a specified position and continuing through the last position

8 String Class Functions
Purpose Replace() Returns a new string in which all occurrences of a specified string in the current instance are replaced with another specified string ToLower() Returns a copy of this string converted to lowercase ToUpper() Returns a copy of this string converted to uppercase Trim() Removes all leading and trailing white-space characters from the current String object TrimEnd() Removes all trailing occurrences of a set of characters specified in an array from the current String object TrimStart() Removes all leading occurrences of a set of characters specified in an array from the current String object

9 The Compare() Function
The Compare() function has several options. We will look at the most basic one. This method is typically used in an If statement. The comparison looks at the lexical relationship of the two strings. (lexical = an association between different words or meanings) String.Compare(strOne, strTwo) intNum Value after execution < 0 strOne is less than strTwo = 0 strOne equals strTwo >0 strOne is greater than strTwo

10 The Compare() Function
Let’s look at this table that tells us what the decimal equivalents of our characters are.

11 The Compare() Function
The Compare() function looks at these values. Example: strFirst = Apple A  strLast = Banana B  66 Code String.Compare (strFirst, strLast) Result – 66 = so String.Compare (strFirst, strLast) < 0 therefore Apple “comes before” Banana

12 The Compare() Function
Dim strA As String = "Apple" Dim strB As String = "Banana" If String.Compare(strA, strB) = 0 Then lblAnswer.Text = strA & " is equal to " & strB ElseIf String.Compare(strA, strB) < 0 Then lblAnswer.Text = strA & " comes before " & strB ElseIf String.Compare(strA, strB) > 0 Then lblAnswer.Text = strA & " comes after " & strB End If

13 The Concat() Function The concat() function will concatenate (merge) strings. Dim strA As String = "Apple" Dim strB As String = "Banana" Dim strNew As String strNew = String.Concat(strA, strB) lblAnswer.Text = strNew ‘strNew = AppleBanana

14 The Equals() Function The Equals function returns a Boolean value (true or false) after comparing the values of two strings. Dim strA As String = "Apple" Dim strB As String = "Banana" If strA.Equals(strB) Then lblAnswer.Text = "The strings are the same." Else lblAnswer.Text = "The strings are the different." End If

15 The IndexOf() Function
The IndexOf() function has several different variations that will return the index position of a character or string. Dim strA As String = "Apple" Dim intIndex As Integer intIndex = strA.IndexOf("p") ‘intIndex = 1 lblAnswer.Text = intIndex

16 The Insert() Function The Insert() function inserts a string at a specified index position. Dim strA As String = "Apple" Dim strNew As String strNew = strA.Insert(5, "s") ‘strNew = Apples lblAnswer.Text = strNew

17 The Remove() Function The Remove() function returns a new string where the specified string has been deleted. Remove() has two options that will delete all of a string or a specified number of characters. Remove(intStartIndex) intStart represents the index position to start removing characters This option will remove all letters from the starting index position to the end. Remove(intStartIndex, intNumCharsToRemove) This option will remove all letters starting at the start index position and removing the given number of characters.

18 The Remove() Function ‘displays anana as Apple is deleted completely
Dim strA As String = "Apple" Dim strB As String = "Banana" Dim strNew, strNew2 As String strNew = strA.Remove(0) strNew2 = strB.Remove(0, 1) lblAnswer.Text = strNew2 & " " & strNew ‘displays anana as Apple is deleted completely

19 The Replace() Function
The Replace() function returns a new string that has the specified string or character replaced in all occurences. Dim strA As String = "Apple" Dim strB As String = "Banana" Dim strNew, strNew2 As String strNew = strA.Replace("p", "b") strNew2 = strB.Replace("n", "") lblAnswer.Text = strNew & " " & strNew2 ‘ displays abble Baaa

20 The ToLower() Function
The ToLower() function returns a copy of the string in lowercase. Dim strA As String = "Apple“ lblAnswer.Text = strA.ToLower ‘Displays apple

21 The ToUpper() Function
The ToUpper() function returns a copy of the string in uppercase. Dim strA As String = "Apple“ lblAnswer.Text = strA.ToUpper ‘Displays APPLE

22 The Trim() Function The Trim() function removes all leading and trailing blanks from the string. Dim strA As String = " Apple " Dim strEx As String = "Example: " Dim strNew As String strNew = strA.Trim lblAnswer.Text = strEx & strNew ‘Displays Example: Apple

23 The TrimEnd() Function
The TrimEnd() function deletes all blanks from the end of the string. Dim strA As String = " Apple " Dim strEx As String = "Example: " Dim strNew As String strNew = strA.TrimEnd lblAnswer.Text = strEx & strNew ‘Displays Example: Apple

24 The TrimStart() Function
The TrimStart() function deletes all blanks from the beginning of the string. Dim strA As String = " Apple " Dim strEx As String = "Example: " Dim strNew As String strNew = strA.TrimStart lblAnswer.Text = strEx & strNew ‘Displays Example: Apple

25 Try It! Create a new application called stringExample
Save it into the location as instructed by your teacher. Add the following controls. When the button is clicked, the appropriate answer should be displayed in the lblAnswer label. For the following functions you will only use the first textbox when clicking the button to display the answer ToLower, ToUpper Trim, TrimEnd, TrimStart For functions such as Replace and Insert, use the first textbox as “Word” input and the second textbox as the input to delete/replace/remove, etc.

26 Try It! Control Name Text/Items Label lblPrompt1 Enter a Word:
Button btnCompare Compare btnConcat Concat btnEquals Equals btnInsert Insert btnRemove Remove btnReplace Replace btnToLower ToLower btnToUpper ToUpper btnTrim Trim btnTrimEnd TrimEnd btnTrimStart TrimStart

27 Try It! Solution – Visual Basic
Private Sub btnCompare_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnCompare.Click Dim strA As String = Me.txtWord1.Text Dim strB As String = Me.txtWord2.Text If String.Compare(strA, strB) = 0 Then lblAnswer.Text = strA & " is equal to " & strB ElseIf String.Compare(strA, strB) < 0 Then lblAnswer.Text = strA & " comes before " & strB ElseIf String.Compare(strA, strB) > 0 Then lblAnswer.Text = strA & " comes after " & strB End If End Sub Private Sub btnConcat_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnConcat.Click Dim strNew As String strNew = String.Concat(strA, strB) lblAnswer.Text = strNew

28 Try It! Solution Private Sub btnEquals_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnEquals.Click Dim strA As String = Me.txtWord1.Text Dim strB As String = Me.txtWord2.Text If strA.Equals(strB) Then lblAnswer.Text = "The strings are the same." Else lblAnswer.Text = "The strings are the different." End If End Sub Private Sub btnReplace_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnReplace.Click Dim strNew, strNew2 As String strNew = strA.Replace(strB, "b") lblAnswer.Text = strNew & " " & strNew2

29 Try It! Solution Private Sub btnIndexOf_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnIndexOf.Click Dim strA As String = Me.txtWord1.Text Dim strB As String = Me.txtWord2.Text Dim intIndex As Integer intIndex = strA.IndexOf(strB) lblAnswer.Text = intIndex End Sub Private Sub btnInsert_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnInsert.Click Dim strNew As String strNew = strA.Insert(5, "s") lblAnswer.Text = strNew Private Sub btnRemove_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnRemove.Click Dim strNew, strNew2 As String strNew = strA.Remove(0) strNew2 = strB.Remove(0, 1) lblAnswer.Text = strNew2 & " " & strNew

30 Try It! Solution Private Sub btnToLower_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnToLower.Click Dim strA As String = Me.txtWord1.Text Dim strB As String = Me.txtWord2.Text lblAnswer.Text = strA.ToLower End Sub Private Sub btnToUpper_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnToUpper.Click lblAnswer.Text = strA.ToUpper Private Sub btnTrim_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnTrim.Click Dim strEx As String = "Example: " Dim strNew As String strNew = strA.Trim lblAnswer.Text = strEx & strNew

31 Try It! Solution Private Sub btnTrimEnd_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnTrimEnd.Click Dim strA As String = Me.txtWord1.Text Dim strB As String = Me.txtWord2.Text Dim strEx As String = "Example: " Dim strNew As String strNew = strA.TrimEnd lblAnswer.Text = strEx & strNew End Sub Private Sub btnTrimStart_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnTrimStart.Click strNew = strA.TrimStart

32 Conclusion This PowerPoint provided an overview of several methods in the String class. For more information on this topic


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