1. A. Kinetic Molecular Theory
Particles in an ideal gas…
have no volume.
have elastic collisions.
are in constant, random, straight-line motion.
don’t attract or repel each other.
have an avg. KE directly related to Kelvin temperature.
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2. B. Real Gases Particles in a REAL gas… Gas behavior is most ideal…
have their own volume
attract each other
Gas behavior is most ideal…
at low pressures
at high temperatures
in nonpolar atoms/molecules

3. C. Characteristics of Gases
Gases expand to fill any container.
random motion, no attraction
Gases are fluids (like liquids).
no attraction
Gases have very low densities.
no volume = lots of empty space

4. C. Characteristics of Gases
Gases can be compressed.
no volume = lots of empty space
Gases undergo diffusion & effusion.
random motion

5. K = ºC + 273 D. Temperature ºF ºC K -459 32 212 -273 100 273 373
Always use absolute temperature (Kelvin) when working with gases. ºF ºC K
-459 32
212
-273
100
273
373
K = ºC + 273

6. Standard Temperature & Pressure
F. STP
STP
Standard Temperature & Pressure
0°C K
1 atm kPa
-OR-

7. II. The Gas Laws BOYLES CHARLES GAY-LUSSACP V T
Ch Gases

8. A. Boyle’s Law
The pressure and volume of a gas are inversely related
at constant mass & temp P V
PV = k

9. B. Charles’ Law
The volume and absolute temperature (K) of a gas are directly related
at constant mass & pressure V T

10. C. Gay-Lussac’s Law
The pressure and absolute temperature (K) of a gas are directly related
at constant mass & volume P T

11. PV T V T P T PV = k P1V1 T1 = P2V2 T2 P1V1T2 = P2V2T1
D. Combined Gas Law PV T V T P T PV
= k
P1V1 T1 =
P2V2 T2
P1V1T2 = P2V2T1

12. E. Gas Law Problems CHARLES’ LAW T V GIVEN: V1 = 473 cm3
A gas occupies 473 cm3 at 36°C. Find its volume at 94°C.
CHARLES’ LAW
GIVEN:
V1 = 473 cm3
T1 = 36°C = 309K
V2 = ?
T2 = 94°C = 367K T V
WORK:
P1V1T2 = P2V2T1
(473 cm3)(367 K)=V2(309 K)
V2 = 562 cm3

13. E. Gas Law Problems BOYLE’S LAW P V GIVEN: V1 = 100. mL
A gas occupies 100. mL at 150. kPa. Find its volume at 200. kPa.
BOYLE’S LAW
GIVEN:
V1 = 100. mL
P1 = 150. kPa
V2 = ?
P2 = 200. kPa P V
WORK:
P1V1T2 = P2V2T1
(150.kPa)(100.mL)=(200.kPa)V2
V2 = 75.0 mL

14. E. Gas Law Problems COMBINED GAS LAW P T V V1 = 7.84 cm3
A gas occupies 7.84 cm3 at 71.8 kPa & 25°C. Find its volume at STP.
COMBINED GAS LAW
GIVEN:
V1 = 7.84 cm3
P1 = 71.8 kPa
T1 = 25°C = 298 K
V2 = ?
P2 = kPa
T2 = 273 K
P T V
WORK:
P1V1T2 = P2V2T1
(71.8 kPa)(7.84 cm3)(273 K)
=( kPa) V2 (298 K)
V2 = 5.09 cm3

15. E. Gas Law Problems GAY-LUSSAC’S LAW P T GIVEN: P1 = 765 torr
A gas’ pressure is 765 torr at 23°C. At what temperature will the pressure be 560. torr?
GAY-LUSSAC’S LAW
GIVEN:
P1 = 765 torr
T1 = 23°C = 296K
P2 = 560. torr
T2 = ? P T
WORK:
P1V1T2 = P2V2T1
(765 torr)T2 = (560. torr)(309K)
T2 = 226 K = -47°C

16. UNIVERSAL GAS CONSTANT
B. Ideal Gas Law PV nT PV T
V n
= k
= R
UNIVERSAL GAS CONSTANT
R= Latm/molK
R=8.315 dm3kPa/molK

17. UNIVERSAL GAS CONSTANT
B. Ideal Gas Law
PV=nRT
UNIVERSAL GAS CONSTANT
R= Latm/molK
R=8.315 dm3kPa/molK

18. B. Ideal Gas Law IDEAL GAS LAW V = ? n = 85 g T = 25°C = 298 K
Find the volume of 85 g of O2 at 25°C and kPa.
IDEAL GAS LAW
GIVEN:
V = ?
n = 85 g
T = 25°C = 298 K
P = kPa
R = dm3kPa/molK
WORK:
85 g 1 mol = 2.7 mol
32.00 g
= 2.7 mol
PV = nRT
(104.5)V=(2.7) (8.315) (298)
kPa mol dm3kPa/molK K
V = 64 dm3

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B. Ideal Gas Law
Calculate the pressure in atmospheres of mol of He at 16°C & occupying L.
IDEAL GAS LAW
GIVEN:
P = ? atm
n = mol
T = 16°C = 289 K
V = 3.25 L
R = Latm/molK
WORK:
PV = nRT
P(3.25)=(0.412)(0.0821)(289)
L mol Latm/molK K
P = 3.01 atm
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