1. If the areas are A1 and A-A1.
C µF, q = 28.8 µC
C2 C24 = 12 µF
C1234 = 3 µF q =36 µC

2. The force on a filling dielectric as it is inserted between the parallel plates of a capacitor.x L
With the battery connected,
U1 = ½CV2
With the battery disconnected,
U2 = Q2/2C
With the battery connected, since x is increasing downwards, a negative force is upwards, pushing the dielectric away.
With the battery disconnected, the force is positive and pointed downwards, pulling in the dielectric.
The force is proportional to (κ-1) and inversely to L.

3. Chapter 26 Current and Resistance
In this chapter we will introduce the following new concepts:
-Electric current ( symbol i ) Electric current density vector (symbol ) Drift speed (symbol vd ) Resistance (symbol R ) and resistivity (symbol ρ ) of a conductor -Ohmic and non-Ohmic conductors
We will also cover the following topics:
-Ohm’s law Power in electric circuits
(26 - 1)

4. HITT
The plate areas and plate separations of five parallel plate capacitors are
capacitor 1: area A0, separation d0
capacitor 2: area 2A0, separation 2d0
capacitor 3: area 2A0, separation d0/2
capacitor 4: area A0/2, separation 2d0
capacitor 5: area A0, separation d0/2
Rank these according to their capacitances, least to greatest.
a. 1,2,3,4,5 b. 5,4,3,2,1 c. (524) ,(13) d. 4, (12), 5,3
e. None of these d

5. A B
(26 - 2)

6. (26 - 3) i
+ q
conductor i
- q
conductor

7. i
+ q
conductor A i
- q
conductor A
(26 - 4)

8. (26 - 5)

9. + - i V R
(26 - 6)

10. + - i V
(26 -7)

11. (26 -8)

12. (26 - 9)

13. ( )

14. ( )

15. ( )

16. V
( )

17. hitt
To store a total of J of energy in the two identical capacitors shown, each should have a capacitance of:
A μF
B μF, μF
C. 1.0 μF
D. 1.5 μF
E. 2.0 μF